我希望使用shell脚本调用长形式和短形式的命令行选项。

我知道可以使用getopts,但是像在Perl中一样,我不能用shell做同样的事情。

关于如何做到这一点的任何想法,这样我就可以使用如下选项:

./shell.sh --copyfile abc.pl /tmp/
./shell.sh -c abc.pl /tmp/

在上面,这两个命令对我的shell意味着同样的事情,但使用getopts,我还不能实现这些?


当前回答

例如,如果所有长选项都有唯一且匹配的首字符作为短选项

./slamm --chaos 23 --plenty test -quiet

./slamm -c 23 -p test -q

你可以在getopts重写$args之前使用它:

# change long options to short options

for arg; do 
    [[ "${arg:0:1}" == "-" ]] && delim="" || delim="\""
    if [ "${arg:0:2}" == "--" ]; 
       then args="${args} -${arg:2:1}" 
       else args="${args} ${delim}${arg}${delim}"
    fi
done

# reset the incoming args
eval set -- $args

# proceed as usual
while getopts ":b:la:h" OPTION; do
    .....

谢谢mtvee的灵感;-)

其他回答

如果你不想要getopt依赖,你可以这样做:

while test $# -gt 0
do
  case $1 in

  # Normal option processing
    -h | --help)
      # usage and help
      ;;
    -v | --version)
      # version info
      ;;
  # ...

  # Special cases
    --)
      break
      ;;
    --*)
      # error unknown (long) option $1
      ;;
    -?)
      # error unknown (short) option $1
      ;;

  # FUN STUFF HERE:
  # Split apart combined short options
    -*)
      split=$1
      shift
      set -- $(echo "$split" | cut -c 2- | sed 's/./-& /g') "$@"
      continue
      ;;

  # Done with options
    *)
      break
      ;;
  esac

  # for testing purposes:
  echo "$1"

  shift
done

当然,这样你就不能使用长样式选项。如果你想添加缩短的版本(例如——verbos而不是——verbose),那么你需要手动添加这些。

但是如果您希望获得getopts功能和长选项,这是一种简单的方法。

我也把这个片段作为一个主旨。

下面是一个实际使用长选项的getopt的示例:

aflag=no
bflag=no
cargument=none

# options may be followed by one colon to indicate they have a required argument
if ! options=$(getopt -o abc: -l along,blong,clong: -- "$@")
then
    # something went wrong, getopt will put out an error message for us
    exit 1
fi

set -- $options

while [ $# -gt 0 ]
do
    case $1 in
    -a|--along) aflag="yes" ;;
    -b|--blong) bflag="yes" ;;
    # for options with required arguments, an additional shift is required
    -c|--clong) cargument="$2" ; shift;;
    (--) shift; break;;
    (-*) echo "$0: error - unrecognized option $1" 1>&2; exit 1;;
    (*) break;;
    esac
    shift
done

我还没有足够的代表来评论或投票他的解决方案,但他的答案对我来说非常有效。我遇到的唯一问题是参数以单引号结尾(所以我把它们去掉了)。

我还添加了一些示例用法和帮助文本。我将在这里附上我略微扩展的版本:

#!/bin/bash

# getopt example
# from: https://stackoverflow.com/questions/402377/using-getopts-in-bash-shell-script-to-get-long-and-short-command-line-options
HELP_TEXT=\
"   USAGE:\n
    Accepts - and -- flags, can specify options that require a value, and can be in any order. A double-hyphen (--) will stop processing options.\n\n

    Accepts the following forms:\n\n

    getopt-example.sh -a -b -c value-for-c some-arg\n
    getopt-example.sh -c value-for-c -a -b some-arg\n
    getopt-example.sh -abc some-arg\n
    getopt-example.sh --along --blong --clong value-for-c -a -b -c some-arg\n
    getopt-example.sh some-arg --clong value-for-c\n
    getopt-example.sh
"

aflag=false
bflag=false
cargument=""

# options may be followed by one colon to indicate they have a required argument
if ! options=$(getopt -o abc:h\? -l along,blong,help,clong: -- "$@")
then
    # something went wrong, getopt will put out an error message for us
    exit 1
fi

set -- $options

while [ $# -gt 0 ]
do
    case $1 in
    -a|--along) aflag=true ;;
    -b|--blong) bflag=true ;;
    # for options with required arguments, an additional shift is required
    -c|--clong) cargument="$2" ; shift;;
    -h|--help|-\?) echo -e $HELP_TEXT; exit;;
    (--) shift; break;;
    (-*) echo "$0: error - unrecognized option $1" 1>&2; exit 1;;
    (*) break;;
    esac
    shift
done

# to remove the single quotes around arguments, pipe the output into:
# | sed -e "s/^'\\|'$//g"  (just leading/trailing) or | sed -e "s/'//g"  (all)

echo aflag=${aflag}
echo bflag=${bflag}
echo cargument=${cargument}

while [ $# -gt 0 ]
do
    echo arg=$1
    shift

    if [[ $aflag == true ]]; then
        echo a is true
    fi

done

一个简单的DIY,只获得长名称的参数:

Use:

$ ./test-args.sh --a1 a1 --a2 "a 2" --a3 --a4= --a5=a5 --a6="a 6"
a1 = "a1"
a2 = "a 2"
a3 = "TRUE"
a4 = ""
a5 = "a5"
a6 = "a 6"
a7 = ""

脚本:

#!/bin/bash

function main() {
    ARGS=`getArgs "$@"`

    a1=`echo "$ARGS" | getNamedArg a1`
    a2=`echo "$ARGS" | getNamedArg a2`
    a3=`echo "$ARGS" | getNamedArg a3`
    a4=`echo "$ARGS" | getNamedArg a4`
    a5=`echo "$ARGS" | getNamedArg a5`
    a6=`echo "$ARGS" | getNamedArg a6`
    a7=`echo "$ARGS" | getNamedArg a7`

    echo "a1 = \"$a1\""
    echo "a2 = \"$a2\""
    echo "a3 = \"$a3\""
    echo "a4 = \"$a4\""
    echo "a5 = \"$a5\""
    echo "a6 = \"$a6\""
    echo "a7 = \"$a7\""

    exit 0
}


function getArgs() {
    for arg in "$@"; do
        echo "$arg"
    done
}


function getNamedArg() {
    ARG_NAME=$1

    sed --regexp-extended --quiet --expression="
        s/^--$ARG_NAME=(.*)\$/\1/p  # Get arguments in format '--arg=value': [s]ubstitute '--arg=value' by 'value', and [p]rint
        /^--$ARG_NAME\$/ {          # Get arguments in format '--arg value' ou '--arg'
            n                       # - [n]ext, because in this format, if value exists, it will be the next argument
            /^--/! p                # - If next doesn't starts with '--', it is the value of the actual argument
            /^--/ {                 # - If next do starts with '--', it is the next argument and the actual argument is a boolean one
                # Then just repla[c]ed by TRUE
                c TRUE
            }
        }
    "
}


main "$@"
#!/bin/bash
while getopts "abc:d:" flag
do
  case $flag in
    a) echo "[getopts:$OPTIND]==> -$flag";;
    b) echo "[getopts:$OPTIND]==> -$flag";;
    c) echo "[getopts:$OPTIND]==> -$flag $OPTARG";;
    d) echo "[getopts:$OPTIND]==> -$flag $OPTARG";;
  esac
done

shift $((OPTIND-1))
echo "[otheropts]==> $@"

exit

.

#!/bin/bash
until [ -z "$1" ]; do
  case $1 in
    "--dlong")
      shift
      if [ "${1:1:0}" != "-" ]
      then
        echo "==> dlong $1"
        shift
      fi;;
    *) echo "==> other $1"; shift;;
  esac
done
exit