如何将颜色在RGB格式转换为十六进制格式，反之亦然?
例如，将'#0080C0'转换为(0,128,192)。
当前回答
我发现了这个，因为我认为它非常直截了当，有验证测试和支持alpha值(可选)，这将适合这种情况。
只要注释掉regex行，如果你知道你在做什么，它会快一点。
function hexToRGBA(hex, alpha){
hex = (""+hex).trim().replace(/#/g,""); //trim and remove any leading # if there (supports number values as well)
if (!/^(?:[0-9a-fA-F]{3}){1,2}$/.test(hex)) throw ("not a valid hex string"); //Regex Validator
if (hex.length==3){hex=hex[0]+hex[0]+hex[1]+hex[1]+hex[2]+hex[2]} //support short form
var b_int = parseInt(hex, 16);
return "rgba("+[
(b_int >> 16) & 255, //R
(b_int >> 8) & 255, //G
b_int & 255, //B
alpha || 1 //add alpha if is set
].join(",")+")";
}
其他回答
哇。这些答案都不能处理分数的边缘情况，等等。当r, g, b为零时，位移版本也不起作用。
这是一个可以处理r g b是小数的版本。它对颜色之间的插值很有用，所以我也包括了这段代码。但它仍然不能处理r, g, b在0-255范围之外的情况
/**
* Operates with colors.
* @class Q.Colors
*/
Q.Color = {
/**
* Get a color somewhere between startColor and endColor
* @method toHex
* @static
* @param {String|Number} startColor
* @param {String|Number} endColor
* @param {String|Number} fraction
* @returns {String} a color as a hex string without '#' in front
*/
toHex: function (r, g, b) {
return [r, g, b].map(x => {
const hex = Math.round(x).toString(16)
return hex.length === 1 ? '0' + hex : hex
}).join('');
},
/**
* Get a color somewhere between startColor and endColor
* @method between
* @static
* @param {String|Number} startColor
* @param {String|Number} endColor
* @param {String|Number} fraction
* @returns {String} a color as a hex string without '#' in front
*/
between: function(startColor, endColor, fraction) {
if (typeof startColor === 'string') {
startColor = parseInt(startColor.replace('#', '0x'), 16);
}
if (typeof endColor === 'string') {
endColor = parseInt(endColor.replace('#', '0x'), 16);
}
var startRed = (startColor >> 16) & 0xFF;
var startGreen = (startColor >> 8) & 0xFF;
var startBlue = startColor & 0xFF;
var endRed = (endColor >> 16) & 0xFF;
var endGreen = (endColor >> 8) & 0xFF;
var endBlue = endColor & 0xFF;
var newRed = startRed + fraction * (endRed - startRed);
var newGreen = startGreen + fraction * (endGreen - startGreen);
var newBlue = startBlue + fraction * (endBlue - startBlue);
return Q.Color.toHex(newRed, newGreen, newBlue);
},
/**
* Sets a new theme-color on the window
* @method setWindowTheme
* @static
* @param {String} color in any CSS format, such as "#aabbcc"
* @return {String} the previous color
*/
setWindowTheme: function (color) {
var meta = document.querySelector('meta[name="theme-color"]');
var prevColor = null;
if (meta) {
prevColor = meta.getAttribute('content');
}
if (color) {
if (!meta) {
meta = document.createElement('meta');
meta.setAttribute('name', 'theme-color');
}
meta.setAttribute('content', color);
}
return prevColor;
},
/**
* Gets the current window theme color
* @method getWindowTheme
* @static
* @param {String} color in any CSS format, such as "#aabbcc"
* @return {String} the previous color
*/
getWindowTheme: function () {
var meta = document.querySelector('meta[name="theme-color"]');
return meta.getAttribute('content');
}
}
我需要一个函数，接受无效值太像
Rgb (- 255,255,255) Rgb (510, 255, 255)
这是@cwolves answer的衍生
function rgb(r, g, b) {
this.c = this.c || function (n) {
return Math.max(Math.min(n, 255), 0)
};
return ((1 << 24) + (this.c(r) << 16) + (this.c(g) << 8) + this.c(b)).toString(16).slice(1).toUpperCase();
}
我假设您指的是html风格的十六进制符号，即#rrggbb。你的代码几乎是正确的，只是顺序颠倒了。它应该是:
var decColor = red * 65536 + green * 256 + blue;
此外，使用位移位可能会让它更容易阅读:
var decColor = (red << 16) + (green << 8) + blue;
HTML converer :)
<!DOCTYPE html>
<html>
<body>
<p id="res"></p>
<script>
function hexToRgb(hex) {
var res = /^#?([a-f\d]{2})([a-f\d]{2})([a-f\d]{2})$/i.exec(hex);
return "(" + parseInt(res[1], 16) + "," + parseInt(res[2], 16) + "," + parseInt(res[3], 16) + ")";
};
document.getElementById("res").innerHTML = hexToRgb('#0080C0');
</script>
</body>
</html>
上面的一个干净的咖啡脚本版本(谢谢@TimDown):
rgbToHex = (rgb) ->
a = rgb.match /\d+/g
rgb unless a.length is 3
"##{ ((1 << 24) + (parseInt(a[0]) << 16) + (parseInt(a[1]) << 8) + parseInt(a[2])).toString(16).slice(1) }"
