我希望使用shell脚本调用长形式和短形式的命令行选项。
我知道可以使用getopts,但是像在Perl中一样,我不能用shell做同样的事情。
关于如何做到这一点的任何想法,这样我就可以使用如下选项:
./shell.sh --copyfile abc.pl /tmp/
./shell.sh -c abc.pl /tmp/
在上面,这两个命令对我的shell意味着同样的事情,但使用getopts,我还不能实现这些?
我希望使用shell脚本调用长形式和短形式的命令行选项。
我知道可以使用getopts,但是像在Perl中一样,我不能用shell做同样的事情。
关于如何做到这一点的任何想法,这样我就可以使用如下选项:
./shell.sh --copyfile abc.pl /tmp/
./shell.sh -c abc.pl /tmp/
在上面,这两个命令对我的shell意味着同样的事情,但使用getopts,我还不能实现这些?
当前回答
例如,如果所有长选项都有唯一且匹配的首字符作为短选项
./slamm --chaos 23 --plenty test -quiet
和
./slamm -c 23 -p test -q
你可以在getopts重写$args之前使用它:
# change long options to short options
for arg; do
[[ "${arg:0:1}" == "-" ]] && delim="" || delim="\""
if [ "${arg:0:2}" == "--" ];
then args="${args} -${arg:2:1}"
else args="${args} ${delim}${arg}${delim}"
fi
done
# reset the incoming args
eval set -- $args
# proceed as usual
while getopts ":b:la:h" OPTION; do
.....
谢谢mtvee的灵感;-)
其他回答
如果你不想要getopt依赖,你可以这样做:
while test $# -gt 0
do
case $1 in
# Normal option processing
-h | --help)
# usage and help
;;
-v | --version)
# version info
;;
# ...
# Special cases
--)
break
;;
--*)
# error unknown (long) option $1
;;
-?)
# error unknown (short) option $1
;;
# FUN STUFF HERE:
# Split apart combined short options
-*)
split=$1
shift
set -- $(echo "$split" | cut -c 2- | sed 's/./-& /g') "$@"
continue
;;
# Done with options
*)
break
;;
esac
# for testing purposes:
echo "$1"
shift
done
当然,这样你就不能使用长样式选项。如果你想添加缩短的版本(例如——verbos而不是——verbose),那么你需要手动添加这些。
但是如果您希望获得getopts功能和长选项,这是一种简单的方法。
我也把这个片段作为一个主旨。
下面是一个实际使用长选项的getopt的示例:
aflag=no
bflag=no
cargument=none
# options may be followed by one colon to indicate they have a required argument
if ! options=$(getopt -o abc: -l along,blong,clong: -- "$@")
then
# something went wrong, getopt will put out an error message for us
exit 1
fi
set -- $options
while [ $# -gt 0 ]
do
case $1 in
-a|--along) aflag="yes" ;;
-b|--blong) bflag="yes" ;;
# for options with required arguments, an additional shift is required
-c|--clong) cargument="$2" ; shift;;
(--) shift; break;;
(-*) echo "$0: error - unrecognized option $1" 1>&2; exit 1;;
(*) break;;
esac
shift
done
我还没有足够的代表来评论或投票他的解决方案,但他的答案对我来说非常有效。我遇到的唯一问题是参数以单引号结尾(所以我把它们去掉了)。
我还添加了一些示例用法和帮助文本。我将在这里附上我略微扩展的版本:
#!/bin/bash
# getopt example
# from: https://stackoverflow.com/questions/402377/using-getopts-in-bash-shell-script-to-get-long-and-short-command-line-options
HELP_TEXT=\
" USAGE:\n
Accepts - and -- flags, can specify options that require a value, and can be in any order. A double-hyphen (--) will stop processing options.\n\n
Accepts the following forms:\n\n
getopt-example.sh -a -b -c value-for-c some-arg\n
getopt-example.sh -c value-for-c -a -b some-arg\n
getopt-example.sh -abc some-arg\n
getopt-example.sh --along --blong --clong value-for-c -a -b -c some-arg\n
getopt-example.sh some-arg --clong value-for-c\n
getopt-example.sh
"
aflag=false
bflag=false
cargument=""
# options may be followed by one colon to indicate they have a required argument
if ! options=$(getopt -o abc:h\? -l along,blong,help,clong: -- "$@")
then
# something went wrong, getopt will put out an error message for us
exit 1
fi
set -- $options
while [ $# -gt 0 ]
do
case $1 in
-a|--along) aflag=true ;;
-b|--blong) bflag=true ;;
# for options with required arguments, an additional shift is required
-c|--clong) cargument="$2" ; shift;;
-h|--help|-\?) echo -e $HELP_TEXT; exit;;
(--) shift; break;;
(-*) echo "$0: error - unrecognized option $1" 1>&2; exit 1;;
(*) break;;
esac
shift
done
# to remove the single quotes around arguments, pipe the output into:
# | sed -e "s/^'\\|'$//g" (just leading/trailing) or | sed -e "s/'//g" (all)
echo aflag=${aflag}
echo bflag=${bflag}
echo cargument=${cargument}
while [ $# -gt 0 ]
do
echo arg=$1
shift
if [[ $aflag == true ]]; then
echo a is true
fi
done
一个简单的DIY,只获得长名称的参数:
Use:
$ ./test-args.sh --a1 a1 --a2 "a 2" --a3 --a4= --a5=a5 --a6="a 6"
a1 = "a1"
a2 = "a 2"
a3 = "TRUE"
a4 = ""
a5 = "a5"
a6 = "a 6"
a7 = ""
脚本:
#!/bin/bash
function main() {
ARGS=`getArgs "$@"`
a1=`echo "$ARGS" | getNamedArg a1`
a2=`echo "$ARGS" | getNamedArg a2`
a3=`echo "$ARGS" | getNamedArg a3`
a4=`echo "$ARGS" | getNamedArg a4`
a5=`echo "$ARGS" | getNamedArg a5`
a6=`echo "$ARGS" | getNamedArg a6`
a7=`echo "$ARGS" | getNamedArg a7`
echo "a1 = \"$a1\""
echo "a2 = \"$a2\""
echo "a3 = \"$a3\""
echo "a4 = \"$a4\""
echo "a5 = \"$a5\""
echo "a6 = \"$a6\""
echo "a7 = \"$a7\""
exit 0
}
function getArgs() {
for arg in "$@"; do
echo "$arg"
done
}
function getNamedArg() {
ARG_NAME=$1
sed --regexp-extended --quiet --expression="
s/^--$ARG_NAME=(.*)\$/\1/p # Get arguments in format '--arg=value': [s]ubstitute '--arg=value' by 'value', and [p]rint
/^--$ARG_NAME\$/ { # Get arguments in format '--arg value' ou '--arg'
n # - [n]ext, because in this format, if value exists, it will be the next argument
/^--/! p # - If next doesn't starts with '--', it is the value of the actual argument
/^--/ { # - If next do starts with '--', it is the next argument and the actual argument is a boolean one
# Then just repla[c]ed by TRUE
c TRUE
}
}
"
}
main "$@"
#!/bin/bash
while getopts "abc:d:" flag
do
case $flag in
a) echo "[getopts:$OPTIND]==> -$flag";;
b) echo "[getopts:$OPTIND]==> -$flag";;
c) echo "[getopts:$OPTIND]==> -$flag $OPTARG";;
d) echo "[getopts:$OPTIND]==> -$flag $OPTARG";;
esac
done
shift $((OPTIND-1))
echo "[otheropts]==> $@"
exit
.
#!/bin/bash
until [ -z "$1" ]; do
case $1 in
"--dlong")
shift
if [ "${1:1:0}" != "-" ]
then
echo "==> dlong $1"
shift
fi;;
*) echo "==> other $1"; shift;;
esac
done
exit