我如何通过iPhone键盘上的“下一步”按钮浏览所有的文本字段?

最后一个文本字段应该关闭键盘。

我已经设置了IB按钮(下一步/完成),但现在我卡住了。

我实现了textFieldShouldReturn动作,但现在下一步和完成按钮关闭键盘。


当前回答

我已经添加到PeyloW的答案,以防你想实现一个previous/next按钮功能:

- (IBAction)moveThroughTextFields:(UIBarButtonItem *)sender 
{
    NSInteger nextTag;
    UITextView *currentTextField = [self.view findFirstResponderAndReturn];

    if (currentTextField != nil) {
        // I assigned tags to the buttons.  0 represent prev & 1 represents next
        if (sender.tag == 0) {
            nextTag = currentTextField.tag - 1;

        } else if (sender.tag == 1) {
            nextTag = currentTextField.tag + 1;
        }
    }
    // Try to find next responder
    UIResponder* nextResponder = [self.view viewWithTag:nextTag];
    if (nextResponder) {
        // Found next responder, so set it.
        // I added the resign here in case there's different keyboards in place.
        [currentTextField resignFirstResponder];
        [nextResponder becomeFirstResponder];
    } else {
        // Not found, so remove keyboard.
        [currentTextField resignFirstResponder];

    }
}

你像这样子类化UIView:

@implementation UIView (FindAndReturnFirstResponder)
- (UITextView *)findFirstResponderAndReturn
{
    for (UITextView *subView in self.subviews) {
        if (subView.isFirstResponder){
            return subView;
        }
    }
    return nil;
}
@end

其他回答

大家好,请看这个

- (void)nextPrevious:(id)sender
{

  UIView *responder = [self.view findFirstResponder];   

  if (nil == responder || ![responder isKindOfClass:[GroupTextField class]]) {
    return;
  }

  switch([(UISegmentedControl *)sender selectedSegmentIndex]) {
    case 0:
      // previous
      if (nil != ((GroupTextField *)responder).previousControl) {
        [((GroupTextField *)responder).previousControl becomeFirstResponder];
        DebugLog(@"currentControl: %i previousControl: %i",((GroupTextField *)responder).tag,((GroupTextField *)responder).previousControl.tag);
      }
      break;
    case 1:
      // next
      if (nil != ((GroupTextField *)responder).nextControl) {
        [((GroupTextField *)responder).nextControl becomeFirstResponder];
        DebugLog(@"currentControl: %i nextControl: %i",((GroupTextField *)responder).tag,((GroupTextField *)responder).nextControl.tag);
      }     
      break;    
  }
}

下面是一个没有授权的例子:

tf1.addTarget(tf2, action: #selector(becomeFirstResponder), for: .editingDidEndOnExit)
tf2.addTarget(tf3, action: #selector(becomeFirstResponder), for: .editingDidEndOnExit)

ObjC:

[tf1 addTarget:tf2 action:@selector(becomeFirstResponder) forControlEvents:UIControlEventEditingDidEndOnExit];
[tf2 addTarget:tf3 action:@selector(becomeFirstResponder) forControlEvents:UIControlEventEditingDidEndOnExit];

使用UIControlEventEditingDidEndOnExit UITextField动作工作(大部分是未知的)。

您还可以很容易地将其连接到故事板中,因此不需要委托或代码。

编辑:实际上我不知道如何在故事板中连接这个。becomeFirstResponder似乎不是这个control-event的一个提供的动作,这是一个遗憾。尽管如此,你可以将所有的文本字段连接到你的ViewController中的一个动作,然后决定哪个textField成为基于发送者的firstresponder(虽然它不像上面的编程解决方案那么优雅,所以IMO用viewDidLoad中的上述代码来做)。

这是我对这个问题的解决方案。

为了解决这个问题(因为我讨厌依赖标签来做事情),我决定向UITextField对象添加一个自定义属性。换句话说,我在UITextField上创建了一个这样的类别:

UITextField + Extended.h

@interface UITextField (Extended)

@property(retain, nonatomic)UITextField* nextTextField;

@end

UITextField +扩展。m

#import "UITextField+Extended.h"
#import <objc/runtime.h>

static char defaultHashKey;

@implementation UITextField (Extended)

- (UITextField*) nextTextField { 
    return objc_getAssociatedObject(self, &defaultHashKey); 
}

- (void) setNextTextField:(UITextField *)nextTextField{
    objc_setAssociatedObject(self, &defaultHashKey, nextTextField, OBJC_ASSOCIATION_RETAIN_NONATOMIC); 
}

@end

下面是我如何使用它:

UITextField *textField1 = ...init your textfield
UITextField *textField2 = ...init your textfield
UITextField *textField3 = ...init your textfield

textField1.nextTextField = textField2;
textField2.nextTextField = textField3;
textField3.nextTextField = nil;

实现textFieldShouldReturn方法:

- (BOOL)textFieldShouldReturn:(UITextField *)theTextField {

    UITextField *next = theTextField.nextTextField;
    if (next) {
        [next becomeFirstResponder];
    } else {
        [theTextField resignFirstResponder];
    }

    return NO; 
}

我现在有一个UITextField的链表,每一个都知道下一个是谁。

希望能有所帮助。

你可以使用IQKeyboardManager库来做到这一点。它处理所有的事情,你不需要任何额外的设置。IQKeyboardManager可以通过CocoaPods获得,要安装它,只需在Podfile中添加以下行:

pod 'IQKeyboardManager'

或 只需拖放IQKeyBoardManager目录从演示项目到您的项目。就是这样。 IQKeyBoardManager目录可以从https://github.com/hackiftekhar/IQKeyboardManager找到

 -(BOOL)textFieldShouldReturn:(UITextField *)textField
{
   [[self.view viewWithTag:textField.tag+1] becomeFirstResponder];
   return YES;
}