毫秒到持续时间，简单的方法是:

// To have leading zero digits in strings.
function pad(num, size) {
    var s = num + "";
    while (s.length < size) s = "0" + s;
    return s;
}

// ms to time/duration
msToDuration = function(ms){
    var seconds = ms / 1000;
    var hh = Math.floor(seconds / 3600),
    mm = Math.floor(seconds / 60) % 60,
    ss = Math.floor(seconds) % 60,
    mss = ms % 1000;
    return pad(hh,2)+':'+pad(mm,2)+':'+pad(ss,2)+'.'+pad(mss,3);
}

它将327577转换为00:05:27.577。

更新

另一种不同场景的方法:

toHHMMSS = function (n) {
    var sep = ':',
        n = parseFloat(n),
        sss = parseInt((n % 1)*1000),
        hh = parseInt(n / 3600);
    n %= 3600;
    var mm = parseInt(n / 60),
        ss = parseInt(n % 60);
    return pad(hh,2)+sep+pad(mm,2)+sep+pad(ss,2)+'.'+pad(sss,3);
    function pad(num, size) {
        var str = num + "";
        while (str.length < size) str = "0" + str;
        return str;
    }
}

toHHMMSS(6315.077) // Return 01:45:15.077

以下是2019年更新的一句话:

//your date
var someDate = new Date("Wed Jun 26 2019 09:38:02 GMT+0100") 

var result = `${String(someDate.getHours()).padStart(2,"0")}:${String(someDate.getMinutes()).padStart(2,"0")}:${String(someDate.getSeconds()).padStart(2,"0")}`

//result will be "09:38:02"

我推荐使用普通的javascript，使用Date对象。(要获得更简短的解决方案，请使用toTimeString，请参阅第二个代码片段。)

var seconds = 9999;
// multiply by 1000 because Date() requires miliseconds
var date = new Date(seconds * 1000);
var hh = date.getUTCHours();
var mm = date.getUTCMinutes();
var ss = date.getSeconds();
// If you were building a timestamp instead of a duration, you would uncomment the following line to get 12-hour (not 24) time
// if (hh > 12) {hh = hh % 12;}
// These lines ensure you have two-digits
if (hh < 10) {hh = "0"+hh;}
if (mm < 10) {mm = "0"+mm;}
if (ss < 10) {ss = "0"+ss;}
// This formats your string to HH:MM:SS
var t = hh+":"+mm+":"+ss;
document.write(t);

(当然，创建的Date对象将有一个与之关联的实际日期，但该数据是无关的，因此出于这些目的，您不必担心它。)

编辑(简短的解决方案):

使用toTimeString函数并对空白进行分割:

var seconds = 9999; // Some arbitrary value
var date = new Date(seconds * 1000); // multiply by 1000 because Date() requires miliseconds
var timeStr = date.toTimeString().split(' ')[0];

toTimeString给出'16:54:58 GMT-0800 (PST)'，对第一个空格进行分割给出'16:54:58'。

要获得格式为hh:MM:ss的时间部分，可以使用下面的正则表达式:

(上面有人在同一篇文章中提到了这一点，谢谢。)

var替换= new日期().toTimeString () .replace (/ . * (\ d {2}: \ d {2}: \ d{2})。* / " $ 1 "); console.log(替换)

function secondsToTime(secs)
{
    var hours = Math.floor(secs / (60 * 60));

    var divisor_for_minutes = secs % (60 * 60);
    var minutes = Math.floor(divisor_for_minutes / 60);

    var divisor_for_seconds = divisor_for_minutes % 60;
    var seconds = Math.ceil(divisor_for_seconds);

    if(hours >= 12)
    {
     var m= 'pm' ;
     }
     else
     {
         var m='am'
     }
     if(hours-12 >0)
     {
            var hrs = hours-12;
     }
     else if(hours-12 <0)
     {
            var hrs = hours;
     }
    var obj = {
        "h": hrs,
        "m": minutes,
        "s": seconds,
        "a":m
    };


    return obj;
}
var d = new Date();
var n = d.getHours();
var hms = d.getHours()+':'+d.getMinutes()+':'+d.getSeconds();   // your input string
var a = hms.split(':'); // split it at the colons

// minutes are worth 60 seconds. Hours are worth 60 minutes.
var seconds = (+a[0]) * 60 * 60 + (+a[1]) * 60 + (+a[2]); 




console.log(seconds);
console.log(secondsToTime(seconds))

https://jsfiddle.net/jithinksoft/9x6z4sdt/

正则表达式可以用来匹配Date对象的toString()方法返回的字符串中的时间子字符串，该字符串的格式如下:“Thu Jul 05 2012 02:45:12 GMT+0100 (GMT夏令时)”。请注意，此解决方案使用自epoch以来的时间:1970年1月1日午夜。这个解决方案可以是一行代码，不过将其拆分会更容易理解。

function secondsToTime(seconds) {
    const start = new Date(1970, 1, 1, 0, 0, 0, 0).getTime();
    const end = new Date(1970, 1, 1, 0, 0, parseInt(seconds), 0).getTime();
    const duration = end - start;

    return new Date(duration).toString().replace(/.*(\d{2}:\d{2}:\d{2}).*/, "$1");
}