我进一步开发了志刚、木uri和固颈的溶液:

 #!/bin/bash

if test $# -lt 1 ; then
    echo >&2 "usage: kiltree pid (sig)"
    exit 1 ;
  fi ;

_pid=$1
_sig=${2:-TERM}

# echo >&2 "killtree($_pid) mypid = $$"
# ps axwwf | grep -6 "^[ ]*$_pid " >&2 ;

function _killtree () {
    local _children
    local _child
    local _success

    if test $1 -eq $2 ; then # this is killtree - don't commit suicide!
        echo >&2 "killtree can´t kill it´s own branch - some processes will survive." ; 
        return 1 ;
      fi ;
    # this avoids that children are spawned or disappear.
    kill -SIGSTOP $2 ;

    _children=$(ps -o pid --no-headers --ppid $2) ;        
    _success=0 
    for _child in ${_children}; do
        _killtree $1 ${_child} $3 ;
        _success=$(($_success+$?)) ;
      done ;

    if test $_success -eq 0 ; then
        kill -$3 $2
      fi ;
    # when a stopped process is killed, it will linger in the system until it is continued
    kill -SIGCONT $2
    test $_success -eq 0 ;
    return $?
    }

_killtree $$ $_pid $_sig

这个版本将避免杀死它的祖先进程——在以前的解决方案中，这会导致大量的子进程。

在确定子列表之前适当地停止进程，这样就不会创建或消失新的子列表。

停止的作业被杀死后，必须继续执行，才能从系统中消失。

谢谢你们的智慧。我的脚本在退出时留下了一些子进程，而否定提示使事情变得更容易。我写这个函数是为了在其他脚本中使用:

# kill my group's subprocesses:          killGroup
# kill also myself:                      killGroup -x
# kill another group's subprocesses:     killGroup N  
# kill that group all:                   killGroup -x N
# N: PID of the main process (= process group ID).

function killGroup () {
    local prid mainpid
    case $1 in
        -x) [ -n "$2" ] && kill -9 -$2 || kill -9 -$$ ;;
        "") mainpid=$$ ;;
         *) mainpid=$1 ;;
    esac
    prid=$(ps ax -o pid,pgid | grep $mainpid)
    prid=${prid//$mainpid/}
    kill -9 $prid 2>/dev/null
    return
}

欢呼。

如果你知道传递父进程的pid，下面这个shell脚本应该可以工作:

for child in $(ps -o pid,ppid -ax | \
   awk "{ if ( \$2 == $pid ) { print \$1 }}")
do
  echo "Killing child process $child because ppid = $pid"
  kill $child
done

下面是@zhigang的答案的一个变种，它没有AWK，只依赖于Bash的本地解析可能性:

function killtree {
  kill -STOP "$1"
  ps -e -o pid= -o ppid= | while read -r pid ppid
                           do
                             [[ $ppid = $1 ]] || continue
                             killtree "$pid"  || true # Skip over failures
                           done
  kill -CONT "$1"          
  kill -TERM "$1"
}

它在mac和Linux上都运行得很好。在您不能依赖于管理流程组的情况下——比如在编写测试必须在多个环境中构建的软件的脚本时——这种遍历树技术绝对是有用的。

ps -o pid= --ppid $PPID | xargs kill -9 

修改后的志刚回答:

#!/usr/bin/env bash
set -eu

killtree() {
    local pid
    for pid; do
        kill -stop $pid
        local cpid
        for cpid in $(pgrep -P $pid); do
            killtree $cpid
        done
        kill $pid
        kill -cont $pid
        wait $pid 2>/dev/null || true
   done
}

cpids() {
    local pid=$1 options=${2:-} space=${3:-}
    local cpid
    for cpid in $(pgrep -P $pid); do
        echo "$space$cpid"
        if [[ "${options/a/}" != "$options" ]]; then
            cpids $cpid "$options" "$space  "
        fi
    done
}

while true; do sleep 1; done &
cpid=$!
for i in $(seq 1 2); do
    cpids $$ a
    sleep 1
done
killtree $cpid
echo ---
cpids $$ a