简单的方法

enum Color { Red, Green }

const c1 = Color["Red"]
const redStr = "Red" // important: use `const`, not mutable `let`
const c2 = Color[redStr]

这既适用于数值枚举，也适用于字符串枚举。不需要使用类型断言。

未知enum字符串

Simple, unsafe variant

const redStrWide: string = "Red" // wide, unspecific typed string
const c3 = Color[redStrWide as keyof typeof Color]

Safe variant with checks

const isEnumName = <T>(str: string, _enum: T): str is Extract<keyof T, string> =>
    str in _enum
const enumFromName = <T>(name: string, _enum: T) => {
    if (!isEnumName(name, _enum)) throw Error() // here fail fast as an example
    return _enum[name]
}
const c4 = enumFromName(redStrWide, Color)

转换字符串enum值

字符串枚举没有反向映射(与数字枚举相反)。我们可以创建一个查找助手来将枚举值字符串转换为枚举类型:

enum ColorStr { Red = "red", Green = "green" }

const c5_by_name = ColorStr["Red"] // ✅ this works
const c5_by_value_error = ColorStr["red"] // ❌ , but this not

const enumFromValue = <T extends Record<string, string>>(val: string, _enum: T) => {
    const enumName = (Object.keys(_enum) as Array<keyof T>).find(k => _enum[k] === val)
    if (!enumName) throw Error() // here fail fast as an example
    return _enum[enumName]
}

const c5 = enumFromValue("red", ColorStr)

操场上的样品

几乎所有答案都使用不安全的类型转换(as或is)。这一条没有:

enum Color {
    Red = "red",
    Green = "green"
}

const colorsMap = new Map<string,Color>(Object.values(Color).map((v) => [v,v]))

function parseColor(volumeData: string): Color | undefined {
    return colorsMap.get(volumeData)
}

const color = parseColor("red")

这些答案对我来说都太复杂了……

您可以简单地在枚举上创建一个解析函数，期望其中一个键作为参数。添加新颜色时，不需要进行其他更改

enum Color { red, green}

// Get the keys 'red' | 'green' (but not 'parse')
type ColorKey = keyof Omit<typeof Color, 'parse'>;

namespace Color {
  export function parse(colorName: ColorKey ) {
    return Color[colorName];
  }
}

// The key 'red' exists as an enum so no warning is given
Color.parse('red');  // == Colors.red

// Without the 'any' cast you would get a compile-time warning
// Because 'foo' is not one of the keys in the enum
Color.parse('foo' as any); // == undefined

// Creates warning:
// "Argument of type '"bar"' is not assignable to parameter of type '"red" | "green"'"
Color.parse('bar');

简单的方法

enum Color { Red, Green }

const c1 = Color["Red"]
const redStr = "Red" // important: use `const`, not mutable `let`
const c2 = Color[redStr]

这既适用于数值枚举，也适用于字符串枚举。不需要使用类型断言。

未知enum字符串

Simple, unsafe variant

const redStrWide: string = "Red" // wide, unspecific typed string
const c3 = Color[redStrWide as keyof typeof Color]

Safe variant with checks

const isEnumName = <T>(str: string, _enum: T): str is Extract<keyof T, string> =>
    str in _enum
const enumFromName = <T>(name: string, _enum: T) => {
    if (!isEnumName(name, _enum)) throw Error() // here fail fast as an example
    return _enum[name]
}
const c4 = enumFromName(redStrWide, Color)

转换字符串enum值

字符串枚举没有反向映射(与数字枚举相反)。我们可以创建一个查找助手来将枚举值字符串转换为枚举类型:

enum ColorStr { Red = "red", Green = "green" }

const c5_by_name = ColorStr["Red"] // ✅ this works
const c5_by_value_error = ColorStr["red"] // ❌ , but this not

const enumFromValue = <T extends Record<string, string>>(val: string, _enum: T) => {
    const enumName = (Object.keys(_enum) as Array<keyof T>).find(k => _enum[k] === val)
    if (!enumName) throw Error() // here fail fast as an example
    return _enum[enumName]
}

const c5 = enumFromValue("red", ColorStr)

操场上的样品

我还遇到了同样的编译器错误。只是Sly_cardinal方法的一个稍短的变种。

var color: Color = Color[<string>colorId];

对于Typescript >= 4，此代码工作:

enum Color{
    Red, Green
}

// Conversion :
var green= "Green";
var color : Color = green as unknown as Color;