下面是一个不向系统提供外壳的版本(在macOS 10.14上编写和测试)

#include <unistd.h>
#include <termios.h>
#include <stdio.h>
#include <string.h>

char* getStr( char* buffer , int maxRead ) {
  int  numRead  = 0;
  char ch;

  struct termios old = {0};
  struct termios new = {0};
  if( tcgetattr( 0 , &old ) < 0 )        perror( "tcgetattr() old settings" );
  if( tcgetattr( 0 , &new ) < 0 )        perror( "tcgetaart() new settings" );
  cfmakeraw( &new );
  if( tcsetattr( 0 , TCSADRAIN , &new ) < 0 ) perror( "tcssetattr makeraw new" );

  for( int i = 0 ; i < maxRead ; i++)  {
    ch = getchar();
    switch( ch )  {
      case EOF: 
      case '\n':
      case '\r':
        goto exit_getStr;
        break;

      default:
        printf( "%1c" , ch );
        buffer[ numRead++ ] = ch;
        if( numRead >= maxRead )  {
          goto exit_getStr;
        }
        break;
    }
  }

exit_getStr:
  if( tcsetattr( 0 , TCSADRAIN , &old) < 0)   perror ("tcsetattr reset to old" );
  printf( "\n" );   
  return buffer;
}


int main( void ) 
{
  const int maxChars = 20;
  char      stringBuffer[ maxChars+1 ];
  memset(   stringBuffer , 0 , maxChars+1 ); // initialize to 0

  printf( "enter a string: ");
  getStr( stringBuffer , maxChars );
  printf( "you entered: [%s]\n" , stringBuffer );
}

Ncurses提供了一个很好的方法来做到这一点! 这也是我的第一篇文章(我记得)，所以欢迎任何评论。我会欣赏有用的，但都是受欢迎的!

编译： g++ -std=c++11 -pthread -lncurses .cpp -o

#include <iostream>
#include <ncurses.h>
#include <future>

char get_keyboard_input();

int main(int argc, char *argv[])
{
    initscr();
    raw();
    noecho();
    keypad(stdscr,true);

    auto f = std::async(std::launch::async, get_keyboard_input);
    while (f.wait_for(std::chrono::milliseconds(20)) != std::future_status::ready)
    {
        // do some work
    }

    endwin();
    std::cout << "returned: " << f.get() << std::endl;
    return 0;
}

char get_keyboard_input()
{
    char input = '0';
    while(input != 'q')
    {
        input = getch();
    }
    return input;
}

我总是想要一个循环读取我的输入而不按返回键。 这对我很管用。

#include<stdio.h>
 main()
 {
   char ch;
    system("stty raw");//seting the terminal in raw mode
    while(1)
     {
     ch=getchar();
      if(ch=='~'){          //terminate or come out of raw mode on "~" pressed
      system("stty cooked");
     //while(1);//you may still run the code 
     exit(0); //or terminate
     }
       printf("you pressed %c\n ",ch);  //write rest code here
      }

    }

在WINDOWS上我这样做:

#include <Windows.h>
int main()
{
    system("PAUSE>NUL");
    if (GetKeyState(0x41/*(the 'A' key, choosen e.g.)*/) & (0xff80/*That stands for "Default state / Key Down"*/)) {
        //whatever I want to do after 'A' is pressed
    }
}

这里可以找到一个键的列表，每个键都有自己的十六进制值: https://learn.microsoft.com/en-us/windows/win32/inputdev/virtual-key-codes

ssinfod对Linux的回答的变体，对我的口味来说稍微干净一些，为wcout和wchar_t实现，并在没有错误的情况下擦除无效字符。

#include <functional>

//For Linux kbhit(). For Windows, use conio.h.
#ifdef __unix__
  #include <sys/ioctl.h> //For FIONREAD.
  #include <termios.h>

  //Call this at program start to setup for kbhit.
  void initTerminalInput()
  {
    //Disable internal buffering.
    std::wcout << std::unitbuf;

    //Turn off line buffering.
    struct termios term;
    tcgetattr(0, &term);
    term.c_lflag &= ~ICANON;
    tcsetattr(0, TCSANOW, &term);
    setbuf(stdin, NULL);
  }

  //Returns 0 if there's no input character to read.
  int kbhit()
  {
    static int nbbytes;
    ioctl(0, FIONREAD, &nbbytes);
    return nbbytes;
  }
#endif

//Waits for and retrieves a single validated character, calling a validation function on each character entered and
//erasing any that are invalid (when the validation function returns false).
static wchar_t getWChar(std::function<bool(wchar_t)> validationFunction)
{
  static wchar_t inputWChar;
  do
  {
    //Wait until there's an input character.
    while (!kbhit())
    {
    }
    inputWChar = getwchar();
    //Validate the input character.
    if (validationFunction(inputWChar))
    {
      //Valid.
      break;
    }
    else
    {
      //Erase the invalid character.
      std::wcout << L"\b \b";
    }
  } while (true);
  return inputWChar;
}

在下面的例子中，我想让用户输入1、2或3。输入的任何其他字符都不会显示，它将等待，直到按下其中一个有效字符:

int main()
{
  #ifdef __unix__
    initTerminalInput();
  #endif

  getWChar([] (wchar_t inputWChar)
  {
    return (inputWChar >= L'1' && inputWChar <= L'3');
  });

  return 0;
}

如果你在windows上，你可以使用PeekConsoleInput来检测是否有任何输入，

HANDLE handle = GetStdHandle(STD_INPUT_HANDLE);
DWORD events;
INPUT_RECORD buffer;
PeekConsoleInput( handle, &buffer, 1, &events );

然后使用ReadConsoleInput“消费”输入字符..

PeekConsoleInput(handle, &buffer, 1, &events);
if(events > 0)
{
    ReadConsoleInput(handle, &buffer, 1, &events);  
    return buffer.Event.KeyEvent.wVirtualKeyCode;
}
else return 0

老实说，这是从一些旧的代码，我有，所以你必须拨弄它一点。

最酷的是它读取输入时没有任何提示，所以字符根本不会显示出来。