随机字符串生成器返回相同的字符串

我已经开发了一个随机字符串生成器，但它的行为并不像我所希望的那样。我的目标是能够运行两次，并生成两个不同的四字符随机字符串。但是，它只生成一个四个字符的随机字符串两次。

下面是代码和输出示例:

private string RandomString(int size)
{
    StringBuilder builder = new StringBuilder();
    Random random = new Random();
    char ch;
    for (int i = 0; i < size; i++)
    {
        ch = Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65)));                 
        builder.Append(ch);
    }

    return builder.ToString();
}

// get 1st random string 
string Rand1 = RandomString(4);

// get 2nd random string 
string Rand2 = RandomString(4);

// create full rand string
string docNum = Rand1 + "-" + Rand2;

.．.输出如下:UNTE-UNTE .．.但它应该看起来像这个UNTE-FWNU

如何确保两个明显随机的字符串?

当前回答

我创建了这个方法。

效果很好。

public static string GeneratePassword(int Lenght, int NonAlphaNumericChars)
    {
        string allowedChars = "abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXYZ0123456789";
        string allowedNonAlphaNum = "!@#$%^&*()_-+=[{]};:<>|./?";
        Random rd = new Random();

        if (NonAlphaNumericChars > Lenght || Lenght <= 0 || NonAlphaNumericChars < 0)
            throw new ArgumentOutOfRangeException();

            char[] pass = new char[Lenght];
            int[] pos = new int[Lenght];
            int i = 0, j = 0, temp = 0;
            bool flag = false;

            //Random the position values of the pos array for the string Pass
            while (i < Lenght - 1)
            {
                j = 0;
                flag = false;
                temp = rd.Next(0, Lenght);
                for (j = 0; j < Lenght; j++)
                    if (temp == pos[j])
                    {
                        flag = true;
                        j = Lenght;
                    }

                if (!flag)
                {
                    pos[i] = temp;
                    i++;
                }
            }

            //Random the AlphaNumericChars
            for (i = 0; i < Lenght - NonAlphaNumericChars; i++)
                pass[i] = allowedChars[rd.Next(0, allowedChars.Length)];

            //Random the NonAlphaNumericChars
            for (i = Lenght - NonAlphaNumericChars; i < Lenght; i++)
                pass[i] = allowedNonAlphaNum[rd.Next(0, allowedNonAlphaNum.Length)];

            //Set the sorted array values by the pos array for the rigth posistion
            char[] sorted = new char[Lenght];
            for (i = 0; i < Lenght; i++)
                sorted[i] = pass[pos[i]];

            string Pass = new String(sorted);

            return Pass;
    }

2012-05-15 12:04:56

其他回答

这是另一个基于guid的想法。我在Visual Studio性能测试中使用它来生成只包含字母数字字符的随机字符串。

public string GenerateRandomString(int stringLength)
{
    Random rnd = new Random();
    Guid guid;
    String randomString = string.Empty;

    int numberOfGuidsRequired = (int)Math.Ceiling((double)stringLength / 32d);
    for (int i = 0; i < numberOfGuidsRequired; i++)
    {
        guid = Guid.NewGuid();
        randomString += guid.ToString().Replace("-", "");
    }

    return randomString.Substring(0, stringLength);
}

2012-06-19 10:48:55

我发现这更有帮助，因为它是一个扩展，它允许您选择代码的源代码。

static string
    numbers = "0123456789",
    letters = "abcdefghijklmnopqrstvwxyz",
    lettersUp = letters.ToUpper(),
    codeAll = numbers + letters + lettersUp;

static Random m_rand = new Random();

public static string GenerateCode(this int size)
{
    return size.GenerateCode(CodeGeneratorType.All);
}

public static string GenerateCode(this int size, CodeGeneratorType type)
{
    string source;

    if (type == CodeGeneratorType.All)
    {
        source = codeAll;
    }
    else
    {
        StringBuilder sourceBuilder = new StringBuilder();
        if ((type & CodeGeneratorType.Letters) == CodeGeneratorType.Numbers)
            sourceBuilder.Append(numbers);
        if ((type & CodeGeneratorType.Letters) == CodeGeneratorType.Letters)
            sourceBuilder.Append(letters);
        if ((type & CodeGeneratorType.Letters) == CodeGeneratorType.LettersUpperCase)
            sourceBuilder.Append(lettersUp);

        source = sourceBuilder.ToString();
    }

    return size.GenerateCode(source);
}

public static string GenerateCode(this int size, string source)
{
    StringBuilder code = new StringBuilder();
    int maxIndex = source.Length-1;
    for (int i = 0; i < size; i++)
    {

        code.Append(source[Convert.ToInt32(Math.Round(m_rand.NextDouble() * maxIndex))]);
    }

    return code.ToString();
}

public enum CodeGeneratorType { Numbers = 1, Letters = 2, LettersUpperCase = 4, All = 16 };

希望这能有所帮助。

2013-04-07 18:22:17

我想也许这也是可以接受的和简单的。

Guid.NewGuid().ToString()

2013-10-29 07:34:27

我创建了这个方法。

效果很好。

public static string GeneratePassword(int Lenght, int NonAlphaNumericChars)
    {
        string allowedChars = "abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXYZ0123456789";
        string allowedNonAlphaNum = "!@#$%^&*()_-+=[{]};:<>|./?";
        Random rd = new Random();

        if (NonAlphaNumericChars > Lenght || Lenght <= 0 || NonAlphaNumericChars < 0)
            throw new ArgumentOutOfRangeException();

            char[] pass = new char[Lenght];
            int[] pos = new int[Lenght];
            int i = 0, j = 0, temp = 0;
            bool flag = false;

            //Random the position values of the pos array for the string Pass
            while (i < Lenght - 1)
            {
                j = 0;
                flag = false;
                temp = rd.Next(0, Lenght);
                for (j = 0; j < Lenght; j++)
                    if (temp == pos[j])
                    {
                        flag = true;
                        j = Lenght;
                    }

                if (!flag)
                {
                    pos[i] = temp;
                    i++;
                }
            }

            //Random the AlphaNumericChars
            for (i = 0; i < Lenght - NonAlphaNumericChars; i++)
                pass[i] = allowedChars[rd.Next(0, allowedChars.Length)];

            //Random the NonAlphaNumericChars
            for (i = Lenght - NonAlphaNumericChars; i < Lenght; i++)
                pass[i] = allowedNonAlphaNum[rd.Next(0, allowedNonAlphaNum.Length)];

            //Set the sorted array values by the pos array for the rigth posistion
            char[] sorted = new char[Lenght];
            for (i = 0; i < Lenght; i++)
                sorted[i] = pass[pos[i]];

            string Pass = new String(sorted);

            return Pass;
    }

2012-05-15 12:04:56

结合“推送码”的答案和使用随机生成器种子的答案。我需要它来创造一系列伪可读的“单词”。

private int RandomNumber(int min, int max, int seed=0)
{
    Random random = new Random((int)DateTime.Now.Ticks + seed);
    return random.Next(min, max);
}

2011-09-23 07:18:07

随机字符串生成器返回相同的字符串

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