因为在一般情况下，CPU以1字节作为基本单位分配内存，尽管一些CPU如MIPS使用4字节字。

但是vector以一种特殊的方式处理bool类型，vector<bool>为每个bool类型分配一个位。

即使最小大小可能是1字节，你可以在1字节上有8位布尔信息:

http://en.wikipedia.org/wiki/Bit_array

Julia语言有BitArray，我读过c++实现。

因为CPU不能寻址任何小于字节的东西。

bool can be one byte -- the smallest addressable size of CPU, or can be bigger. It's not unusual to have bool to be the size of int for performance purposes. If for specific purposes (say hardware simulation) you need a type with N bits, you can find a library for that (e.g. GBL library has BitSet<N> class). If you are concerned with size of bool (you probably have a big container,) then you can pack bits yourself, or use std::vector<bool> that will do it for you (be careful with the latter, as it doesn't satisfy container requirments).

考虑一下如何在模拟器级别实现这一点……

bool a[10] = {false};

bool &rbool = a[3];
bool *pbool = a + 3;

assert(pbool == &rbool);
rbool = true;
assert(*pbool);
*pbool = false;
assert(!rbool);

最简单的答案是;这是因为CPU以字节而不是位来寻址内存，按位的操作非常慢。

然而，在c++中可以使用位分配。对于位向量，有std::vector专门化，还有接受位大小条目的结构。