首先在xib中设置键盘返回键，否则你可以在viewdidload中编写代码:

passWord.returnKeyType = UIReturnKeyNext;

-(BOOL)textFieldShouldReturn:(UITextField *)textField
{
    if(textField == eMail) {
        [textField resignFirstResponder];
        [userName becomeFirstResponder];
    }
    if (textField==userName) {
        [textField resignFirstResponder];
        [passWord becomeFirstResponder];
    }
    if (textField==passWord) {
        [textField resignFirstResponder];
        [country becomeFirstResponder];
    }
    if (textField==country) {
        [textField resignFirstResponder];
    }
    return YES;
}

我已经添加到PeyloW的答案，以防你想实现一个previous/next按钮功能:

- (IBAction)moveThroughTextFields:(UIBarButtonItem *)sender 
{
    NSInteger nextTag;
    UITextView *currentTextField = [self.view findFirstResponderAndReturn];

    if (currentTextField != nil) {
        // I assigned tags to the buttons.  0 represent prev & 1 represents next
        if (sender.tag == 0) {
            nextTag = currentTextField.tag - 1;

        } else if (sender.tag == 1) {
            nextTag = currentTextField.tag + 1;
        }
    }
    // Try to find next responder
    UIResponder* nextResponder = [self.view viewWithTag:nextTag];
    if (nextResponder) {
        // Found next responder, so set it.
        // I added the resign here in case there's different keyboards in place.
        [currentTextField resignFirstResponder];
        [nextResponder becomeFirstResponder];
    } else {
        // Not found, so remove keyboard.
        [currentTextField resignFirstResponder];

    }
}

你像这样子类化UIView:

@implementation UIView (FindAndReturnFirstResponder)
- (UITextView *)findFirstResponderAndReturn
{
    for (UITextView *subView in self.subviews) {
        if (subView.isFirstResponder){
            return subView;
        }
    }
    return nil;
}
@end

我刚刚创建了新的Pod处理这些东西GNTextFieldsCollectionManager。它自动处理下一个/最后一个textField问题，非常容易使用:

[[GNTextFieldsCollectionManager alloc] initWithView:self.view];

抓取所有的文本字段排序出现在视图层次结构(或标签)，或者你可以指定自己的文本字段数组。

一种更安全、更直接的方式，假设:

文本字段委托被设置为你的视图控制器 所有文本字段都是同一视图的子视图 文本字段的标签按照你想要进行的顺序(例如，textField2. txt)。标签= 2,textField3。Tag = 3，等等) 当你点击键盘上的返回按钮时，就会移动到下一个文本字段(你可以将此更改为next, done等)。 您希望键盘在最后一个文本字段之后被取消

斯威夫特4.1:

extension ViewController: UITextFieldDelegate {
    func textFieldShouldReturn(_ textField: UITextField) -> Bool {
        let nextTag = textField.tag + 1
        guard let nextTextField = textField.superview?.viewWithTag(nextTag) else {
            textField.resignFirstResponder()
            return false
        }

    nextTextField.becomeFirstResponder()

    return false

    }
}

一个更加一致和健壮的方法是使用NextResponderTextField 你可以完全从接口构建器中配置它，而不需要设置委托或使用view.tag。

你所需要做的就是

将UITextField的类类型设置为NextResponderTextField 然后设置nextResponderField的出口指向下一个responder它可以是任何UITextField或任何UIResponder子类。它也可以是一个UIButton，库足够智能，只有当它被启用时才会触发按钮的TouchUpInside事件。

下面是运行中的库:

大家好，请看这个

- (void)nextPrevious:(id)sender
{

  UIView *responder = [self.view findFirstResponder];   

  if (nil == responder || ![responder isKindOfClass:[GroupTextField class]]) {
    return;
  }

  switch([(UISegmentedControl *)sender selectedSegmentIndex]) {
    case 0:
      // previous
      if (nil != ((GroupTextField *)responder).previousControl) {
        [((GroupTextField *)responder).previousControl becomeFirstResponder];
        DebugLog(@"currentControl: %i previousControl: %i",((GroupTextField *)responder).tag,((GroupTextField *)responder).previousControl.tag);
      }
      break;
    case 1:
      // next
      if (nil != ((GroupTextField *)responder).nextControl) {
        [((GroupTextField *)responder).nextControl becomeFirstResponder];
        DebugLog(@"currentControl: %i nextControl: %i",((GroupTextField *)responder).tag,((GroupTextField *)responder).nextControl.tag);
      }     
      break;    
  }
}