挖掘一根旧柱子……但我最近使用了这个方法，并测试了以下两种替代方法:

test_declare () {
    a () { echo 'a' ;}

    declare -f a > /dev/null
}

test_type () {
    a () { echo 'a' ;}
    type a | grep -q 'is a function'
}

echo 'declare'
time for i in $(seq 1 1000); do test_declare; done
echo 'type'
time for i in $(seq 1 100); do test_type; done

这产生了:

real    0m0.064s
user    0m0.040s
sys     0m0.020s
type

real    0m2.769s
user    0m1.620s
sys     0m1.130s

声明要快得多!

这告诉你它是否存在，但不是说它是一个函数

fn_exists()
{
  type $1 >/dev/null 2>&1;
}

借鉴其他解决方案和评论，我得出了以下结论:

fn_exists() {
  # appended double quote is an ugly trick to make sure we do get a string -- if $1 is not a known command, type does not output anything
  [ `type -t $1`"" == 'function' ]
}

用作……

if ! fn_exists $FN; then
    echo "Hey, $FN does not exist ! Duh."
    exit 2
fi

它检查给定的参数是否是一个函数，并避免重定向和其他grepping。

可以在没有任何外部命令的情况下使用'type'，但你必须调用它两次，所以它的速度仍然是'declare'版本的两倍:

test_function () {
        ! type -f $1 >/dev/null 2>&1 && type -t $1 >/dev/null 2>&1
}

加上这不能在POSIX sh中工作，所以它完全没有价值，除了作为琐事!

测试不同的解决方案:

#!/bin/bash

test_declare () {
    declare -f f > /dev/null
}

test_declare2 () {
    declare -F f > /dev/null
}

test_type () {
    type -t f | grep -q 'function'
}

test_type2 () {
     [[ $(type -t f) = function ]]
}

funcs=(test_declare test_declare2 test_type test_type2)

test () {
    for i in $(seq 1 1000); do $1; done
}

f () {
echo 'This is a test function.'
echo 'This has more than one command.'
return 0
}
post='(f is function)'

for j in 1 2 3; do

    for func in ${funcs[@]}; do
        echo $func $post
        time test $func
        echo exit code $?; echo
    done

    case $j in
    1)  unset -f f
        post='(f unset)'
        ;;
    2)  f='string'
        post='(f is string)'
        ;;
    esac
done

例如:输出

test_declare (f is function) real 0m0,055s user 0m0,041s sys 0m0,004s exit code 0 test_declare2 (f is function) real 0m0,042s user 0m0,022s sys 0m0,017s exit code 0 test_type (f is function) real 0m2,200s user 0m1,619s sys 0m1,008s exit code 0 test_type2 (f is function) real 0m0,746s user 0m0,534s sys 0m0,237s exit code 0 test_declare (f unset) real 0m0,040s user 0m0,029s sys 0m0,010s exit code 1 test_declare2 (f unset) real 0m0,038s user 0m0,038s sys 0m0,000s exit code 1 test_type (f unset) real 0m2,438s user 0m1,678s sys 0m1,045s exit code 1 test_type2 (f unset) real 0m0,805s user 0m0,541s sys 0m0,274s exit code 1 test_declare (f is string) real 0m0,043s user 0m0,034s sys 0m0,007s exit code 1 test_declare2 (f is string) real 0m0,039s user 0m0,035s sys 0m0,003s exit code 1 test_type (f is string) real 0m2,394s user 0m1,679s sys 0m1,035s exit code 1 test_type2 (f is string) real 0m0,851s user 0m0,554s sys 0m0,294s exit code 1

所以declare -F似乎是最好的解决方案。

你可以用四种方法检查它们

fn_exists() { type -t $1 >/dev/null && echo 'exists'; }
fn_exists() { declare -F $1 >/dev/null && echo 'exists'; }
fn_exists() { typeset -F $1 >/dev/null && echo 'exists'; }
fn_exists() { compgen -A function $1 >/dev/null && echo 'exists'; }