我可以用printf打印十六进制或八进制数字。是否有格式标签打印为二进制或任意基数?

我正在运行gcc。

printf("%d %x %o\n", 10, 10, 10); //prints "10 A 12\n"
printf("%b\n", 10); // prints "%b\n"

当前回答

void
print_binary(unsigned int n)
{
    unsigned int mask = 0;
    /* this grotesque hack creates a bit pattern 1000... */
    /* regardless of the size of an unsigned int */
    mask = ~mask ^ (~mask >> 1);

    for(; mask != 0; mask >>= 1) {
        putchar((n & mask) ? '1' : '0');
    }

}

其他回答

做一个函数并调用它

display_binary(int n)
{
    long int arr[32];
    int arr_counter=0;
    while(n>=1)
    {
        arr[arr_counter++]=n%2;
        n/=2;
    }
    for(int i=arr_counter-1;i>=0;i--)
    {
        printf("%d",arr[i]);
    }
}
void print_ulong_bin(const unsigned long * const var, int bits) {
        int i;

        #if defined(__LP64__) || defined(_LP64)
                if( (bits > 64) || (bits <= 0) )
        #else
                if( (bits > 32) || (bits <= 0) )
        #endif
                return;

        for(i = 0; i < bits; i++) { 
                printf("%lu", (*var >> (bits - 1 - i)) & 0x01);
        }
}

应该工作-未经测试。

根据@William Whyte的回答,这是一个提供int8、16,32和64版本的宏,重用int8宏以避免重复。

/* --- PRINTF_BYTE_TO_BINARY macro's --- */
#define PRINTF_BINARY_PATTERN_INT8 "%c%c%c%c%c%c%c%c"
#define PRINTF_BYTE_TO_BINARY_INT8(i)    \
    (((i) & 0x80ll) ? '1' : '0'), \
    (((i) & 0x40ll) ? '1' : '0'), \
    (((i) & 0x20ll) ? '1' : '0'), \
    (((i) & 0x10ll) ? '1' : '0'), \
    (((i) & 0x08ll) ? '1' : '0'), \
    (((i) & 0x04ll) ? '1' : '0'), \
    (((i) & 0x02ll) ? '1' : '0'), \
    (((i) & 0x01ll) ? '1' : '0')

#define PRINTF_BINARY_PATTERN_INT16 \
    PRINTF_BINARY_PATTERN_INT8              PRINTF_BINARY_PATTERN_INT8
#define PRINTF_BYTE_TO_BINARY_INT16(i) \
    PRINTF_BYTE_TO_BINARY_INT8((i) >> 8),   PRINTF_BYTE_TO_BINARY_INT8(i)
#define PRINTF_BINARY_PATTERN_INT32 \
    PRINTF_BINARY_PATTERN_INT16             PRINTF_BINARY_PATTERN_INT16
#define PRINTF_BYTE_TO_BINARY_INT32(i) \
    PRINTF_BYTE_TO_BINARY_INT16((i) >> 16), PRINTF_BYTE_TO_BINARY_INT16(i)
#define PRINTF_BINARY_PATTERN_INT64    \
    PRINTF_BINARY_PATTERN_INT32             PRINTF_BINARY_PATTERN_INT32
#define PRINTF_BYTE_TO_BINARY_INT64(i) \
    PRINTF_BYTE_TO_BINARY_INT32((i) >> 32), PRINTF_BYTE_TO_BINARY_INT32(i)
/* --- end macros --- */

#include <stdio.h>
int main() {
    long long int flag = 1648646756487983144ll;
    printf("My Flag "
           PRINTF_BINARY_PATTERN_INT64 "\n",
           PRINTF_BYTE_TO_BINARY_INT64(flag));
    return 0;
}

这个输出:

My Flag 0001011011100001001010110111110101111000100100001111000000101000

为了可读性,你可能需要为eg添加分隔符:

My Flag 00010110,11100001,00101011,01111101,01111000,10010000,11110000,00101000
void DisplayBinary(int n)
{
    int arr[8];
    int top =-1;
    while (n)
    {
        if (n & 1)
            arr[++top] = 1;
        else
            arr[++top] = 0;

        n >>= 1;
    }
    for (int i = top ; i > -1;i--)
    {
        printf("%d",arr[i]);
    }
    printf("\n");
}
const char* byte_to_binary(int x)
{
    static char b[sizeof(int)*8+1] = {0};
    int y;
    long long z;

    for (z = 1LL<<sizeof(int)*8-1, y = 0; z > 0; z >>= 1, y++) {
        b[y] = (((x & z) == z) ? '1' : '0');
    }
    b[y] = 0;

    return b;
}