如何将std::vector的内容打印到屏幕上?


实现以下操作符<<的解决方案也很好:

template<container C, class T, String delim = ", ", String open = "[", String close = "]">
std::ostream & operator<<(std::ostream & o, const C<T> & x)
{
  // ... What can I write here?
}

以下是目前为止我所做的,没有单独的函数:

#include <iostream>
#include <fstream>
#include <string>
#include <cmath>
#include <vector>
#include <sstream>
#include <cstdio>
using namespace std;

int main()
{
    ifstream file("maze.txt");
    if (file) {
        vector<char> vec(istreambuf_iterator<char>(file), (istreambuf_iterator<char>()));
        vector<char> path;
        int x = 17;
        char entrance = vec.at(16);
        char firstsquare = vec.at(x);
        if (entrance == 'S') { 
            path.push_back(entrance); 
        }
        for (x = 17; isalpha(firstsquare); x++) {
            path.push_back(firstsquare);
        }
        for (int i = 0; i < path.size(); i++) {
            cout << path[i] << " ";
        }
        cout << endl;
        return 0;
    }
}

当前回答

模板收集:

应用std::cout <<和std::to_string

std::vector、std::array和std::tuple

由于在cpp中打印一个向量被证明是惊人的工作量(至少与这个任务的基本程度相比),并且作为再次跨越相同问题的一个步骤,当使用其他容器时,这里有一个更通用的解决方案…

模板收集内容

这个模板集合处理3种容器类型: Std::vector, Std::array和Std::tuple。 它为这些对象定义了std::to_string(),并可以通过std::cout << container;直接将它们打印出来。

此外,它还为std::string << container定义了<<运算符。 这样就可以以紧凑的方式构造包含这些容器类型的字符串。

From

std::string s1 = "s1: " + std::to_string(arr) + "; " + std::to_string(vec) + "; " + std::to_string(tup);

我们会讲到

std::string s2 = STR() << "s2: " << arr << "; " << vec << "; " << tup;

Code

您可以交互地测试这段代码:这里。

#include <iostream>
#include <string>
#include <tuple>
#include <vector>
#include <array>

namespace std
{   
    // declations: needed for std::to_string(std::vector<std::tuple<int, float>>)
    std::string to_string(std::string str);
    std::string to_string(const char *str);
    template<typename T, size_t N>
    std::string to_string(std::array<T, N> const& arr);
    template<typename T>
    std::string to_string(std::vector<T> const& vec);
    template<typename... Args>
    std::string to_string(const std::tuple<Args...>& tup);
    
    std::string to_string(std::string str)
    {
        return std::string(str);
    }
    std::string to_string(const char *str)
    {
        return std::string(str);
    }

    template<typename T, size_t N>
    std::string to_string(std::array<T, N> const& arr)
    {
        std::string s="{";
        for (std::size_t t = 0; t != N; ++t)
            s += std::to_string(arr[t]) + (t+1 < N ? ", ":"");
        return s + "}";
    }

    template<typename T>
    std::string to_string(std::vector<T> const& vec)
    {
        std::string s="[";
        for (std::size_t t = 0; t != vec.size(); ++t)
            s += std::to_string(vec[t]) + (t+1 < vec.size() ? ", ":"");
        return s + "]";
    }
    
    // to_string(tuple)
    // https://en.cppreference.com/w/cpp/utility/tuple/operator%3D
    template<class Tuple, std::size_t N>
    struct TupleString
    {
        static std::string str(const Tuple& tup)
        {
            std::string out;
            out += TupleString<Tuple, N-1>::str(tup);
            out += ", ";
            out += std::to_string(std::get<N-1>(tup));
            return out;
        }
    };
    template<class Tuple>
    struct TupleString<Tuple, 1>
    {
        static std::string str(const Tuple& tup)
        {
            std::string out;
            out += std::to_string(std::get<0>(tup));
            return out;
        }
    };
    template<typename... Args>
    std::string to_string(const std::tuple<Args...>& tup)
    {
        std::string out = "(";
        out += TupleString<decltype(tup), sizeof...(Args)>::str(tup);
        out += ")";
        return out;
    }
} // namespace std


/**
 * cout: cout << continer
 */
template <typename T, std::size_t N> // cout << array
std::ostream& operator <<(std::ostream &out, std::array<T, N> &con)
{
    out <<  std::to_string(con);
    return out;
}
template <typename T, typename A> // cout << vector
std::ostream& operator <<(std::ostream &out, std::vector<T, A> &con)
{
    out <<  std::to_string(con);
    return out;
}
template<typename... Args> // cout << tuple
std::ostream& operator <<(std::ostream &out, std::tuple<Args...> &con)
{
    out <<  std::to_string(con);
    return out;
}

/**
 * Concatenate: string << continer
 */
template <class C>
std::string operator <<(std::string str, C &con)
{
    std::string out = str;
    out += std::to_string(con);
    return out;
}
#define STR() std::string("")

int main()
{
    std::array<int, 3> arr {1, 2, 3};
    std::string sArr = std::to_string(arr);
    std::cout << "std::array" << std::endl;
    std::cout << "\ttest to_string: " << sArr << std::endl;
    std::cout << "\ttest cout <<: " << arr << std::endl;
    std::cout << "\ttest string <<: " << (std::string() << arr) << std::endl;
    
    std::vector<std::string> vec {"a", "b"};
    std::string sVec = std::to_string(vec);
    std::cout << "std::vector" << std::endl;
    std::cout << "\ttest to_string: " << sVec << std::endl;
    std::cout << "\ttest cout <<: " << vec << std::endl;
    std::cout << "\ttest string <<: " << (std::string() << vec) << std::endl;
    
    std::tuple<int, std::string> tup = std::make_tuple(5, "five");
    std::string sTup = std::to_string(tup);
    std::cout << "std::tuple" << std::endl;
    std::cout << "\ttest to_string: " << sTup << std::endl;
    std::cout << "\ttest cout <<: " << tup << std::endl;
    std::cout << "\ttest string <<: " << (std::string() << tup) << std::endl;
    
    std::vector<std::tuple<int, float>> vt {std::make_tuple(1, .1), std::make_tuple(2, .2)};
    std::string sVt = std::to_string(vt);
    std::cout << "std::vector<std::tuple>" << std::endl;
    std::cout << "\ttest to_string: " << sVt << std::endl;
    std::cout << "\ttest cout <<: " << vt << std::endl;
    std::cout << "\ttest string <<: " << (std::string() << vt) << std::endl;
    
    std::cout << std::endl;
    
    std::string s1 = "s1: " + std::to_string(arr) + "; " + std::to_string(vec) + "; " + std::to_string(tup);
    std::cout << s1 << std::endl;
    
    std::string s2 = STR() << "s2: " << arr << "; " << vec << "; " << tup;
    std::cout << s2 << std::endl;

    return 0;
}

输出

std::array
    test to_string: {1, 2, 3}
    test cout <<: {1, 2, 3}
    test string <<: {1, 2, 3}
std::vector
    test to_string: [a, b]
    test cout <<: [a, b]
    test string <<: [a, b]
std::tuple
    test to_string: (5, five)
    test cout <<: (5, five)
    test string <<: (5, five)
std::vector<std::tuple>
    test to_string: [(1, 0.100000), (2, 0.200000)]
    test cout <<: [(1, 0.100000), (2, 0.200000)]
    test string <<: [(1, 0.100000), (2, 0.200000)]

s1: {1, 2, 3}; [a, b]; (5, five)
s2: {1, 2, 3}; [a, b]; (5, five)

其他回答

我的解决方案是simple.h,它是scc包的一部分。所有std容器,map, set, c-arrays都是可打印的。

模板收集:

应用std::cout <<和std::to_string

std::vector、std::array和std::tuple

由于在cpp中打印一个向量被证明是惊人的工作量(至少与这个任务的基本程度相比),并且作为再次跨越相同问题的一个步骤,当使用其他容器时,这里有一个更通用的解决方案…

模板收集内容

这个模板集合处理3种容器类型: Std::vector, Std::array和Std::tuple。 它为这些对象定义了std::to_string(),并可以通过std::cout << container;直接将它们打印出来。

此外,它还为std::string << container定义了<<运算符。 这样就可以以紧凑的方式构造包含这些容器类型的字符串。

From

std::string s1 = "s1: " + std::to_string(arr) + "; " + std::to_string(vec) + "; " + std::to_string(tup);

我们会讲到

std::string s2 = STR() << "s2: " << arr << "; " << vec << "; " << tup;

Code

您可以交互地测试这段代码:这里。

#include <iostream>
#include <string>
#include <tuple>
#include <vector>
#include <array>

namespace std
{   
    // declations: needed for std::to_string(std::vector<std::tuple<int, float>>)
    std::string to_string(std::string str);
    std::string to_string(const char *str);
    template<typename T, size_t N>
    std::string to_string(std::array<T, N> const& arr);
    template<typename T>
    std::string to_string(std::vector<T> const& vec);
    template<typename... Args>
    std::string to_string(const std::tuple<Args...>& tup);
    
    std::string to_string(std::string str)
    {
        return std::string(str);
    }
    std::string to_string(const char *str)
    {
        return std::string(str);
    }

    template<typename T, size_t N>
    std::string to_string(std::array<T, N> const& arr)
    {
        std::string s="{";
        for (std::size_t t = 0; t != N; ++t)
            s += std::to_string(arr[t]) + (t+1 < N ? ", ":"");
        return s + "}";
    }

    template<typename T>
    std::string to_string(std::vector<T> const& vec)
    {
        std::string s="[";
        for (std::size_t t = 0; t != vec.size(); ++t)
            s += std::to_string(vec[t]) + (t+1 < vec.size() ? ", ":"");
        return s + "]";
    }
    
    // to_string(tuple)
    // https://en.cppreference.com/w/cpp/utility/tuple/operator%3D
    template<class Tuple, std::size_t N>
    struct TupleString
    {
        static std::string str(const Tuple& tup)
        {
            std::string out;
            out += TupleString<Tuple, N-1>::str(tup);
            out += ", ";
            out += std::to_string(std::get<N-1>(tup));
            return out;
        }
    };
    template<class Tuple>
    struct TupleString<Tuple, 1>
    {
        static std::string str(const Tuple& tup)
        {
            std::string out;
            out += std::to_string(std::get<0>(tup));
            return out;
        }
    };
    template<typename... Args>
    std::string to_string(const std::tuple<Args...>& tup)
    {
        std::string out = "(";
        out += TupleString<decltype(tup), sizeof...(Args)>::str(tup);
        out += ")";
        return out;
    }
} // namespace std


/**
 * cout: cout << continer
 */
template <typename T, std::size_t N> // cout << array
std::ostream& operator <<(std::ostream &out, std::array<T, N> &con)
{
    out <<  std::to_string(con);
    return out;
}
template <typename T, typename A> // cout << vector
std::ostream& operator <<(std::ostream &out, std::vector<T, A> &con)
{
    out <<  std::to_string(con);
    return out;
}
template<typename... Args> // cout << tuple
std::ostream& operator <<(std::ostream &out, std::tuple<Args...> &con)
{
    out <<  std::to_string(con);
    return out;
}

/**
 * Concatenate: string << continer
 */
template <class C>
std::string operator <<(std::string str, C &con)
{
    std::string out = str;
    out += std::to_string(con);
    return out;
}
#define STR() std::string("")

int main()
{
    std::array<int, 3> arr {1, 2, 3};
    std::string sArr = std::to_string(arr);
    std::cout << "std::array" << std::endl;
    std::cout << "\ttest to_string: " << sArr << std::endl;
    std::cout << "\ttest cout <<: " << arr << std::endl;
    std::cout << "\ttest string <<: " << (std::string() << arr) << std::endl;
    
    std::vector<std::string> vec {"a", "b"};
    std::string sVec = std::to_string(vec);
    std::cout << "std::vector" << std::endl;
    std::cout << "\ttest to_string: " << sVec << std::endl;
    std::cout << "\ttest cout <<: " << vec << std::endl;
    std::cout << "\ttest string <<: " << (std::string() << vec) << std::endl;
    
    std::tuple<int, std::string> tup = std::make_tuple(5, "five");
    std::string sTup = std::to_string(tup);
    std::cout << "std::tuple" << std::endl;
    std::cout << "\ttest to_string: " << sTup << std::endl;
    std::cout << "\ttest cout <<: " << tup << std::endl;
    std::cout << "\ttest string <<: " << (std::string() << tup) << std::endl;
    
    std::vector<std::tuple<int, float>> vt {std::make_tuple(1, .1), std::make_tuple(2, .2)};
    std::string sVt = std::to_string(vt);
    std::cout << "std::vector<std::tuple>" << std::endl;
    std::cout << "\ttest to_string: " << sVt << std::endl;
    std::cout << "\ttest cout <<: " << vt << std::endl;
    std::cout << "\ttest string <<: " << (std::string() << vt) << std::endl;
    
    std::cout << std::endl;
    
    std::string s1 = "s1: " + std::to_string(arr) + "; " + std::to_string(vec) + "; " + std::to_string(tup);
    std::cout << s1 << std::endl;
    
    std::string s2 = STR() << "s2: " << arr << "; " << vec << "; " << tup;
    std::cout << s2 << std::endl;

    return 0;
}

输出

std::array
    test to_string: {1, 2, 3}
    test cout <<: {1, 2, 3}
    test string <<: {1, 2, 3}
std::vector
    test to_string: [a, b]
    test cout <<: [a, b]
    test string <<: [a, b]
std::tuple
    test to_string: (5, five)
    test cout <<: (5, five)
    test string <<: (5, five)
std::vector<std::tuple>
    test to_string: [(1, 0.100000), (2, 0.200000)]
    test cout <<: [(1, 0.100000), (2, 0.200000)]
    test string <<: [(1, 0.100000), (2, 0.200000)]

s1: {1, 2, 3}; [a, b]; (5, five)
s2: {1, 2, 3}; [a, b]; (5, five)

如果boost是一个选项,那么你可以使用boost::algorithm::join。例如,打印std::string的向量:

#include <boost/algorithm/string/join.hpp>

std::vector<std::string> vs { "some", "string", "vector" };
std::cout << boost::algorithm::join(vs, " | ") << '\n';

对于其他类型的向量,首先需要转换为字符串

#include <algorithm>
#include <iostream>
#include <numeric>
#include <vector>

#include <boost/algorithm/string/join.hpp>
#include <boost/range/adaptor/transformed.hpp>

int main()
{
    using boost::adaptors::transformed;
    using boost::algorithm::join;

    // Generate the vector
    std::vector<int> vi(10);
    std::iota(vi.begin(), vi.end(), -3);

    // Print out the vector
    std::cout << join(vi |
                 transformed(static_cast<std::string(*)(int)>(std::to_string)),
                 ", ")
              << '\n';
}

Godbolt演示

我将在这里添加另一个答案,因为我已经提出了与之前的方法不同的方法,那就是使用locale facet。

基本原理在这里

基本上你要做的是:

Create a class that derives from std::locale::facet. The slight downside is that you will need a compilation unit somewhere to hold its id. Let's call it MyPrettyVectorPrinter. You'd probably give it a better name, and also create ones for pair and map. In your stream function, you check std::has_facet< MyPrettyVectorPrinter > If that returns true, extract it with std::use_facet< MyPrettyVectorPrinter >( os.getloc() ) Your facet objects will have values for the delimiters and you can read them. If the facet isn't found, your print function (operator<<) provides default ones. Note you can do the same thing for reading a vector.

我喜欢这种方法,因为你可以使用默认打印,同时仍然能够使用自定义覆盖。

缺点是如果在多个项目中使用facet,则需要一个面向facet的库(因此不能仅仅是头文件),而且需要注意创建一个新的locale对象的开销。

我把这个作为一个新的解决方案来写,而不是修改我的另一个解决方案,因为我相信两种方法都是正确的,你可以选择。

我认为最好的方法是通过在程序中添加这个函数来重载操作符<<:

#include <vector>
using std::vector;
#include <iostream>
using std::ostream;

template<typename T>
ostream& operator<< (ostream& out, const vector<T>& v) {
    out << "{";
    size_t last = v.size() - 1;
    for(size_t i = 0; i < v.size(); ++i) {
        out << v[i];
        if (i != last) 
            out << ", ";
    }
    out << "}";
    return out;
}

然后你可以在任何可能的向量上使用<<运算符,假设它的元素也定义了ostream&运算符<<:

vector<string>  s = {"first", "second", "third"};
vector<bool>    b = {true, false, true, false, false};
vector<int>     i = {1, 2, 3, 4};
cout << s << endl;
cout << b << endl;
cout << i << endl;

输出:

{first, second, third}
{1, 0, 1, 0, 0}
{1, 2, 3, 4}