我正在构建一个PHP脚本，将JSON数据提供给另一个脚本。我的脚本将数据构建到一个大型关联数组中，然后使用json_encode输出数据。下面是一个脚本示例:
$data = array('a' => 'apple', 'b' => 'banana', 'c' => 'catnip');
header('Content-type: text/javascript');
echo json_encode($data);
上面的代码产生如下输出:
{"a":"apple","b":"banana","c":"catnip"}
如果你有少量的数据，这是很好的，但我更喜欢这样的东西:
{
"a": "apple",
"b": "banana",
"c": "catnip"
}
有没有办法在PHP中做到这一点，而不需要丑陋的黑客?似乎Facebook的某个人发现了这一点。
当前回答
将<pre>与json_encode()和JSON_PRETTY_PRINT选项结合使用:
<pre>
<?php
echo json_encode($dataArray, JSON_PRETTY_PRINT);
?>
</pre>
其他回答
你可以这样做。
$array = array(
"a" => "apple",
"b" => "banana",
"c" => "catnip"
);
foreach ($array as $a_key => $a_val) {
$json .= "\"{$a_key}\" : \"{$a_val}\",\n";
}
header('Content-Type: application/json');
echo "{\n" .rtrim($json, ",\n") . "\n}";
上面的输出有点像Facebook。
{
"a" : "apple",
"b" : "banana",
"c" : "catnip"
}
递归解的经典例子。这是我的:
class JsonFormatter {
public static function prettyPrint(&$j, $indentor = "\t", $indent = "") {
$inString = $escaped = false;
$result = $indent;
if(is_string($j)) {
$bak = $j;
$j = str_split(trim($j, '"'));
}
while(count($j)) {
$c = array_shift($j);
if(false !== strpos("{[,]}", $c)) {
if($inString) {
$result .= $c;
} else if($c == '{' || $c == '[') {
$result .= $c."\n";
$result .= self::prettyPrint($j, $indentor, $indentor.$indent);
$result .= $indent.array_shift($j);
} else if($c == '}' || $c == ']') {
array_unshift($j, $c);
$result .= "\n";
return $result;
} else {
$result .= $c."\n".$indent;
}
} else {
$result .= $c;
$c == '"' && !$escaped && $inString = !$inString;
$escaped = $c == '\\' ? !$escaped : false;
}
}
$j = $bak;
return $result;
}
}
用法:
php > require 'JsonFormatter.php';
php > $a = array('foo' => 1, 'bar' => 'This "is" bar', 'baz' => array('a' => 1, 'b' => 2, 'c' => '"3"'));
php > print_r($a);
Array
(
[foo] => 1
[bar] => This "is" bar
[baz] => Array
(
[a] => 1
[b] => 2
[c] => "3"
)
)
php > echo JsonFormatter::prettyPrint(json_encode($a));
{
"foo":1,
"bar":"This \"is\" bar",
"baz":{
"a":1,
"b":2,
"c":"\"3\""
}
}
干杯
如果你有JSON ($ugly_json)
echo nl2br(str_replace(' ', ' ', (json_encode(json_decode($ugly_json), JSON_PRETTY_PRINT | JSON_UNESCAPED_SLASHES))));
将<pre>与json_encode()和JSON_PRETTY_PRINT选项结合使用:
<pre>
<?php
echo json_encode($dataArray, JSON_PRETTY_PRINT);
?>
</pre>
以下是对我有效的方法:
test.php的内容:
<html>
<body>
Testing JSON array output
<pre>
<?php
$data = array('a'=>'apple', 'b'=>'banana', 'c'=>'catnip');
// encode in json format
$data = json_encode($data);
// json as single line
echo "</br>Json as single line </br>";
echo $data;
// json as an array, formatted nicely
echo "</br>Json as multiline array </br>";
print_r(json_decode($data, true));
?>
</pre>
</body>
</html>
输出:
Testing JSON array output
Json as single line
{"a":"apple","b":"banana","c":"catnip"}
Json as multiline array
Array
(
[a] => apple
[b] => banana
[c] => catnip
)
还要注意html中“pre”标签的使用。
希望这能帮助到别人
