我正在构建一个PHP脚本,将JSON数据提供给另一个脚本。我的脚本将数据构建到一个大型关联数组中,然后使用json_encode输出数据。下面是一个脚本示例:
$data = array('a' => 'apple', 'b' => 'banana', 'c' => 'catnip');
header('Content-type: text/javascript');
echo json_encode($data);
上面的代码产生如下输出:
{"a":"apple","b":"banana","c":"catnip"}
如果你有少量的数据,这是很好的,但我更喜欢这样的东西:
{
"a": "apple",
"b": "banana",
"c": "catnip"
}
有没有办法在PHP中做到这一点,而不需要丑陋的黑客?似乎Facebook的某个人发现了这一点。
有颜色全输出:微小的解决方案
代码:
$s = '{"access": {"token": {"issued_at": "2008-08-16T14:10:31.309353", "expires": "2008-08-17T14:10:31Z", "id": "MIICQgYJKoZIhvcIegeyJpc3N1ZWRfYXQiOiAi"}, "serviceCatalog": [], "user": {"username": "ajay", "roles_links": [], "id": "16452ca89", "roles": [], "name": "ajay"}}}';
$crl = 0;
$ss = false;
echo "<pre>";
for($c=0; $c<strlen($s); $c++)
{
if ( $s[$c] == '}' || $s[$c] == ']' )
{
$crl--;
echo "\n";
echo str_repeat(' ', ($crl*2));
}
if ( $s[$c] == '"' && ($s[$c-1] == ',' || $s[$c-2] == ',') )
{
echo "\n";
echo str_repeat(' ', ($crl*2));
}
if ( $s[$c] == '"' && !$ss )
{
if ( $s[$c-1] == ':' || $s[$c-2] == ':' )
echo '<span style="color:#0000ff;">';
else
echo '<span style="color:#ff0000;">';
}
echo $s[$c];
if ( $s[$c] == '"' && $ss )
echo '</span>';
if ( $s[$c] == '"' )
$ss = !$ss;
if ( $s[$c] == '{' || $s[$c] == '[' )
{
$crl++;
echo "\n";
echo str_repeat(' ', ($crl*2));
}
}
echo $s[$c];
这个函数将接受JSON字符串并缩进,使其非常可读。它也是收敛的,
prettyPrint( $json ) === prettyPrint( prettyPrint( $json ) )
输入
{"key1":[1,2,3],"key2":"value"}
输出
{
"key1": [
1,
2,
3
],
"key2": "value"
}
Code
function prettyPrint( $json )
{
$result = '';
$level = 0;
$in_quotes = false;
$in_escape = false;
$ends_line_level = NULL;
$json_length = strlen( $json );
for( $i = 0; $i < $json_length; $i++ ) {
$char = $json[$i];
$new_line_level = NULL;
$post = "";
if( $ends_line_level !== NULL ) {
$new_line_level = $ends_line_level;
$ends_line_level = NULL;
}
if ( $in_escape ) {
$in_escape = false;
} else if( $char === '"' ) {
$in_quotes = !$in_quotes;
} else if( ! $in_quotes ) {
switch( $char ) {
case '}': case ']':
$level--;
$ends_line_level = NULL;
$new_line_level = $level;
break;
case '{': case '[':
$level++;
case ',':
$ends_line_level = $level;
break;
case ':':
$post = " ";
break;
case " ": case "\t": case "\n": case "\r":
$char = "";
$ends_line_level = $new_line_level;
$new_line_level = NULL;
break;
}
} else if ( $char === '\\' ) {
$in_escape = true;
}
if( $new_line_level !== NULL ) {
$result .= "\n".str_repeat( "\t", $new_line_level );
}
$result .= $char.$post;
}
return $result;
}
我通常会用这些简单的语句。
如果你已经有一个JSON字符串,你可以简单地使用echo()和print_r()的组合。
不要忘记将print_r()的第二个参数传递给true,以便它返回值而不是打印它:
echo('<pre>' . print_r($json, true) . '</pre>');
或者你可以使用die(),这对调试很方便:
die('<pre>' . print_r($json, true) . '</pre>');
如果您有一个数组,您需要在之前将其转换为JSON字符串。
请确保使用JSON_PRETTY_PRINT标志设置json_encode()的第二个参数,这样您的JSON将被正确呈现:
echo('<pre>' . print_r(json_encode($array, JSON_PRETTY_PRINT), true) . '</pre>');
或者用于调试:
die('<pre>' . print_r(json_encode($array, JSON_PRETTY_PRINT), true) . '</pre>');
以下是对我有效的方法:
test.php的内容:
<html>
<body>
Testing JSON array output
<pre>
<?php
$data = array('a'=>'apple', 'b'=>'banana', 'c'=>'catnip');
// encode in json format
$data = json_encode($data);
// json as single line
echo "</br>Json as single line </br>";
echo $data;
// json as an array, formatted nicely
echo "</br>Json as multiline array </br>";
print_r(json_decode($data, true));
?>
</pre>
</body>
</html>
输出:
Testing JSON array output
Json as single line
{"a":"apple","b":"banana","c":"catnip"}
Json as multiline array
Array
(
[a] => apple
[b] => banana
[c] => catnip
)
还要注意html中“pre”标签的使用。
希望这能帮助到别人