我希望使用shell脚本调用长形式和短形式的命令行选项。

我知道可以使用getopts,但是像在Perl中一样,我不能用shell做同样的事情。

关于如何做到这一点的任何想法,这样我就可以使用如下选项:

./shell.sh --copyfile abc.pl /tmp/
./shell.sh -c abc.pl /tmp/

在上面,这两个命令对我的shell意味着同样的事情,但使用getopts,我还不能实现这些?


当前回答

我想要一个没有外部依赖关系、有严格bash支持(-u)的东西,而且我需要它能在较旧的bash版本上工作。这个函数处理各种类型的参数:

短bool (-h) 短选项(-i "image.jpg") 长boos(——救命) = options(——file="filename.ext") 空格选项(——file "filename.ext") 连接的bool (-hvm)

只需在脚本顶部插入以下内容:

# Check if a list of params contains a specific param
# usage: if _param_variant "h|?|help p|path f|file long-thing t|test-thing" "file" ; then ...
# the global variable $key is updated to the long notation (last entry in the pipe delineated list, if applicable)
_param_variant() {
  for param in $1 ; do
    local variants=${param//\|/ }
    for variant in $variants ; do
      if [[ "$variant" = "$2" ]] ; then
        # Update the key to match the long version
        local arr=(${param//\|/ })
        let last=${#arr[@]}-1
        key="${arr[$last]}"
        return 0
      fi
    done
  done
  return 1
}

# Get input parameters in short or long notation, with no dependencies beyond bash
# usage:
#     # First, set your defaults
#     param_help=false
#     param_path="."
#     param_file=false
#     param_image=false
#     param_image_lossy=true
#     # Define allowed parameters
#     allowed_params="h|?|help p|path f|file i|image image-lossy"
#     # Get parameters from the arguments provided
#     _get_params $*
#
# Parameters will be converted into safe variable names like:
#     param_help,
#     param_path,
#     param_file,
#     param_image,
#     param_image_lossy
#
# Parameters without a value like "-h" or "--help" will be treated as
# boolean, and will be set as param_help=true
#
# Parameters can accept values in the various typical ways:
#     -i "path/goes/here"
#     --image "path/goes/here"
#     --image="path/goes/here"
#     --image=path/goes/here
# These would all result in effectively the same thing:
#     param_image="path/goes/here"
#
# Concatinated short parameters (boolean) are also supported
#     -vhm is the same as -v -h -m
_get_params(){

  local param_pair
  local key
  local value
  local shift_count

  while : ; do
    # Ensure we have a valid param. Allows this to work even in -u mode.
    if [[ $# == 0 || -z $1 ]] ; then
      break
    fi

    # Split the argument if it contains "="
    param_pair=(${1//=/ })
    # Remove preceeding dashes
    key="${param_pair[0]#--}"

    # Check for concatinated boolean short parameters.
    local nodash="${key#-}"
    local breakout=false
    if [[ "$nodash" != "$key" && ${#nodash} -gt 1 ]]; then
      # Extrapolate multiple boolean keys in single dash notation. ie. "-vmh" should translate to: "-v -m -h"
      local short_param_count=${#nodash}
      let new_arg_count=$#+$short_param_count-1
      local new_args=""
      # $str_pos is the current position in the short param string $nodash
      for (( str_pos=0; str_pos<new_arg_count; str_pos++ )); do
        # The first character becomes the current key
        if [ $str_pos -eq 0 ] ; then
          key="${nodash:$str_pos:1}"
          breakout=true
        fi
        # $arg_pos is the current position in the constructed arguments list
        let arg_pos=$str_pos+1
        if [ $arg_pos -gt $short_param_count ] ; then
          # handle other arguments
          let orignal_arg_number=$arg_pos-$short_param_count+1
          local new_arg="${!orignal_arg_number}"
        else
          # break out our one argument into new ones
          local new_arg="-${nodash:$str_pos:1}"
        fi
        new_args="$new_args \"$new_arg\""
      done
      # remove the preceding space and set the new arguments
      eval set -- "${new_args# }"
    fi
    if ! $breakout ; then
      key="$nodash"
    fi

    # By default we expect to shift one argument at a time
    shift_count=1
    if [ "${#param_pair[@]}" -gt "1" ] ; then
      # This is a param with equals notation
      value="${param_pair[1]}"
    else
      # This is either a boolean param and there is no value,
      # or the value is the next command line argument
      # Assume the value is a boolean true, unless the next argument is found to be a value.
      value=true
      if [[ $# -gt 1 && -n "$2" ]]; then
        local nodash="${2#-}"
        if [ "$nodash" = "$2" ]; then
          # The next argument has NO preceding dash so it is a value
          value="$2"
          shift_count=2
        fi
      fi
    fi

    # Check that the param being passed is one of the allowed params
    if _param_variant "$allowed_params" "$key" ; then
      # --key-name will now become param_key_name
      eval param_${key//-/_}="$value"
    else
      printf 'WARNING: Unknown option (ignored): %s\n' "$1" >&2
    fi
    shift $shift_count
  done
}

像这样使用它:

# Assign defaults for parameters
param_help=false
param_path=$(pwd)
param_file=false
param_image=true
param_image_lossy=true
param_image_lossy_quality=85

# Define the params we will allow
allowed_params="h|?|help p|path f|file i|image image-lossy image-lossy-quality"

# Get the params from arguments provided
_get_params $*

其他回答

我是这样解决的:

# A string with command options
options=$@

# An array with all the arguments
arguments=($options)

# Loop index
index=0

for argument in $options
  do
    # Incrementing index
    index=`expr $index + 1`

    # The conditions
    case $argument in
      -a) echo "key $argument value ${arguments[index]}" ;;
      -abc) echo "key $argument value ${arguments[index]}" ;;
    esac
  done

exit;

我是不是太笨了?Getopt和getopts太让人困惑了。

Getopts“可以用来”解析长选项,只要你不希望它们有参数……

以下是如何:

$ cat > longopt
while getopts 'e:-:' OPT; do
  case $OPT in
    e) echo echo: $OPTARG;;
    -) #long option
       case $OPTARG in
         long-option) echo long option;;
         *) echo long option: $OPTARG;;
       esac;;
  esac
done

$ bash longopt -e asd --long-option --long1 --long2 -e test
echo: asd
long option
long option: long1
long option: long2
echo: test

如果尝试使用OPTIND获取长选项的参数,getopts将把它作为第一个不可选的位置参数,并停止解析任何其他参数。 在这种情况下,您最好使用简单的case语句手动处理它。

这将“总是”工作:

$ cat >longopt2
while (($#)); do
    OPT=$1
    shift
    case $OPT in
        --*) case ${OPT:2} in
            long1) echo long1 option;;
            complex) echo comples with argument $1; shift;;
        esac;;

        -*) case ${OPT:1} in
            a) echo short option a;;
            b) echo short option b with parameter $1; shift;;
        esac;;
    esac
done


$ bash longopt2 --complex abc -a --long -b test
comples with argument abc
short option a
short option b with parameter test

尽管它不像getopts那么灵活,而且你必须在用例实例中自己做很多错误检查代码……

但这是一种选择。

公认的答案很好地指出了bash内置getopts的所有缺点。答案以:

因此,虽然可以编写更多的代码来解决长选项支持不足的问题,但工作量要大得多,并且在一定程度上违背了使用getopt解析器来简化代码的目的。

尽管我原则上同意这种说法,但我觉得我们在各种脚本中实现这个特性的次数证明,我们应该花一些精力来创建一个“标准化”的、经过良好测试的解决方案。

因此,我通过在纯bash中实现getopts_long“升级”了内置在getopts中的bash,没有外部依赖。该函数的使用与内置的getopts 100%兼容。

通过在脚本中包含getopts_long(在GitHub上托管),可以简单地实现原始问题的答案:

source "${PATH_TO}/getopts_long.bash"

while getopts_long ':c: copyfile:' OPTKEY; do
    case ${OPTKEY} in
        'c'|'copyfile')
            echo 'file supplied -- ${OPTARG}'
            ;;
        '?')
            echo "INVALID OPTION -- ${OPTARG}" >&2
            exit 1
            ;;
        ':')
            echo "MISSING ARGUMENT for option -- ${OPTARG}" >&2
            exit 1
            ;;
        *)
            echo "Misconfigured OPTSPEC or uncaught option -- ${OPTKEY}" >&2
            exit 1
            ;;
    esac
done

shift $(( OPTIND - 1 ))
[[ "${1}" == "--" ]] && shift

下面你可以找到bash中复杂选项解析的几种不同方法: http://mywiki.wooledge.org/ComplexOptionParsing

我确实创建了下面的一个,而且我认为它很好,因为它的代码最少 多头和空头选择都有效。使用这种方法,长选项也可以有多个参数。

#!/bin/bash
# Uses bash extensions.  Not portable as written.

declare -A longoptspec
longoptspec=( [loglevel]=1 ) #use associative array to declare how many arguments a long option expects, in this case we declare that loglevel expects/has one argument, long options that aren't listed i n this way will have zero arguments by default
optspec=":h-:"
while getopts "$optspec" opt; do
while true; do
    case "${opt}" in
        -) #OPTARG is name-of-long-option or name-of-long-option=value
            if [[ "${OPTARG}" =~ .*=.* ]] #with this --key=value format only one argument is possible
            then
                opt=${OPTARG/=*/}
                OPTARG=${OPTARG#*=}
                ((OPTIND--))    
            else #with this --key value1 value2 format multiple arguments are possible
                opt="$OPTARG"
                OPTARG=(${@:OPTIND:$((longoptspec[$opt]))})
            fi
            ((OPTIND+=longoptspec[$opt]))
            continue #now that opt/OPTARG are set we can process them as if getopts would've given us long options
            ;;
        loglevel)
          loglevel=$OPTARG
            ;;
        h|help)
            echo "usage: $0 [--loglevel[=]<value>]" >&2
            exit 2
            ;;
    esac
break; done
done

# End of file

这需要一些时间,但我想要全部:

短选项 长选项 不管有没有论点 非选项参数(没有“-”或“——”的参数) 顺序不重要(script.sh /file -V或script.sh -V /file) 抓住错误用法 在不同的脚本中使用它作为模块,而不需要更改多行代码

最后,我提出了下面的解决方案,它使用getopt来捕获错误并将非选项移动到列表的末尾,然后再使用getopts来解析短选项和长选项。

所有的选项都会自动解析,将它们的长选项名作为变量名(请看例子):

# create string of short options
opt_short=$(printf "%s" "${!options[@]}")

# create string of long options
opt_long="$(printf ",%s" "${options[@]}")"

# catch wrong options and move non-options to the end of the string
args=$(getopt -l "$opt_long" "$opt_short" "$@" 2> >(sed -e 's/^/stderr/g')) || echo -n "Error: " && echo "$args" | grep -oP "(?<=^stderr).*" && exit 1

# create new array of options
mapfile -t args < <(xargs -n1 <<< "$(echo "$args" | sed -E "s/(--[^ ]+) '/\1='/g")" )

# overwrite $@ (options)
set -- "${args[@]}"

# parse options ([h]=help sets the variable "$opt_help" and [V]="" sets the variable "$opt_V")
while getopts "$opt_short-:" opt; do

  echo "$opt:$OPTARG"

  # long option
  if [[ "$opt" == "-" ]]; then

    # extract long option name
    opt="${OPTARG%%=*}"

    # extract long option argument (may be empty)
    OPTARG="${OPTARG#"$opt"}"

    # remove "=" from long option argument
    OPTARG="${OPTARG#=}"

    # set variable name
    opt=opt_$opt

  # short option without argument uses long option name as variable name
  elif [[ "${options[$opt]+x}" ]] && [[ "${options[$opt]}" ]]; then
    opt=opt_${options[$opt]} 

  # short option with argument uses long option name as variable name
  elif [[ "${options[$opt:]+x}" ]] && [[ "${options[$opt:]}" ]]; then
    opt=opt_${options[$opt:]} 

  # short option without long option name uses short option name as variable name
  else
    opt=opt_$opt
  fi

  # remove double colon
  opt="${opt%:}" 

  # options without arguments are set to 1
  [[ ! $OPTARG ]] && OPTARG=1 

  # replace hyphen against underscore
  opt="${opt//-/_}"

  # set variable variables (replaces hyphen against underscore)
  printf -v "$opt" '%s' "$OPTARG" 

done

现在,我只需要定义所需的选项名称和源代码脚本:

# import options module
declare -A options=( [h]=help [f:]=file: [V]=verbose [0]=long_only: [s]="" )
source "/usr/local/bin/inc/options.sh";

# display help text
if [[ $opt_help ]]; then
  echo "help text"
  exit
fi

# output
echo "opt_help:$opt_help"
echo "opt_file:$opt_file"
echo "opt_verbose:$opt_verbose"
echo "opt_long_only:$opt_long_only"
echo "opt_short_only:$opt_s"
echo "opt_path:$1"
echo "opt_mail:$2"

在调用脚本时,可以完全随机地传递所有选项和非选项:

#             $opt_file     $1        $2       $opt_V  $opt_long_only $opt_s
# /demo.sh --file=file.txt /dir info@example.com -V --long_only=yes -s
opt_help:1
opt_file:file.txt
opt_verbose:1
opt_long_only:yes
opt_short_only:1
opt_path=/dir
opt_mail:info@example.com

笔记

在选项数组中,在选项名称后添加:以启用参数。 如果没有给出较长的选项名,则变量名将是$opt_X,其中X是较短的选项名。 如果您希望使用较长的选项名而不定义较短的选项名,则将数组索引设置为一个数字,如上面示例中使用[0]=long_only所做的那样。当然,每个数组下标必须是唯一的。

使用的技术

不使用临时文件捕获stderr 将字符串转换为数组 使用:来解析getopt参数 使用getopts解析长选项名