如何将颜色在RGB格式转换为十六进制格式,反之亦然?

例如,将'#0080C0'转换为(0,128,192)。


当前回答

HTML converer :)

<!DOCTYPE html>
<html>
<body>

<p id="res"></p>

<script>
function hexToRgb(hex) {
  var res = /^#?([a-f\d]{2})([a-f\d]{2})([a-f\d]{2})$/i.exec(hex);
  return "(" + parseInt(res[1], 16) + "," + parseInt(res[2], 16) + "," + parseInt(res[3], 16) + ")";
};

document.getElementById("res").innerHTML = hexToRgb('#0080C0');
</script>

</body>
</html>

其他回答

结合使用匿名函数和数组。地图为清洁工;更流线型的外观。

var write=function(str){document.body.innerHTML=JSON.stringify(str,null,' ');}; function hexToRgb(hex, asObj) { return (function(res) { return res == null ? null : (function(parts) { return !asObj ? parts : { r : parts[0], g : parts[1], b : parts[2] } }(res.slice(1,4).map(function(val) { return parseInt(val, 16); }))); }(/^#?([a-f\d]{2})([a-f\d]{2})([a-f\d]{2})$/i.exec(hex))); } function rgbToHex(r, g, b) { return (function(values) { return '#' + values.map(function(intVal) { return (function(hexVal) { return hexVal.length == 1 ? "0" + hexVal : hexVal; }(intVal.toString(16))); }).join(''); }(arguments.length === 1 ? Array.isArray(r) ? r : [r.r, r.g, r.b] : [r, g, b])) } // Prints: { r: 255, g: 127, b: 92 } write(hexToRgb(rgbToHex(hexToRgb(rgbToHex(255, 127, 92), true)), true)); body{font-family:monospace;white-space:pre}

这个代码片段将十六进制转换为rgb, rgb转换为十六进制。

视图演示

function hexToRgb(str) { 
    if ( /^#([0-9a-f]{3}|[0-9a-f]{6})$/ig.test(str) ) { 
        var hex = str.substr(1);
        hex = hex.length == 3 ? hex.replace(/(.)/g, '$1$1') : hex;
        var rgb = parseInt(hex, 16);               
        return 'rgb(' + [(rgb >> 16) & 255, (rgb >> 8) & 255, rgb & 255].join(',') + ')';
    } 

    return false; 
}

function rgbToHex(red, green, blue) {
    var out = '#';

    for (var i = 0; i < 3; ++i) {
        var n = typeof arguments[i] == 'number' ? arguments[i] : parseInt(arguments[i]);

        if (isNaN(n) || n < 0 || n > 255) {
            return false;
        }

        out += (n < 16 ? '0' : '') + n.toString(16);
    }
    return out
}

我正在使用XAML数据,具有十六进制格式的#AARRGGBB (Alpha,红色,绿色,蓝色)。利用上面的答案,以下是我的解决方案:

function hexToRgba(hex) {
    var bigint, r, g, b, a;
    //Remove # character
    var re = /^#?/;
    var aRgb = hex.replace(re, '');
    bigint = parseInt(aRgb, 16);

    //If in #FFF format
    if (aRgb.length == 3) {
        r = (bigint >> 4) & 255;
        g = (bigint >> 2) & 255;
        b = bigint & 255;
        return "rgba(" + r + "," + g + "," + b + ",1)";
    }

    //If in #RRGGBB format
    if (aRgb.length >= 6) {
        r = (bigint >> 16) & 255;
        g = (bigint >> 8) & 255;
        b = bigint & 255;
        var rgb = r + "," + g + "," + b;

        //If in #AARRBBGG format
        if (aRgb.length == 8) {
            a = ((bigint >> 24) & 255) / 255;
            return "rgba(" + rgb + "," + a.toFixed(1) + ")";
        }
    }
    return "rgba(" + rgb + ",1)";
}

http://jsfiddle.net/kvLyscs3/

我假设您指的是html风格的十六进制符号,即#rrggbb。你的代码几乎是正确的,只是顺序颠倒了。它应该是:

var decColor = red * 65536 + green * 256 + blue;

此外,使用位移位可能会让它更容易阅读:

var decColor = (red << 16) + (green << 8) + blue;

以下是我的看法:

function rgbToHex(red, green, blue) {
  const rgb = (red << 16) | (green << 8) | (blue << 0);
  return '#' + (0x1000000 + rgb).toString(16).slice(1);
}

function hexToRgb(hex) {
  const normal = hex.match(/^#([0-9a-f]{2})([0-9a-f]{2})([0-9a-f]{2})$/i);
  if (normal) return normal.slice(1).map(e => parseInt(e, 16));

  const shorthand = hex.match(/^#([0-9a-f])([0-9a-f])([0-9a-f])$/i);
  if (shorthand) return shorthand.slice(1).map(e => 0x11 * parseInt(e, 16));

  return null;
}