这里有一个相当简单的解决方案，四舍五入到最近的秒!

var returnElapsedTime =函数(epoch) { //我们假设epoch以秒为单位 Var小时= epoch / 3600， 分钟=(小时% 1)* 60， 秒=(分钟% 1)* 60; 返回Math.floor(小时)+ ":" + Math.floor(分钟)+ ":" + Math.round(秒); ｝

主题的变奏。处理个位数秒的方式有点不同

seconds2time(0)  ->  "0s" 
seconds2time(59) -> "59s" 
seconds2time(60) -> "1:00" 
seconds2time(1000) -> "16:40" 
seconds2time(4000) -> "1:06:40"

function seconds2time (seconds) {
    var hours   = Math.floor(seconds / 3600);
    var minutes = Math.floor((seconds - (hours * 3600)) / 60);
    var seconds = seconds - (hours * 3600) - (minutes * 60);
    var time = "";

    if (hours != 0) {
      time = hours+":";
    }
    if (minutes != 0 || time !== "") {
      minutes = (minutes < 10 && time !== "") ? "0"+minutes : String(minutes);
      time += minutes+":";
    }
    if (time === "") {
      time = seconds+"s";
    }
    else {
      time += (seconds < 10) ? "0"+seconds : String(seconds);
    }
    return time;
}

我不喜欢在JavaScript中为标准数据类型添加属性，所以我建议这样做:

/**
 * Format a duration in seconds to a human readable format using the notion
 * "h+:mm:ss", e.g. "4:40:78". Negative durations are preceeded by "-".
 *
 * @param t Duration in seconds
 * @return The formatted duration string
 */
var readableDuration = (function() {

    // Each unit is an object with a suffix s and divisor d
    var units = [
        {s: '', d: 1}, // Seconds
        {s: ':', d: 60}, // Minutes
        {s: ':', d: 60}, // Hours
    ];

    // Closure function
    return function(t) {
        t = parseInt(t); // In order to use modulus
        var trunc, n = Math.abs(t), i, out = []; // out: list of strings to concat
        for (i = 0; i < units.length; i++) {
            n = Math.floor(n / units[i].d); // Total number of this unit
            // Truncate e.g. 26h to 2h using modulus with next unit divisor
            if (i+1 < units.length) // Tweak substr with two digits
                trunc = ('00'+ n % units[i+1].d).substr(-2, 2); // …if not final unit
            else
                trunc = n;
            out.unshift(''+ trunc + units[i].s); // Output
        }
        (t < 0) ? out.unshift('-') : null; // Handle negative durations
        return out.join('');
    };
})();

用法:

var str = readableDuration(3808); // "1:03:28"

我还创建了一个更通用的版本。主要的区别是它接受毫秒(这是JS中的标准时间单位)，而输出格式使用空格。

正则表达式可以用来匹配Date对象的toString()方法返回的字符串中的时间子字符串，该字符串的格式如下:“Thu Jul 05 2012 02:45:12 GMT+0100 (GMT夏令时)”。请注意，此解决方案使用自epoch以来的时间:1970年1月1日午夜。这个解决方案可以是一行代码，不过将其拆分会更容易理解。

function secondsToTime(seconds) {
    const start = new Date(1970, 1, 1, 0, 0, 0, 0).getTime();
    const end = new Date(1970, 1, 1, 0, 0, parseInt(seconds), 0).getTime();
    const duration = end - start;

    return new Date(duration).toString().replace(/.*(\d{2}:\d{2}:\d{2}).*/, "$1");
}

要获得格式为hh:MM:ss的时间部分，可以使用下面的正则表达式:

(上面有人在同一篇文章中提到了这一点，谢谢。)

var替换= new日期().toTimeString () .replace (/ . * (\ d {2}: \ d {2}: \ d{2})。* / " $ 1 "); console.log(替换)

secToHHMM(number: number) {
    debugger;
    let hours = Math.floor(number / 3600);
    let minutes = Math.floor((number - (hours * 3600)) / 60);
    let seconds = number - (hours * 3600) - (minutes * 60);
    let H, M, S;
    if (hours < 10) H = ("0" + hours);
    if (minutes < 10) M = ("0" + minutes);
    if (seconds < 10) S = ("0" + seconds);
    return (H || hours) + ':' + (M || minutes) + ':' + (S || seconds);
}