我有一个网络调用要执行。但在此之前,我需要检查设备是否有互联网连接。
这是我目前为止所做的:
var connectivityResult = new Connectivity().checkConnectivity();// User defined class
if (connectivityResult == ConnectivityResult.mobile ||
connectivityResult == ConnectivityResult.wifi) {*/
this.getData();
} else {
neverSatisfied();
}
上述方法行不通。
对我来说,我只是在Firebase中创建一个数据,并使用未来构建器来等待数据。在这里,就像这样,你可以检查连接是否太慢,所以数据将被加载:
FutureBuilder(
future: _getImage(context),
builder: (context, snapshot) {
switch (snapshot.connectionState) {
case ConnectionState.none:
return Text('Press button to start.');
case ConnectionState.active:
case ConnectionState.waiting:
return Container(
height:
MediaQuery.of(context).size.height / 1.25,
width:
MediaQuery.of(context).size.width / 1.25,
child: Loading());
case ConnectionState.done:
if (snapshot.hasData) {
return snapshot.data;
} else {
return FlatButton(
onPressed: () {
Navigator.push(
context,
MaterialPageRoute(
builder: (context) =>
ProfilePage()));
},
child: Icon(
Icons.add_a_photo,
size: 50,
),
);
}
// You can reach your snapshot.data['url'] in here
}
return null;
},
),
这是我的解决方案,它检查互联网连接以及数据连接,我希望你喜欢它。
First of all add dependencies in your pubsec.yaml
dependencies:
data_connection_checker:
And Here Is The main.dart Of My Solution
import 'dart:async';
import 'package:data_connection_checker/data_connection_checker.dart';
import 'package:flutter/material.dart';
void main() => runApp(MyApp());
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return MaterialApp(
title: "Data Connection Checker",
home: HomePage(),
);
}
}
class HomePage extends StatefulWidget {
@override
_HomePageState createState() => _HomePageState();
}
class _HomePageState extends State<HomePage> {
StreamSubscription<DataConnectionStatus> listener;
var Internetstatus = "Unknown";
@override
void initState() {
// TODO: implement initState
super.initState();
// _updateConnectionStatus();
CheckInternet();
}
@override
void dispose() {
// TODO: implement dispose
listener.cancel();
super.dispose();
}
CheckInternet() async {
// Simple check to see if we have internet
print("The statement 'this machine is connected to the Internet' is: ");
print(await DataConnectionChecker().hasConnection);
// returns a bool
// We can also get an enum instead of a bool
print("Current status: ${await DataConnectionChecker().connectionStatus}");
// prints either DataConnectionStatus.connected
// or DataConnectionStatus.disconnected
// This returns the last results from the last call
// to either hasConnection or connectionStatus
print("Last results: ${DataConnectionChecker().lastTryResults}");
// actively listen for status updates
listener = DataConnectionChecker().onStatusChange.listen((status) {
switch (status) {
case DataConnectionStatus.connected:
Internetstatus="Connectd TO THe Internet";
print('Data connection is available.');
setState(() {
});
break;
case DataConnectionStatus.disconnected:
Internetstatus="No Data Connection";
print('You are disconnected from the internet.');
setState(() {
});
break;
}
});
// close listener after 30 seconds, so the program doesn't run forever
// await Future.delayed(Duration(seconds: 30));
// await listener.cancel();
return await await DataConnectionChecker().connectionStatus;
}
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text("Data Connection Checker"),
),
body: Container(
child: Center(
child: Text("$Internetstatus"),
),
),
);
}
}
在@dennmatt的回答之后,我注意到InternetAddress。查找可能会返回成功的结果,即使互联网连接断开-我测试它从我的模拟器连接到我的家庭WiFi,然后断开我的路由器的电缆。我认为原因是路由器缓存了域查找结果,所以它不必在每个查找请求时查询DNS服务器。
不管怎样,如果你像我一样使用Firestore,你可以用一个空事务替换try-SocketException-catch块并捕获TimeoutExceptions:
try {
await Firestore.instance.runTransaction((Transaction tx) {}).timeout(Duration(seconds: 5));
hasConnection = true;
} on PlatformException catch(_) { // May be thrown on Airplane mode
hasConnection = false;
} on TimeoutException catch(_) {
hasConnection = false;
}
另外,请注意,previousConnection是在async internet -check之前设置的,因此理论上,如果checkConnection()在短时间内被调用多次,那么在一行中可能有多个hasConnection=true或多个hasConnection=false。
我不确定@dennmatt是否故意这样做,但在我们的用例中没有副作用(setState只被调用两次,具有相同的值)。