我想在不退出的情况下捕获和记录异常,例如,
try:
do_stuff()
except Exception as err:
print(Exception, err)
# I want to print the entire traceback here,
# not just the exception name and details
我想打印与抛出异常时打印的完全相同的输出,而不使用try/,只是拦截异常,并且我不希望它退出程序。
我想在不退出的情况下捕获和记录异常,例如,
try:
do_stuff()
except Exception as err:
print(Exception, err)
# I want to print the entire traceback here,
# not just the exception name and details
我想打印与抛出异常时打印的完全相同的输出,而不使用try/,只是拦截异常,并且我不希望它退出程序。
当前回答
Python 3解决方案
stacktrace_helper.py:
from linecache import getline
import sys
import traceback
def get_stack_trace():
exc_type, exc_value, exc_tb = sys.exc_info()
trace = traceback.format_stack()
trace = list(filter(lambda x: ("\\lib\\" not in x and "/lib/" not in x and "stacktrace_helper.py" not in x), trace))
ex_type = exc_type.__name__
ex_line = exc_tb.tb_lineno
ex_file = exc_tb.tb_frame.f_code.co_filename
ex_message = str(exc_value)
line_code = ""
try:
line_code = getline(ex_file, ex_line).strip()
except:
pass
trace.insert(
0, f'File "{ex_file}", line {ex_line}, line_code: {line_code} , ex: {ex_type} {ex_message}',
)
return trace
def get_stack_trace_str(msg: str = ""):
trace = list(get_stack_trace())
trace_str = "\n".join(list(map(str, trace)))
trace_str = msg + "\n" + trace_str
return trace_str
其他回答
您需要将try/except放在可能发生错误的最内层循环中,即。
for i in something:
for j in somethingelse:
for k in whatever:
try:
something_complex(i, j, k)
except Exception, e:
print e
try:
something_less_complex(i, j)
except Exception, e:
print e
... 等等
换句话说,您需要将可能在try/中失败的语句包装在尽可能具体的内部循环中。
traceback.format_exception (exception_object)
如果你只有异常对象,你可以从Python 3中的任何代码点获得字符串形式的回溯:
import traceback
''.join(traceback.format_exception(None, exc_obj, exc_obj.__traceback__))
完整的例子:
#!/usr/bin/env python3
import traceback
def f():
g()
def g():
raise Exception('asdf')
try:
g()
except Exception as e:
exc_obj = e
tb_str = ''.join(traceback.format_exception(None, exc_obj, exc_obj.__traceback__))
print(tb_str)
输出:
Traceback (most recent call last):
File "./main.py", line 12, in <module>
g()
File "./main.py", line 9, in g
raise Exception('asdf')
Exception: asdf
文档:https://docs.python.org/3.9/library/traceback.html traceback.format_exception
请参见:从异常对象中提取回溯信息
在Python 3.9中测试
您需要traceback模块。它将允许您像Python通常那样打印堆栈转储。特别是,print_last函数将打印最后一个异常和堆栈跟踪。
Python 3解决方案
stacktrace_helper.py:
from linecache import getline
import sys
import traceback
def get_stack_trace():
exc_type, exc_value, exc_tb = sys.exc_info()
trace = traceback.format_stack()
trace = list(filter(lambda x: ("\\lib\\" not in x and "/lib/" not in x and "stacktrace_helper.py" not in x), trace))
ex_type = exc_type.__name__
ex_line = exc_tb.tb_lineno
ex_file = exc_tb.tb_frame.f_code.co_filename
ex_message = str(exc_value)
line_code = ""
try:
line_code = getline(ex_file, ex_line).strip()
except:
pass
trace.insert(
0, f'File "{ex_file}", line {ex_line}, line_code: {line_code} , ex: {ex_type} {ex_message}',
)
return trace
def get_stack_trace_str(msg: str = ""):
trace = list(get_stack_trace())
trace_str = "\n".join(list(map(str, trace)))
trace_str = msg + "\n" + trace_str
return trace_str
Traceback.format_exc()或sys.exc_info()将产生更多信息,如果这是你想要的。
import traceback
import sys
try:
do_stuff()
except Exception:
print(traceback.format_exc())
# or
print(sys.exc_info()[2])