在Mac OS X的Cocoa中，你有下一个响应器链，在那里你可以询问文本字段下一个控件应该有焦点。这就是在文本字段之间进行标签操作的原因。但由于iOS设备没有键盘，只有触摸，所以这一概念没有在Cocoa touch的过渡中幸存下来。

这很容易做到，只要有两个假设:

所有“tabbable”UITextFields都在同一个父视图上。 它们的“制表符顺序”由tag属性定义。

假设你可以重写textFieldShouldReturn:如下:

-(BOOL)textFieldShouldReturn:(UITextField*)textField
{
  NSInteger nextTag = textField.tag + 1;
  // Try to find next responder
  UIResponder* nextResponder = [textField.superview viewWithTag:nextTag];
  if (nextResponder) {
    // Found next responder, so set it.
    [nextResponder becomeFirstResponder];
  } else {
    // Not found, so remove keyboard.
    [textField resignFirstResponder];
  }
  return NO; // We do not want UITextField to insert line-breaks.
}

添加更多的代码，也可以忽略这些假设。

斯威夫特4.0

 func textFieldShouldReturn(_ textField: UITextField) -> Bool {
    let nextTag = textField.tag + 1
    // Try to find next responder
    let nextResponder = textField.superview?.viewWithTag(nextTag) as UIResponder!

    if nextResponder != nil {
        // Found next responder, so set it
        nextResponder?.becomeFirstResponder()
    } else {
        // Not found, so remove keyboard
        textField.resignFirstResponder()
    }

    return false
}

如果文本字段的superview是一个UITableViewCell那么下一个responder将是

let nextResponder = textField.superview?.superview?.superview?.viewWithTag(nextTag) as UIResponder!

当按下“Done”按钮时，一个非常简单的方法是:

在头文件中创建一个新的IBAction

- (IBAction)textFieldDoneEditing:(id)sender;

在实现文件(。M文件)添加如下方法:

- (IBAction)textFieldDoneEditing:(id)sender 
{ 
  [sender resignFirstResponder];
}

然后，当你来链接IBAction到文本框-链接到'Did End On Exit'事件。

大家好，请看这个

- (void)nextPrevious:(id)sender
{

  UIView *responder = [self.view findFirstResponder];   

  if (nil == responder || ![responder isKindOfClass:[GroupTextField class]]) {
    return;
  }

  switch([(UISegmentedControl *)sender selectedSegmentIndex]) {
    case 0:
      // previous
      if (nil != ((GroupTextField *)responder).previousControl) {
        [((GroupTextField *)responder).previousControl becomeFirstResponder];
        DebugLog(@"currentControl: %i previousControl: %i",((GroupTextField *)responder).tag,((GroupTextField *)responder).previousControl.tag);
      }
      break;
    case 1:
      // next
      if (nil != ((GroupTextField *)responder).nextControl) {
        [((GroupTextField *)responder).nextControl becomeFirstResponder];
        DebugLog(@"currentControl: %i nextControl: %i",((GroupTextField *)responder).tag,((GroupTextField *)responder).nextControl.tag);
      }     
      break;    
  }
}

我很惊讶，这里有这么多答案没有理解一个简单的概念:在应用程序中的控件中导航不是视图本身应该做的事情。控制器的工作是决定将哪个控件作为下一个第一响应器。

此外，大多数答案只适用于前进导航，但用户也可能想后退。

这就是我想到的。表单应该由视图控制器管理，视图控制器是响应器链的一部分。所以你可以完全自由地实现以下方法:

#pragma mark - Key Commands

- (NSArray *)keyCommands
{
    static NSArray *commands;

    static dispatch_once_t once;
    dispatch_once(&once, ^{
        UIKeyCommand *const forward = [UIKeyCommand keyCommandWithInput:@"\t" modifierFlags:0 action:@selector(tabForward:)];
        UIKeyCommand *const backward = [UIKeyCommand keyCommandWithInput:@"\t" modifierFlags:UIKeyModifierShift action:@selector(tabBackward:)];

        commands = @[forward, backward];
    });

    return commands;
}

- (void)tabForward:(UIKeyCommand *)command
{
    NSArray *const controls = self.controls;
    UIResponder *firstResponder = nil;

    for (UIResponder *const responder in controls) {
        if (firstResponder != nil && responder.canBecomeFirstResponder) {
            [responder becomeFirstResponder]; return;
        }
        else if (responder.isFirstResponder) {
            firstResponder = responder;
        }
    }

    [controls.firstObject becomeFirstResponder];
}

- (void)tabBackward:(UIKeyCommand *)command
{
    NSArray *const controls = self.controls;
    UIResponder *firstResponder = nil;

    for (UIResponder *const responder in controls.reverseObjectEnumerator) {
        if (firstResponder != nil && responder.canBecomeFirstResponder) {
            [responder becomeFirstResponder]; return;
        }
        else if (responder.isFirstResponder) {
            firstResponder = responder;
        }
    }

    [controls.lastObject becomeFirstResponder];
}

额外的逻辑滚动屏幕外的响应可见之前可能适用。

这种方法的另一个优点是，您不需要子类化您可能想要显示的所有类型的控件(如UITextFields)，而是可以在控制器级别管理逻辑，老实说，在控制器级别管理逻辑是正确的。

解决方案在Swift 3.1，连接你的文本字段IBOutlets设置你的文本字段委托在viewDidLoad，然后在textFieldShouldReturn导航你的动作

class YourViewController: UIViewController,UITextFieldDelegate {

        @IBOutlet weak var passwordTextField: UITextField!
        @IBOutlet weak var phoneTextField: UITextField!

        override func viewDidLoad() {
            super.viewDidLoad()
            self.passwordTextField.delegate = self
            self.phoneTextField.delegate = self
            // Set your return type
            self.phoneTextField.returnKeyType = .next
            self.passwordTextField.returnKeyType = .done
        }

        func textFieldShouldReturn(_ textField: UITextField) -> Bool{
            if textField == self.phoneTextField {
                self.passwordTextField.becomeFirstResponder()
            }else if textField == self.passwordTextField{
                // Call login api
                self.login()
            }
            return true
        }

    }

首先在xib中设置键盘返回键，否则你可以在viewdidload中编写代码:

passWord.returnKeyType = UIReturnKeyNext;

-(BOOL)textFieldShouldReturn:(UITextField *)textField
{
    if(textField == eMail) {
        [textField resignFirstResponder];
        [userName becomeFirstResponder];
    }
    if (textField==userName) {
        [textField resignFirstResponder];
        [passWord becomeFirstResponder];
    }
    if (textField==passWord) {
        [textField resignFirstResponder];
        [country becomeFirstResponder];
    }
    if (textField==country) {
        [textField resignFirstResponder];
    }
    return YES;
}