我用Michael G. Emmons的答案已经有一年了，效果很好。我最近注意到，立即调用resignFirstResponder，然后立即调用becomeFirstResponder会导致键盘“故障”，消失，然后立即出现。我稍微改变了他的版本，跳过resignFirstResponder如果nextField是可用的。

- (BOOL)textFieldShouldReturn:(UITextField *)textField
{ 

    if ([textField isKindOfClass:[NRTextField class]])
    {
        NRTextField *nText = (NRTextField*)textField;
        if ([nText nextField] != nil){
            dispatch_async(dispatch_get_main_queue(),
                           ^ { [[nText nextField] becomeFirstResponder]; });

        }
        else{
            [textField resignFirstResponder];
        }
    }
    else{
        [textField resignFirstResponder];
    }

    return true;

}

这是我对这个问题的解决方案。

为了解决这个问题(因为我讨厌依赖标签来做事情)，我决定向UITextField对象添加一个自定义属性。换句话说，我在UITextField上创建了一个这样的类别:

UITextField + Extended.h

@interface UITextField (Extended)

@property(retain, nonatomic)UITextField* nextTextField;

@end

UITextField +扩展。m

#import "UITextField+Extended.h"
#import <objc/runtime.h>

static char defaultHashKey;

@implementation UITextField (Extended)

- (UITextField*) nextTextField { 
    return objc_getAssociatedObject(self, &defaultHashKey); 
}

- (void) setNextTextField:(UITextField *)nextTextField{
    objc_setAssociatedObject(self, &defaultHashKey, nextTextField, OBJC_ASSOCIATION_RETAIN_NONATOMIC); 
}

@end

下面是我如何使用它:

UITextField *textField1 = ...init your textfield
UITextField *textField2 = ...init your textfield
UITextField *textField3 = ...init your textfield

textField1.nextTextField = textField2;
textField2.nextTextField = textField3;
textField3.nextTextField = nil;

实现textFieldShouldReturn方法:

- (BOOL)textFieldShouldReturn:(UITextField *)theTextField {

    UITextField *next = theTextField.nextTextField;
    if (next) {
        [next becomeFirstResponder];
    } else {
        [theTextField resignFirstResponder];
    }

    return NO; 
}

我现在有一个UITextField的链表，每一个都知道下一个是谁。

希望能有所帮助。

我尝试了很多代码，最后，这在Swift 3.0最新版[2017年3月]对我有效

ViewController类应该继承UITextFieldDelegate以使这段代码正常工作。

class ViewController: UIViewController,UITextFieldDelegate  

使用适当的标记号添加文本字段，该标记号用于根据分配给它的增量标记号将控件转移到适当的文本字段。

override func viewDidLoad() {
    userNameTextField.delegate = self
    userNameTextField.tag = 0
    userNameTextField.returnKeyType = UIReturnKeyType.next
    passwordTextField.delegate = self
    passwordTextField.tag = 1
    passwordTextField.returnKeyType = UIReturnKeyType.go
}

在上面的代码中，returnKeyType = UIReturnKeyType。下一个将使键垫返回键显示为下一个你也有其他选项加入/走等，根据你的应用程序改变值。

这个textFieldShouldReturn是一个UITextFieldDelegate控制的方法，在这里我们有下一个字段选择基于标签值的增量

func textFieldShouldReturn(_ textField: UITextField) -> Bool {
    if let nextField = textField.superview?.viewWithTag(textField.tag + 1) as? UITextField {
        nextField.becomeFirstResponder()
    } else {
        textField.resignFirstResponder()
        return true;
    }
    return false
 }

下面是一个swift3版本的Anth0的答案。我把它贴在这里，以帮助任何想要利用他的伟大答案的敏捷开发人员!当您设置关联对象时，我擅自添加了一个返回键类型“Next”。

extension UITextField {

  @nonobjc static var NextHashKey: UniChar = 0

  var nextTextField: UITextField? {
    get {
      return objc_getAssociatedObject(self, 
        &UITextField.NextHashKey) as? UITextField
    }
    set(next) {
     self.returnKeyType = UIReturnKeyType.next
     objc_setAssociatedObject(self,
      &UITextField.NextHashKey,next,.OBJC_ASSOCIATION_RETAIN_NONATOMIC)
    }
  }
}

下面是另一个扩展，它显示了使用上述代码循环遍历UITextFields列表的可能性。

extension UIViewController: UITextFieldDelegate {
 public func textFieldShouldReturn(_ textField: UITextField) -> Bool {
   guard let next = textField.nextTextField else {
     textField.resignFirstResponder()
     return true
   }

    next.becomeFirstResponder()
    return false
  }
}

然后在你的ViewController或者其他地方，你可以像这样设置你的文本框。

@IBOutlet fileprivate weak var textfield1: UITextField!
@IBOutlet fileprivate weak var textfield2: UITextField!
@IBOutlet fileprivate weak var textfield3: UITextField!

...

[textfield1, textfield2, textfield3].forEach{ $0?.delegate = self }

textfield1.nextTextField = textfield2
textfield2.nextTextField = textfield3
// We don't assign a nextTextField to textfield3 because we want 
// textfield3 to be the last one and resignFirstResponder when 
// the return button on the soft keyboard is tapped.

首先在xib中设置键盘返回键，否则你可以在viewdidload中编写代码:

passWord.returnKeyType = UIReturnKeyNext;

-(BOOL)textFieldShouldReturn:(UITextField *)textField
{
    if(textField == eMail) {
        [textField resignFirstResponder];
        [userName becomeFirstResponder];
    }
    if (textField==userName) {
        [textField resignFirstResponder];
        [passWord becomeFirstResponder];
    }
    if (textField==passWord) {
        [textField resignFirstResponder];
        [country becomeFirstResponder];
    }
    if (textField==country) {
        [textField resignFirstResponder];
    }
    return YES;
}

我已经添加到PeyloW的答案，以防你想实现一个previous/next按钮功能:

- (IBAction)moveThroughTextFields:(UIBarButtonItem *)sender 
{
    NSInteger nextTag;
    UITextView *currentTextField = [self.view findFirstResponderAndReturn];

    if (currentTextField != nil) {
        // I assigned tags to the buttons.  0 represent prev & 1 represents next
        if (sender.tag == 0) {
            nextTag = currentTextField.tag - 1;

        } else if (sender.tag == 1) {
            nextTag = currentTextField.tag + 1;
        }
    }
    // Try to find next responder
    UIResponder* nextResponder = [self.view viewWithTag:nextTag];
    if (nextResponder) {
        // Found next responder, so set it.
        // I added the resign here in case there's different keyboards in place.
        [currentTextField resignFirstResponder];
        [nextResponder becomeFirstResponder];
    } else {
        // Not found, so remove keyboard.
        [currentTextField resignFirstResponder];

    }
}

你像这样子类化UIView:

@implementation UIView (FindAndReturnFirstResponder)
- (UITextView *)findFirstResponderAndReturn
{
    for (UITextView *subView in self.subviews) {
        if (subView.isFirstResponder){
            return subView;
        }
    }
    return nil;
}
@end