我有一个平面JS对象:
{a: 1, b: 2, c: 3, ..., z:26}
我想克隆对象除了一个元素:
{a: 1, c: 3, ..., z:26}
最简单的方法是什么(如果可能的话，更倾向于使用es6/7)?
当前回答
var clone = Object.assign({}, {a: 1, b: 2, c: 3});
delete clone.b;
或者如果你接受属性为未定义:
var clone = Object.assign({}, {a: 1, b: 2, c: 3}, {b: undefined});
其他回答
你也可以使用展开运算符
const source = { a: 1, b: 2, c: 3, z: 26 }
const copy = { ...source, ...{ b: undefined } } // { a: 1, c: 3, z: 26 }
也许是这样的:
var copy = Object.assign({}, {a: 1, b: 2, c: 3})
delete copy.c;
这样够好吗?或者说c不能被复制?
var clone = Object.assign({}, {a: 1, b: 2, c: 3});
delete clone.b;
或者如果你接受属性为未定义:
var clone = Object.assign({}, {a: 1, b: 2, c: 3}, {b: undefined});
您可以为它编写一个简单的helper函数。Lodash有一个同名的类似函数:省略
function omit(obj, omitKey) {
return Object.keys(obj).reduce((result, key) => {
if(key !== omitKey) {
result[key] = obj[key];
}
return result;
}, {});
}
omit({a: 1, b: 2, c: 3}, 'c') // {a: 1, b: 2}
另外，注意它比Object快。然后分配和删除:http://jsperf.com/omit-key
我以Redux减速机为例:
const clone = { ...state };
delete clone[action.id];
return clone;
换句话说:
const clone = { ...originalObject } // note: original object is not altered
delete clone[unwantedKey] // or use clone.unwantedKey or any other applicable syntax
return clone // the original object without the unwanted key
