如何将std::vector的内容打印到屏幕上?


实现以下操作符<<的解决方案也很好:

template<container C, class T, String delim = ", ", String open = "[", String close = "]">
std::ostream & operator<<(std::ostream & o, const C<T> & x)
{
  // ... What can I write here?
}

以下是目前为止我所做的,没有单独的函数:

#include <iostream>
#include <fstream>
#include <string>
#include <cmath>
#include <vector>
#include <sstream>
#include <cstdio>
using namespace std;

int main()
{
    ifstream file("maze.txt");
    if (file) {
        vector<char> vec(istreambuf_iterator<char>(file), (istreambuf_iterator<char>()));
        vector<char> path;
        int x = 17;
        char entrance = vec.at(16);
        char firstsquare = vec.at(x);
        if (entrance == 'S') { 
            path.push_back(entrance); 
        }
        for (x = 17; isalpha(firstsquare); x++) {
            path.push_back(firstsquare);
        }
        for (int i = 0; i < path.size(); i++) {
            cout << path[i] << " ";
        }
        cout << endl;
        return 0;
    }
}

当前回答

这已经被编辑了几次,我们决定调用包装集合的主类RangePrinter。

一旦您编写了一次性操作符<< overload,这将自动适用于任何集合,除非您将需要一个特殊的映射来打印对,并且可能希望在那里自定义分隔符。

您还可以在项目上使用特殊的“print”函数,而不是直接输出它,有点像STL算法允许您传入自定义谓词。对于map,您可以这样使用它,使用std::pair的自定义打印机。

您的“默认”打印机只会将其输出到流中。

好的,让我们用一台定制打印机。我将外层类改为RangePrinter。所以我们有两个迭代器和一些分隔符,但还没有定制如何打印实际的项。

struct DefaultPrinter
{
   template< typename T >
   std::ostream & operator()( std::ostream& os, const T& t ) const
   {
     return os << t;
   }

   // overload for std::pair
   template< typename K, typename V >
   std::ostream & operator()( std::ostream & os, std::pair<K,V> const& p)
   {
      return os << p.first << '=' << p.second;
   }
};

// some prototypes
template< typename FwdIter, typename Printer > class RangePrinter;

template< typename FwdIter, typename Printer > 
  std::ostream & operator<<( std::ostream &, 
        RangePrinter<FwdIter, Printer> const& );

template< typename FwdIter, typename Printer=DefaultPrinter >
class RangePrinter
{
    FwdIter begin;
    FwdIter end;
    std::string delim;
    std::string open;
    std::string close;
    Printer printer;

    friend std::ostream& operator<< <>( std::ostream&, 
         RangePrinter<FwdIter,Printer> const& );

public:
    RangePrinter( FwdIter b, FwdIter e, Printer p,
         std::string const& d, std::string const & o, std::string const& c )
      : begin( b ), end( e ), printer( p ), open( o ), close( c )
    {
    } 

     // with no "printer" variable
    RangePrinter( FwdIter b, FwdIter e,
         std::string const& d, std::string const & o, std::string const& c )
      : begin( b ), end( e ), open( o ), close( c )
    {
    } 

};


template<typename FwdIter, typename Printer>
std::ostream& operator<<( std::ostream& os, 
          RangePrinter<FwdIter, Printer> const& range )
{
    const Printer & printer = range.printer;

    os << range.open;
    FwdIter begin = range.begin, end = range.end;

    // print the first item
    if (begin == end) 
    { 
      return os << range.close; 
    }

    printer( os, *begin );

    // print the rest with delim as a prefix
    for( ++begin; begin != end; ++begin )
    {
       os << range.delim;
       printer( os, *begin );
    }
    return os << range.close;
}

现在,默认情况下,只要键和值类型都是可打印的,并且当它们都不是可打印的(就像任何其他类型一样),或者如果您不想要“=”作为分隔符,它就可以用于映射,并且您可以使用自己的特殊项目打印机。

现在,我将自由函数移到末尾来创建这些:

free-function(迭代器版本)看起来像这样,你甚至可以有默认值:

template<typename Collection>
RangePrinter<typename Collection::const_iterator> rangePrinter
    ( const Collection& coll, const char * delim=",", 
       const char * open="[", const char * close="]")
{
   return RangePrinter< typename Collection::const_iterator >
     ( coll.begin(), coll.end(), delim, open, close );
}

然后你可以将它用于std::set by

 std::cout << outputFormatter( mySet );

您还可以编写带有自定义打印机和带有两个迭代器的自由函数版本。在任何情况下,它们都将为您解析模板参数,并且您将能够将它们作为临时参数传递。

其他回答

我看到了两个问题。正如在

for (x = 17; isalpha(firstsquare); x++)

要么是一个无限循环,要么根本没有执行,同样在if(入口== 'S')中,如果入口字符与'S'不同,则没有任何东西被推送到路径向量,使其为空,因此在屏幕上不打印任何东西。您可以检查path.empty()或打印path.size()来测试后者。

不管怎样,使用字符串而不是向量不是更好吗?您可以像访问数组一样访问字符串内容,查找字符,提取子字符串并轻松打印字符串(无需循环)。

用字符串来完成这一切可能是用一种不那么复杂的方式来编写它,并且更容易发现问题。

模板收集:

应用std::cout <<和std::to_string

std::vector、std::array和std::tuple

由于在cpp中打印一个向量被证明是惊人的工作量(至少与这个任务的基本程度相比),并且作为再次跨越相同问题的一个步骤,当使用其他容器时,这里有一个更通用的解决方案…

模板收集内容

这个模板集合处理3种容器类型: Std::vector, Std::array和Std::tuple。 它为这些对象定义了std::to_string(),并可以通过std::cout << container;直接将它们打印出来。

此外,它还为std::string << container定义了<<运算符。 这样就可以以紧凑的方式构造包含这些容器类型的字符串。

From

std::string s1 = "s1: " + std::to_string(arr) + "; " + std::to_string(vec) + "; " + std::to_string(tup);

我们会讲到

std::string s2 = STR() << "s2: " << arr << "; " << vec << "; " << tup;

Code

您可以交互地测试这段代码:这里。

#include <iostream>
#include <string>
#include <tuple>
#include <vector>
#include <array>

namespace std
{   
    // declations: needed for std::to_string(std::vector<std::tuple<int, float>>)
    std::string to_string(std::string str);
    std::string to_string(const char *str);
    template<typename T, size_t N>
    std::string to_string(std::array<T, N> const& arr);
    template<typename T>
    std::string to_string(std::vector<T> const& vec);
    template<typename... Args>
    std::string to_string(const std::tuple<Args...>& tup);
    
    std::string to_string(std::string str)
    {
        return std::string(str);
    }
    std::string to_string(const char *str)
    {
        return std::string(str);
    }

    template<typename T, size_t N>
    std::string to_string(std::array<T, N> const& arr)
    {
        std::string s="{";
        for (std::size_t t = 0; t != N; ++t)
            s += std::to_string(arr[t]) + (t+1 < N ? ", ":"");
        return s + "}";
    }

    template<typename T>
    std::string to_string(std::vector<T> const& vec)
    {
        std::string s="[";
        for (std::size_t t = 0; t != vec.size(); ++t)
            s += std::to_string(vec[t]) + (t+1 < vec.size() ? ", ":"");
        return s + "]";
    }
    
    // to_string(tuple)
    // https://en.cppreference.com/w/cpp/utility/tuple/operator%3D
    template<class Tuple, std::size_t N>
    struct TupleString
    {
        static std::string str(const Tuple& tup)
        {
            std::string out;
            out += TupleString<Tuple, N-1>::str(tup);
            out += ", ";
            out += std::to_string(std::get<N-1>(tup));
            return out;
        }
    };
    template<class Tuple>
    struct TupleString<Tuple, 1>
    {
        static std::string str(const Tuple& tup)
        {
            std::string out;
            out += std::to_string(std::get<0>(tup));
            return out;
        }
    };
    template<typename... Args>
    std::string to_string(const std::tuple<Args...>& tup)
    {
        std::string out = "(";
        out += TupleString<decltype(tup), sizeof...(Args)>::str(tup);
        out += ")";
        return out;
    }
} // namespace std


/**
 * cout: cout << continer
 */
template <typename T, std::size_t N> // cout << array
std::ostream& operator <<(std::ostream &out, std::array<T, N> &con)
{
    out <<  std::to_string(con);
    return out;
}
template <typename T, typename A> // cout << vector
std::ostream& operator <<(std::ostream &out, std::vector<T, A> &con)
{
    out <<  std::to_string(con);
    return out;
}
template<typename... Args> // cout << tuple
std::ostream& operator <<(std::ostream &out, std::tuple<Args...> &con)
{
    out <<  std::to_string(con);
    return out;
}

/**
 * Concatenate: string << continer
 */
template <class C>
std::string operator <<(std::string str, C &con)
{
    std::string out = str;
    out += std::to_string(con);
    return out;
}
#define STR() std::string("")

int main()
{
    std::array<int, 3> arr {1, 2, 3};
    std::string sArr = std::to_string(arr);
    std::cout << "std::array" << std::endl;
    std::cout << "\ttest to_string: " << sArr << std::endl;
    std::cout << "\ttest cout <<: " << arr << std::endl;
    std::cout << "\ttest string <<: " << (std::string() << arr) << std::endl;
    
    std::vector<std::string> vec {"a", "b"};
    std::string sVec = std::to_string(vec);
    std::cout << "std::vector" << std::endl;
    std::cout << "\ttest to_string: " << sVec << std::endl;
    std::cout << "\ttest cout <<: " << vec << std::endl;
    std::cout << "\ttest string <<: " << (std::string() << vec) << std::endl;
    
    std::tuple<int, std::string> tup = std::make_tuple(5, "five");
    std::string sTup = std::to_string(tup);
    std::cout << "std::tuple" << std::endl;
    std::cout << "\ttest to_string: " << sTup << std::endl;
    std::cout << "\ttest cout <<: " << tup << std::endl;
    std::cout << "\ttest string <<: " << (std::string() << tup) << std::endl;
    
    std::vector<std::tuple<int, float>> vt {std::make_tuple(1, .1), std::make_tuple(2, .2)};
    std::string sVt = std::to_string(vt);
    std::cout << "std::vector<std::tuple>" << std::endl;
    std::cout << "\ttest to_string: " << sVt << std::endl;
    std::cout << "\ttest cout <<: " << vt << std::endl;
    std::cout << "\ttest string <<: " << (std::string() << vt) << std::endl;
    
    std::cout << std::endl;
    
    std::string s1 = "s1: " + std::to_string(arr) + "; " + std::to_string(vec) + "; " + std::to_string(tup);
    std::cout << s1 << std::endl;
    
    std::string s2 = STR() << "s2: " << arr << "; " << vec << "; " << tup;
    std::cout << s2 << std::endl;

    return 0;
}

输出

std::array
    test to_string: {1, 2, 3}
    test cout <<: {1, 2, 3}
    test string <<: {1, 2, 3}
std::vector
    test to_string: [a, b]
    test cout <<: [a, b]
    test string <<: [a, b]
std::tuple
    test to_string: (5, five)
    test cout <<: (5, five)
    test string <<: (5, five)
std::vector<std::tuple>
    test to_string: [(1, 0.100000), (2, 0.200000)]
    test cout <<: [(1, 0.100000), (2, 0.200000)]
    test string <<: [(1, 0.100000), (2, 0.200000)]

s1: {1, 2, 3}; [a, b]; (5, five)
s2: {1, 2, 3}; [a, b]; (5, five)

我写了一个操作符<<,它输出任何可迭代对象,包括自定义容器、标准容器和具有已知边界的数组。需要c++ 11:

template<typename Container, typename = 
    std::enable_if_t<std::is_same_v<std::void_t<
        decltype(static_cast<typename Container::const_iterator (*)(const Container&)>(&std::cbegin)),
        decltype(static_cast<typename Container::const_iterator (*)(const Container&)>(&std::cend))>, void>
        && !std::is_same_v<std::string, Container>>>
std::ostream& operator<<(std::ostream& out, const Container &vec)
{
    std::cout << "[ ";
    for(const auto& t: vec){
        std::cout << t << " ";
    }
    std::cout << "] ";
    return out;
}

这个解决方案的灵感来自Marcelo的解决方案,有一些变化:

#include <iostream>
#include <iterator>
#include <type_traits>
#include <vector>
#include <algorithm>

// This works similar to ostream_iterator, but doesn't print a delimiter after the final item
template<typename T, typename TChar = char, typename TCharTraits = std::char_traits<TChar> >
class pretty_ostream_iterator : public std::iterator<std::output_iterator_tag, void, void, void, void>
{
public:
    typedef TChar char_type;
    typedef TCharTraits traits_type;
    typedef std::basic_ostream<TChar, TCharTraits> ostream_type;

    pretty_ostream_iterator(ostream_type &stream, const char_type *delim = NULL)
        : _stream(&stream), _delim(delim), _insertDelim(false)
    {
    }

    pretty_ostream_iterator<T, TChar, TCharTraits>& operator=(const T &value)
    {
        if( _delim != NULL )
        {
            // Don't insert a delimiter if this is the first time the function is called
            if( _insertDelim )
                (*_stream) << _delim;
            else
                _insertDelim = true;
        }
        (*_stream) << value;
        return *this;
    }

    pretty_ostream_iterator<T, TChar, TCharTraits>& operator*()
    {
        return *this;
    }

    pretty_ostream_iterator<T, TChar, TCharTraits>& operator++()
    {
        return *this;
    }

    pretty_ostream_iterator<T, TChar, TCharTraits>& operator++(int)
    {
        return *this;
    }
private:
    ostream_type *_stream;
    const char_type *_delim;
    bool _insertDelim;
};

#if _MSC_VER >= 1400

// Declare pretty_ostream_iterator as checked
template<typename T, typename TChar, typename TCharTraits>
struct std::_Is_checked_helper<pretty_ostream_iterator<T, TChar, TCharTraits> > : public std::tr1::true_type
{
};

#endif // _MSC_VER >= 1400

namespace std
{
    // Pre-declarations of container types so we don't actually have to include the relevant headers if not needed, speeding up compilation time.
    // These aren't necessary if you do actually include the headers.
    template<typename T, typename TAllocator> class vector;
    template<typename T, typename TAllocator> class list;
    template<typename T, typename TTraits, typename TAllocator> class set;
    template<typename TKey, typename TValue, typename TTraits, typename TAllocator> class map;
}

// Basic is_container template; specialize to derive from std::true_type for all desired container types
template<typename T> struct is_container : public std::false_type { };

// Mark vector as a container
template<typename T, typename TAllocator> struct is_container<std::vector<T, TAllocator> > : public std::true_type { };

// Mark list as a container
template<typename T, typename TAllocator> struct is_container<std::list<T, TAllocator> > : public std::true_type { };

// Mark set as a container
template<typename T, typename TTraits, typename TAllocator> struct is_container<std::set<T, TTraits, TAllocator> > : public std::true_type { };

// Mark map as a container
template<typename TKey, typename TValue, typename TTraits, typename TAllocator> struct is_container<std::map<TKey, TValue, TTraits, TAllocator> > : public std::true_type { };

// Holds the delimiter values for a specific character type
template<typename TChar>
struct delimiters_values
{
    typedef TChar char_type;
    const TChar *prefix;
    const TChar *delimiter;
    const TChar *postfix;
};

// Defines the delimiter values for a specific container and character type
template<typename T, typename TChar>
struct delimiters
{
    static const delimiters_values<TChar> values; 
};

// Default delimiters
template<typename T> struct delimiters<T, char> { static const delimiters_values<char> values; };
template<typename T> const delimiters_values<char> delimiters<T, char>::values = { "{ ", ", ", " }" };
template<typename T> struct delimiters<T, wchar_t> { static const delimiters_values<wchar_t> values; };
template<typename T> const delimiters_values<wchar_t> delimiters<T, wchar_t>::values = { L"{ ", L", ", L" }" };

// Delimiters for set
template<typename T, typename TTraits, typename TAllocator> struct delimiters<std::set<T, TTraits, TAllocator>, char> { static const delimiters_values<char> values; };
template<typename T, typename TTraits, typename TAllocator> const delimiters_values<char> delimiters<std::set<T, TTraits, TAllocator>, char>::values = { "[ ", ", ", " ]" };
template<typename T, typename TTraits, typename TAllocator> struct delimiters<std::set<T, TTraits, TAllocator>, wchar_t> { static const delimiters_values<wchar_t> values; };
template<typename T, typename TTraits, typename TAllocator> const delimiters_values<wchar_t> delimiters<std::set<T, TTraits, TAllocator>, wchar_t>::values = { L"[ ", L", ", L" ]" };

// Delimiters for pair
template<typename T1, typename T2> struct delimiters<std::pair<T1, T2>, char> { static const delimiters_values<char> values; };
template<typename T1, typename T2> const delimiters_values<char> delimiters<std::pair<T1, T2>, char>::values = { "(", ", ", ")" };
template<typename T1, typename T2> struct delimiters<std::pair<T1, T2>, wchar_t> { static const delimiters_values<wchar_t> values; };
template<typename T1, typename T2> const delimiters_values<wchar_t> delimiters<std::pair<T1, T2>, wchar_t>::values = { L"(", L", ", L")" };

// Functor to print containers. You can use this directly if you want to specificy a non-default delimiters type.
template<typename T, typename TChar = char, typename TCharTraits = std::char_traits<TChar>, typename TDelimiters = delimiters<T, TChar> >
struct print_container_helper
{
    typedef TChar char_type;
    typedef TDelimiters delimiters_type;
    typedef std::basic_ostream<TChar, TCharTraits>& ostream_type;

    print_container_helper(const T &container)
        : _container(&container)
    {
    }

    void operator()(ostream_type &stream) const
    {
        if( delimiters_type::values.prefix != NULL )
            stream << delimiters_type::values.prefix;
        std::copy(_container->begin(), _container->end(), pretty_ostream_iterator<typename T::value_type, TChar, TCharTraits>(stream, delimiters_type::values.delimiter));
        if( delimiters_type::values.postfix != NULL )
            stream << delimiters_type::values.postfix;
    }
private:
    const T *_container;
};

// Prints a print_container_helper to the specified stream.
template<typename T, typename TChar, typename TCharTraits, typename TDelimiters>
std::basic_ostream<TChar, TCharTraits>& operator<<(std::basic_ostream<TChar, TCharTraits> &stream, const print_container_helper<T, TChar, TDelimiters> &helper)
{
    helper(stream);
    return stream;
}

// Prints a container to the stream using default delimiters
template<typename T, typename TChar, typename TCharTraits>
typename std::enable_if<is_container<T>::value, std::basic_ostream<TChar, TCharTraits>&>::type
    operator<<(std::basic_ostream<TChar, TCharTraits> &stream, const T &container)
{
    stream << print_container_helper<T, TChar, TCharTraits>(container);
    return stream;
}

// Prints a pair to the stream using delimiters from delimiters<std::pair<T1, T2>>.
template<typename T1, typename T2, typename TChar, typename TCharTraits>
std::basic_ostream<TChar, TCharTraits>& operator<<(std::basic_ostream<TChar, TCharTraits> &stream, const std::pair<T1, T2> &value)
{
    if( delimiters<std::pair<T1, T2>, TChar>::values.prefix != NULL )
        stream << delimiters<std::pair<T1, T2>, TChar>::values.prefix;

    stream << value.first;

    if( delimiters<std::pair<T1, T2>, TChar>::values.delimiter != NULL )
        stream << delimiters<std::pair<T1, T2>, TChar>::values.delimiter;

    stream << value.second;

    if( delimiters<std::pair<T1, T2>, TChar>::values.postfix != NULL )
        stream << delimiters<std::pair<T1, T2>, TChar>::values.postfix;
    return stream;    
}

// Used by the sample below to generate some values
struct fibonacci
{
    fibonacci() : f1(0), f2(1) { }
    int operator()()
    {
        int r = f1 + f2;
        f1 = f2;
        f2 = r;
        return f1;
    }
private:
    int f1;
    int f2;
};

int main()
{
    std::vector<int> v;
    std::generate_n(std::back_inserter(v), 10, fibonacci());

    std::cout << v << std::endl;

    // Example of using pretty_ostream_iterator directly
    std::generate_n(pretty_ostream_iterator<int>(std::cout, ";"), 20, fibonacci());
    std::cout << std::endl;
}

与Marcelo的版本一样,它使用了一个is_container类型的特征,必须为所有要支持的容器特殊化。也许可以使用trait来检查value_type、const_iterator、begin()/end(),但我不确定我是否会推荐这样做,因为它可能匹配那些符合这些标准但实际上不是容器的东西,比如std::basic_string。同样像Marcelo的版本一样,它使用可以专门化的模板来指定要使用的分隔符。

主要的区别是,我围绕pretty_ostream_iterator构建了我的版本,它的工作原理类似于std::ostream_iterator,但没有在最后一项后面打印分隔符。容器的格式化是由print_container_helper完成的,它可以直接用于打印不带is_container特征的容器,或指定不同的分隔符类型。

我还定义了is_container和分隔符,因此它将适用于具有非标准谓词或分配器的容器,以及char和wchar_t。操作符<<函数本身也被定义为同时使用char和wchar_t流。

最后,我使用了std::enable_if,它是c++0x的一部分,在Visual c++ 2010和g++ 4.3(需要-std=c++0x标志)和更高版本中可用。这样就不依赖于Boost。

在c++ 11中,基于范围的for循环可能是一个很好的解决方案:

vector<char> items = {'a','b','c'};
for (char n : items)
    cout << n << ' ';

输出:

a b c