下面是一个没有授权的例子:

tf1.addTarget(tf2, action: #selector(becomeFirstResponder), for: .editingDidEndOnExit)
tf2.addTarget(tf3, action: #selector(becomeFirstResponder), for: .editingDidEndOnExit)

ObjC:

[tf1 addTarget:tf2 action:@selector(becomeFirstResponder) forControlEvents:UIControlEventEditingDidEndOnExit];
[tf2 addTarget:tf3 action:@selector(becomeFirstResponder) forControlEvents:UIControlEventEditingDidEndOnExit];

使用UIControlEventEditingDidEndOnExit UITextField动作工作(大部分是未知的)。

您还可以很容易地将其连接到故事板中，因此不需要委托或代码。

编辑:实际上我不知道如何在故事板中连接这个。becomeFirstResponder似乎不是这个control-event的一个提供的动作，这是一个遗憾。尽管如此，你可以将所有的文本字段连接到你的ViewController中的一个动作，然后决定哪个textField成为基于发送者的firstresponder(虽然它不像上面的编程解决方案那么优雅，所以IMO用viewDidLoad中的上述代码来做)。

这是一个简单的解决方案在swift，没有标签使用，没有故事板技巧…

只需使用这个扩展:

extension UITextField{

    func nextTextFieldField() -> UITextField?{
        //field to return
        var returnField : UITextField?
        if self.superview != nil{
            //for each view in superview
            for (_, view) in self.superview!.subviews.enumerate(){
                //if subview is a text's field
                if view.isKindOfClass(UITextField){
                    //cast curent view as text field
                    let currentTextField = view as! UITextField
                    //if text field is after the current one
                    if currentTextField.frame.origin.y > self.frame.origin.y{
                        //if there is no text field to return already
                        if returnField == nil {
                            //set as default return
                            returnField = currentTextField
                        }
                            //else if this this less far than the other
                        else if currentTextField.frame.origin.y < returnField!.frame.origin.y{
                            //this is the field to return
                            returnField = currentTextField
                        }
                    }
                }
            }
        }
        //end of the mdethod
        return returnField
    }

}

并调用它像这样(例如)与你的textfield委托:

func textFieldShouldReturn(textField: UITextField) -> Bool {
    textField.resignFirstResponder()
    textField.nextTextFieldField()?.becomeFirstResponder()
    return true
}

我更喜欢:

@interface MyViewController : UIViewController
@property (nonatomic, retain) IBOutletCollection(UIView) NSArray *inputFields;
@end

在NIB文件中，我以所需的顺序将textFields钩子到这个inputFields数组中。之后，我做了一个简单的UITextField的索引测试，报告用户点击返回:

// for UITextField
-(BOOL)textFieldShouldReturn:(UITextField*)textField {
    NSUInteger index = [_inputFields indexOfObject:textField];
    index++;
    if (index < _inputFields.count) {
        UIView *v = [_inputFields objectAtIndex:index];
        [v becomeFirstResponder];
    }
    return NO;
}

// for UITextView
-(BOOL)textView:(UITextView*)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString*)text {
    if ([@"\n" isEqualToString:text]) {
        NSUInteger index = [_inputFields indexOfObject:textView];
        index++;
        if (index < _inputFields.count) {
            UIView *v = [_inputFields objectAtIndex:index];
            [v becomeFirstResponder];
        } else {
            [self.view endEditing:YES];
        }
        return NO;
    }
    return YES;
}

我喜欢Anth0和Answerbot已经提出的面向对象解决方案。然而，我正在开发一个快速而小型的POC，所以我不想让子类和类别使事情变得混乱。

另一个简单的解决方案是创建一个字段的NSArray，并在按下next时查找下一个字段。不是面向对象的解决方案，而是快速、简单且易于实现。此外，您可以一目了然地查看和修改排序。

下面是我的代码(基于这个线程中的其他答案):

@property (nonatomic) NSArray *fieldArray;

- (void)viewDidLoad {
    [super viewDidLoad];

    fieldArray = [NSArray arrayWithObjects: firstField, secondField, thirdField, nil];
}

- (BOOL) textFieldShouldReturn:(UITextField *) textField {
    BOOL didResign = [textField resignFirstResponder];
    if (!didResign) return NO;

    NSUInteger index = [self.fieldArray indexOfObject:textField];
    if (index == NSNotFound || index + 1 == fieldArray.count) return NO;

    id nextField = [fieldArray objectAtIndex:index + 1];
    activeField = nextField;
    [nextField becomeFirstResponder];

    return NO;
}

I always return NO because I don't want a line break inserted. Just thought I'd point that out since when I returned YES it would automatically exit the subsequent fields or insert a line break in my TextView. It took me a bit of time to figure that out. activeField keeps track of the active field in case scrolling is necessary to unobscure the field from the keyboard. If you have similar code, make sure you assign the activeField before changing the first responder. Changing first responder is immediate and will fire the KeyboardWasShown event immediately.

这是一个老帖子，但有一个很高的页面排名，所以我将附和我的解决方案。

我有一个类似的问题，最终创建了UIToolbar的子类来管理动态tableView中的下一个/前一个/完成功能:https://github.com/jday001/DataEntryToolbar

您将工具栏设置为文本字段的inputAccessoryView，并将它们添加到它的字典中。这允许您向前和向后循环浏览它们，即使是动态内容。有委托方法，如果你想触发你自己的功能时textField导航发生，但你不必处理管理任何标签或第一个响应器状态。

在GitHub链接中有代码片段和示例应用程序，以帮助实现细节。您需要自己的数据模型来跟踪字段中的值。

if (cell == nil)
{
    cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:cellIdentifier];
    txt_Input = [[ UITextField alloc] initWithFrame:CGRectMake(0, 10, 150, 30)];
    txt_Input.tag = indexPath.row+1;
    [self.array_Textfields addObject:txt_Input]; // Initialize mutable array in ViewDidLoad
}

-(BOOL)textFieldShouldReturn:(UITextField *)textField
{

    int tag = ( int) textField.tag ;
    UITextField * txt = [  self.array_Textfields objectAtIndex:tag ] ;
    [ txt becomeFirstResponder] ;
    return YES ;
}