我如何通过iPhone键盘上的“下一步”按钮浏览所有的文本字段?
最后一个文本字段应该关闭键盘。
我已经设置了IB按钮(下一步/完成)，但现在我卡住了。
我实现了textFieldShouldReturn动作，但现在下一步和完成按钮关闭键盘。
当前回答
我已经实现了在视图层次结构中通过Responders导航的动态解决方案。其思想是，在整个层次结构中搜索下一个可能的响应器，根据需要向前或向后搜索。
UIView搜索扩展:
UIView+Cat.h
- (UIResponder *)getNextFirstResponder;
- (UIResponder *)getPreviousFirstResponder;
UIView+Cat.m
- (UIResponder *)getPreviousFirstResponder {
if (!self.superview) {
return nil;
}
BOOL hasreachedself = NO;
for (NSInteger i = self.superview.subviews.count-1; i >= 0; i--) {
UIView *v = [self.superview.subviews objectAtIndex:i];
if (v == self) {
hasreachedself = YES;
continue;
}
if (!hasreachedself) continue;
if ([v canBecomeFirstResponder] && !v.hidden) {
return v;
}
UIResponder *subResponder = [self getNextFirstResponderInView:v];
if (subResponder) {
return subResponder;
}
}
//search hierachicaly in superviews
return [self.superview getPreviousFirstResponder];
}
- (UIResponder *)getNextFirstResponder {
if (!self.superview) {
return nil;
}
BOOL hasreachedself = NO;
for (UIView *v in self.superview.subviews) {
if (v == self) {
hasreachedself = YES;
continue;
}
if (!hasreachedself) continue;
if ([v canBecomeFirstResponder] && !v.hidden) {
return v;
}
UIResponder *subResponder = [self getNextFirstResponderInView:v];
if (subResponder) {
return subResponder;
}
}
//search hierachicaly in superviews
return [self.superview getNextFirstResponder];
}
- (UIResponder *)getNextFirstResponderInView:(UIView *)view {
if ([view canBecomeFirstResponder] && !view.hidden) {
return view;
}
for (UIView *v in view.subviews) {
UIResponder *subResponder = [self getNextFirstResponderInView:v];
if (subResponder) {
return subResponder;
}
}
return nil;
}
用法:添加UIToolbar到UITextField / UITextView(在类别或子类中):
- (void)addToolbarInputAccessoryView {
UIToolbar *toolbar = [[UIToolbar alloc] initWithFrame:CGRectZero];
UIBarButtonItem *prev = [[UIBarButtonItem alloc] initWithImage:[UIImage systemImageNamed:@"chevron.up"] style:UIBarButtonItemStylePlain target:self action:@selector(moveToPreviousFirstResponder)];
UIBarButtonItem *next = [[UIBarButtonItem alloc] initWithImage:[UIImage systemImageNamed:@"chevron.down"] style:UIBarButtonItemStylePlain target:self action:@selector(moveToNextFirstResponder)];
UIBarButtonItem *space = [[UIBarButtonItem alloc] initWithBarButtonSystemItem:UIBarButtonSystemItemFlexibleSpace target:nil action:nil];
UIBarButtonItem *done = [[UIBarButtonItem alloc] initWithBarButtonSystemItem:UIBarButtonSystemItemDone target:self action:@selector(hideKeyboard)];
toolbar.items = @[prev, next, space, done];
if ([[UITextField appearance] keyboardAppearance] == UIKeyboardAppearanceDark) {
toolbar.barStyle = UIBarStyleBlack;
toolbar.translucent = YES;
[toolbar setBarTintColor:[UIColor blackColor]];
[toolbar setTintColor:[UIColor whiteColor]];
}
[toolbar sizeToFit];
self.inputAccessoryView = toolbar;
}
- (void)hideKeyboard {
[self resignFirstResponder];
}
- (void)moveToNextFirstResponder {
UIResponder *next = [self getNextFirstResponder];
if (next) {
[next becomeFirstResponder];
}
else {
[self resignFirstResponder];
}
}
- (void)moveToPreviousFirstResponder {
UIResponder *prev = [self getPreviousFirstResponder];
if (prev) {
[prev becomeFirstResponder];
}
else {
[self resignFirstResponder];
}
}
其他回答
我用Michael G. Emmons的答案已经有一年了，效果很好。我最近注意到，立即调用resignFirstResponder，然后立即调用becomeFirstResponder会导致键盘“故障”，消失，然后立即出现。我稍微改变了他的版本，跳过resignFirstResponder如果nextField是可用的。
- (BOOL)textFieldShouldReturn:(UITextField *)textField
{
if ([textField isKindOfClass:[NRTextField class]])
{
NRTextField *nText = (NRTextField*)textField;
if ([nText nextField] != nil){
dispatch_async(dispatch_get_main_queue(),
^ { [[nText nextField] becomeFirstResponder]; });
}
else{
[textField resignFirstResponder];
}
}
else{
[textField resignFirstResponder];
}
return true;
}
我很惊讶，这里有这么多答案没有理解一个简单的概念:在应用程序中的控件中导航不是视图本身应该做的事情。控制器的工作是决定将哪个控件作为下一个第一响应器。
此外，大多数答案只适用于前进导航，但用户也可能想后退。
这就是我想到的。表单应该由视图控制器管理，视图控制器是响应器链的一部分。所以你可以完全自由地实现以下方法:
#pragma mark - Key Commands
- (NSArray *)keyCommands
{
static NSArray *commands;
static dispatch_once_t once;
dispatch_once(&once, ^{
UIKeyCommand *const forward = [UIKeyCommand keyCommandWithInput:@"\t" modifierFlags:0 action:@selector(tabForward:)];
UIKeyCommand *const backward = [UIKeyCommand keyCommandWithInput:@"\t" modifierFlags:UIKeyModifierShift action:@selector(tabBackward:)];
commands = @[forward, backward];
});
return commands;
}
- (void)tabForward:(UIKeyCommand *)command
{
NSArray *const controls = self.controls;
UIResponder *firstResponder = nil;
for (UIResponder *const responder in controls) {
if (firstResponder != nil && responder.canBecomeFirstResponder) {
[responder becomeFirstResponder]; return;
}
else if (responder.isFirstResponder) {
firstResponder = responder;
}
}
[controls.firstObject becomeFirstResponder];
}
- (void)tabBackward:(UIKeyCommand *)command
{
NSArray *const controls = self.controls;
UIResponder *firstResponder = nil;
for (UIResponder *const responder in controls.reverseObjectEnumerator) {
if (firstResponder != nil && responder.canBecomeFirstResponder) {
[responder becomeFirstResponder]; return;
}
else if (responder.isFirstResponder) {
firstResponder = responder;
}
}
[controls.lastObject becomeFirstResponder];
}
额外的逻辑滚动屏幕外的响应可见之前可能适用。
这种方法的另一个优点是，您不需要子类化您可能想要显示的所有类型的控件(如UITextFields)，而是可以在控制器级别管理逻辑，老实说，在控制器级别管理逻辑是正确的。
Swift 3解决方案，使用UITextField的有序数组
func nextTextField() {
let textFields = // Your textfields array
for i in 0 ..< textFields.count{
if let textfield = textFields[i], textfield.isFirstResponder{
textfield.resignFirstResponder()
if i+1 < textFields.count, let nextextfield = textFields[i+1]{
nextextfield.becomeFirstResponder()
return
}
}
}
}
下面是一个swift3版本的Anth0的答案。我把它贴在这里，以帮助任何想要利用他的伟大答案的敏捷开发人员!当您设置关联对象时，我擅自添加了一个返回键类型“Next”。
extension UITextField {
@nonobjc static var NextHashKey: UniChar = 0
var nextTextField: UITextField? {
get {
return objc_getAssociatedObject(self,
&UITextField.NextHashKey) as? UITextField
}
set(next) {
self.returnKeyType = UIReturnKeyType.next
objc_setAssociatedObject(self,
&UITextField.NextHashKey,next,.OBJC_ASSOCIATION_RETAIN_NONATOMIC)
}
}
}
下面是另一个扩展，它显示了使用上述代码循环遍历UITextFields列表的可能性。
extension UIViewController: UITextFieldDelegate {
public func textFieldShouldReturn(_ textField: UITextField) -> Bool {
guard let next = textField.nextTextField else {
textField.resignFirstResponder()
return true
}
next.becomeFirstResponder()
return false
}
}
然后在你的ViewController或者其他地方，你可以像这样设置你的文本框。
@IBOutlet fileprivate weak var textfield1: UITextField!
@IBOutlet fileprivate weak var textfield2: UITextField!
@IBOutlet fileprivate weak var textfield3: UITextField!
...
[textfield1, textfield2, textfield3].forEach{ $0?.delegate = self }
textfield1.nextTextField = textfield2
textfield2.nextTextField = textfield3
// We don't assign a nextTextField to textfield3 because we want
// textfield3 to be the last one and resignFirstResponder when
// the return button on the soft keyboard is tapped.
首先在xib中设置键盘返回键，否则你可以在viewdidload中编写代码:
passWord.returnKeyType = UIReturnKeyNext;
-(BOOL)textFieldShouldReturn:(UITextField *)textField
{
if(textField == eMail) {
[textField resignFirstResponder];
[userName becomeFirstResponder];
}
if (textField==userName) {
[textField resignFirstResponder];
[passWord becomeFirstResponder];
}
if (textField==passWord) {
[textField resignFirstResponder];
[country becomeFirstResponder];
}
if (textField==country) {
[textField resignFirstResponder];
}
return YES;
}
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