从3.3开始，time.clock()已弃用，建议使用time.process_time()或time.perf_counter()。

在2.7之前，根据time模块docs:

time.clock() On Unix, return the current processor time as a floating point number expressed in seconds. The precision, and in fact the very definition of the meaning of “processor time”, depends on that of the C function of the same name, but in any case, this is the function to use for benchmarking Python or timing algorithms. On Windows, this function returns wall-clock seconds elapsed since the first call to this function, as a floating point number, based on the Win32 function QueryPerformanceCounter(). The resolution is typically better than one microsecond.

此外，还有timeit模块用于对代码段进行基准测试。

简单回答:在Python中使用time.clock()进行计时。

在*nix系统上，clock()返回处理器时间为浮点数，以秒表示。在Windows上，它以浮点数的形式返回自第一次调用此函数以来所经过的秒数。

time()返回自纪元以来的秒数，以UTC为单位，作为浮点数。不能保证您将获得比1秒更好的精度(即使time()返回一个浮点数)。还要注意，如果在两次调用该函数之间设置了系统时钟，那么第二次函数调用将返回一个较低的值。

从3.3开始，time.clock()已弃用，建议使用time.process_time()或time.perf_counter()。

在2.7之前，根据time模块docs:

time.clock() On Unix, return the current processor time as a floating point number expressed in seconds. The precision, and in fact the very definition of the meaning of “processor time”, depends on that of the C function of the same name, but in any case, this is the function to use for benchmarking Python or timing algorithms. On Windows, this function returns wall-clock seconds elapsed since the first call to this function, as a floating point number, based on the Win32 function QueryPerformanceCounter(). The resolution is typically better than one microsecond.

此外，还有timeit模块用于对代码段进行基准测试。

正确答案:它们都是相同长度的分数。

但如果主题是时间，哪个更快?

一个小测试案例:

import timeit
import time

clock_list = []
time_list = []

test1 = """
def test(v=time.clock()):
    s = time.clock() - v
"""

test2 = """
def test(v=time.time()):
    s = time.time() - v
"""
def test_it(Range) :
    for i in range(Range) :
        clk = timeit.timeit(test1, number=10000)
        clock_list.append(clk)
        tml = timeit.timeit(test2, number=10000)
        time_list.append(tml)

test_it(100)

print "Clock Min: %f Max: %f Average: %f" %(min(clock_list), max(clock_list), sum(clock_list)/float(len(clock_list)))
print "Time  Min: %f Max: %f Average: %f" %(min(time_list), max(time_list), sum(time_list)/float(len(time_list)))

我不是在瑞士实验室工作，但我做过测试。

基于这个问题:time.clock()比time.time()更好

编辑:time.clock()是内部计数器，所以不能在外部使用，得到限制最大32位浮点数，如果不存储第一个/最后一个值，就不能继续计数。不能合并另一个计数器…

在Linux上，time()比clock()具有更好的精度。Clock()的精度小于10毫秒。而time()提供完美的精度。 我的测试用的是CentOS 6.4和python 2.6

using time():

1 requests, response time: 14.1749382019 ms
2 requests, response time: 8.01301002502 ms
3 requests, response time: 8.01491737366 ms
4 requests, response time: 8.41021537781 ms
5 requests, response time: 8.38804244995 ms

使用时钟():

1 requests, response time: 10.0 ms
2 requests, response time: 0.0 ms 
3 requests, response time: 0.0 ms
4 requests, response time: 10.0 ms
5 requests, response time: 0.0 ms 
6 requests, response time: 0.0 ms
7 requests, response time: 0.0 ms 
8 requests, response time: 0.0 ms

简单的答案是:大多数时候time.clock()会更好。 然而，如果你正在为某些硬件计时(例如你在GPU中放入的某些算法)，那么time.clock()将摆脱这个时间，而time.time()是唯一剩下的解决方案。

注意:无论使用何种方法，计时将取决于您无法控制的因素(进程何时切换，频率如何，……)，这对于time.time()来说更糟糕，但对于time.clock()也存在，因此您永远不应该只运行一个计时测试，而是始终运行一系列测试并查看时间的均值/方差。