我从来都不记得我是怎么做到的，因为它很少出现在我身上。但是在C或c++中，从标准输入中读取字符而不等待换行符(按enter)的最佳方法是什么?
理想情况下，它也不会将输入字符回显到屏幕上。我只是想在不影响控制台屏幕的情况下捕捉击键。
当前回答
下面是一个不向系统提供外壳的版本(在macOS 10.14上编写和测试)
#include <unistd.h>
#include <termios.h>
#include <stdio.h>
#include <string.h>
char* getStr( char* buffer , int maxRead ) {
int numRead = 0;
char ch;
struct termios old = {0};
struct termios new = {0};
if( tcgetattr( 0 , &old ) < 0 ) perror( "tcgetattr() old settings" );
if( tcgetattr( 0 , &new ) < 0 ) perror( "tcgetaart() new settings" );
cfmakeraw( &new );
if( tcsetattr( 0 , TCSADRAIN , &new ) < 0 ) perror( "tcssetattr makeraw new" );
for( int i = 0 ; i < maxRead ; i++) {
ch = getchar();
switch( ch ) {
case EOF:
case '\n':
case '\r':
goto exit_getStr;
break;
default:
printf( "%1c" , ch );
buffer[ numRead++ ] = ch;
if( numRead >= maxRead ) {
goto exit_getStr;
}
break;
}
}
exit_getStr:
if( tcsetattr( 0 , TCSADRAIN , &old) < 0) perror ("tcsetattr reset to old" );
printf( "\n" );
return buffer;
}
int main( void )
{
const int maxChars = 20;
char stringBuffer[ maxChars+1 ];
memset( stringBuffer , 0 , maxChars+1 ); // initialize to 0
printf( "enter a string: ");
getStr( stringBuffer , maxChars );
printf( "you entered: [%s]\n" , stringBuffer );
}
其他回答
ssinfod对Linux的回答的变体，对我的口味来说稍微干净一些，为wcout和wchar_t实现，并在没有错误的情况下擦除无效字符。
#include <functional>
//For Linux kbhit(). For Windows, use conio.h.
#ifdef __unix__
#include <sys/ioctl.h> //For FIONREAD.
#include <termios.h>
//Call this at program start to setup for kbhit.
void initTerminalInput()
{
//Disable internal buffering.
std::wcout << std::unitbuf;
//Turn off line buffering.
struct termios term;
tcgetattr(0, &term);
term.c_lflag &= ~ICANON;
tcsetattr(0, TCSANOW, &term);
setbuf(stdin, NULL);
}
//Returns 0 if there's no input character to read.
int kbhit()
{
static int nbbytes;
ioctl(0, FIONREAD, &nbbytes);
return nbbytes;
}
#endif
//Waits for and retrieves a single validated character, calling a validation function on each character entered and
//erasing any that are invalid (when the validation function returns false).
static wchar_t getWChar(std::function<bool(wchar_t)> validationFunction)
{
static wchar_t inputWChar;
do
{
//Wait until there's an input character.
while (!kbhit())
{
}
inputWChar = getwchar();
//Validate the input character.
if (validationFunction(inputWChar))
{
//Valid.
break;
}
else
{
//Erase the invalid character.
std::wcout << L"\b \b";
}
} while (true);
return inputWChar;
}
在下面的例子中，我想让用户输入1、2或3。输入的任何其他字符都不会显示，它将等待，直到按下其中一个有效字符:
int main()
{
#ifdef __unix__
initTerminalInput();
#endif
getWChar([] (wchar_t inputWChar)
{
return (inputWChar >= L'1' && inputWChar <= L'3');
});
return 0;
}
假设是Windows，看一下ReadConsoleInput函数。
我也遇到过同样的问题。这里是一个小的解决方案为windows控制台使用cygwing++与if(GetKeyState(keycode) & bitANDcompare){};
#include <windows.h>
#include <fstream>
#include <iostream>
using namespace std;
void clear() {
COORD topLeft = { 0, 0 };
HANDLE console = GetStdHandle(STD_OUTPUT_HANDLE);
CONSOLE_SCREEN_BUFFER_INFO screen;
DWORD written;
GetConsoleScreenBufferInfo(console, &screen);
FillConsoleOutputCharacterA(
console, ' ', screen.dwSize.X * screen.dwSize.Y, topLeft, &written
);
FillConsoleOutputAttribute(
console, FOREGROUND_GREEN | FOREGROUND_RED | FOREGROUND_BLUE,
screen.dwSize.X * screen.dwSize.Y, topLeft, &written
);
SetConsoleCursorPosition(console, topLeft);
}
class Keyclick{
private:
int key;
char id;
public:
bool keydown = false;
Keyclick(int key1, char id1){
key=key1;
id=id1;
};
void watch(){
if(keydown==false){
if(GetKeyState(key) & 0x8000 ){
cout << id;
cout << " pressed.\r\n";
keydown = true;
}
}
if(keydown == true){
if(!(GetKeyState(key) & 0x8000)) {
cout << "released!!!!!!!!!!\r\n";
keydown = false;
clear();
}
}
};
};
int main()
{
bool primaryloop =true;
Keyclick keysp(VK_SPACE,'S');
Keyclick keyw(0x57,'w');
Keyclick keya(0x41,'a');
Keyclick keys(0x53,'s');
Keyclick keyd(0x44,'d');
Keyclick keyesc(VK_ESCAPE,'E');
while(primaryloop){
keysp.watch();
keyw.watch();
keya.watch();
keys.watch();
keyd.watch();
keyesc.watch();
if(keyesc.keydown){
primaryloop=false;
};
}
return 0;
}
https://github.com/wark77/windows_console_keypoller/blob/main/getkeystate_SOLUTION01.cpp
下面是一个不向系统提供外壳的版本(在macOS 10.14上编写和测试)
#include <unistd.h>
#include <termios.h>
#include <stdio.h>
#include <string.h>
char* getStr( char* buffer , int maxRead ) {
int numRead = 0;
char ch;
struct termios old = {0};
struct termios new = {0};
if( tcgetattr( 0 , &old ) < 0 ) perror( "tcgetattr() old settings" );
if( tcgetattr( 0 , &new ) < 0 ) perror( "tcgetaart() new settings" );
cfmakeraw( &new );
if( tcsetattr( 0 , TCSADRAIN , &new ) < 0 ) perror( "tcssetattr makeraw new" );
for( int i = 0 ; i < maxRead ; i++) {
ch = getchar();
switch( ch ) {
case EOF:
case '\n':
case '\r':
goto exit_getStr;
break;
default:
printf( "%1c" , ch );
buffer[ numRead++ ] = ch;
if( numRead >= maxRead ) {
goto exit_getStr;
}
break;
}
}
exit_getStr:
if( tcsetattr( 0 , TCSADRAIN , &old) < 0) perror ("tcsetattr reset to old" );
printf( "\n" );
return buffer;
}
int main( void )
{
const int maxChars = 20;
char stringBuffer[ maxChars+1 ];
memset( stringBuffer , 0 , maxChars+1 ); // initialize to 0
printf( "enter a string: ");
getStr( stringBuffer , maxChars );
printf( "you entered: [%s]\n" , stringBuffer );
}
这在纯c++中以可移植的方式是不可能的，因为它太依赖于可能与stdin连接的终端(它们通常是行缓冲的)。不过，你可以使用一个库来实现:
conio available with Windows compilers. Use the _getch() function to give you a character without waiting for the Enter key. I'm not a frequent Windows developer, but I've seen my classmates just include <conio.h> and use it. See conio.h at Wikipedia. It lists getch(), which is declared deprecated in Visual C++. curses available for Linux. Compatible curses implementations are available for Windows too. It has also a getch() function. (try man getch to view its manpage). See Curses at Wikipedia.
如果你的目标是跨平台兼容性，我建议你使用curses。也就是说，我相信有一些函数可以用来关闭行缓冲(我相信这被称为“原始模式”，而不是“熟模式”-看看man stty)。如果我没记错的话，诅咒可以方便地帮你解决这个问题。
