我有一些复选框:

<input type='checkbox' value="apple" checked>
<input type='checkbox' value="orange">
<input type='checkbox' value="pear" checked>
<input type='checkbox' value="naartjie">

我想绑定到我的控制器中的一个列表,这样每当一个复选框被更改时,控制器就会维护一个包含所有选中值的列表,例如,['apple', 'pear']。

Ng-model似乎只能将一个复选框的值绑定到控制器中的一个变量。

是否有其他方法可以将这四个复选框绑定到控制器中的列表?


当前回答

你不需要编写所有的代码。AngularJS会通过使用ngTrueValue和ngFalseValue来使模型和复选框保持同步

代码在这里:http://codepen.io/paulbhartzog/pen/kBhzn

代码片段:

<p ng-repeat="item in list1" class="item" id="{{item.id}}">
  <strong>{{item.id}}</strong> <input name='obj1_data' type="checkbox" ng-model="list1[$index].data" ng-true-value="1" ng-false-value="0"> Click this to change data value below
</p>
<pre>{{list1 | json}}</pre>

其他回答

我在控制器中放了一个数组。

$scope.statuses = [{ name: 'Shutdown - Reassessment Required' },
    { name: 'Under Construction' },
    { name: 'Administrative Cancellation' },
    { name: 'Initial' },
    { name: 'Shutdown - Temporary' },
    { name: 'Decommissioned' },
    { name: 'Active' },
    { name: 'SO Shutdown' }]

在标记上,我添加了如下内容

<div ng-repeat="status in $scope.statuses">
   <input type="checkbox" name="unit_status" ng-model="$scope.checkboxes[status.name]"> {{status.name}}
   <br>                        
</div>
{{$scope.checkboxes}}

输出如下,在控制器中,我只需要检查它是真还是假;选中为True,未选中为null /false。

{
"Administrative Cancellation":true,
"Under Construction":true,
"Shutdown - Reassessment Required":true,
"Decommissioned":true,
"Active":true
}

希望这能有所帮助。

试试我的宝贝:

**

myApp.filter('inputSelected', function(){
  return function(formData){
    var keyArr = [];
    var word = [];
    Object.keys(formData).forEach(function(key){
    if (formData[key]){
        var keyCap = key.charAt(0).toUpperCase() + key.slice(1);
      for (var char = 0; char<keyCap.length; char++ ) {
        if (keyCap[char] == keyCap[char].toUpperCase()){
          var spacedLetter = ' '+ keyCap[char];
          word.push(spacedLetter);
        }
        else {
          word.push(keyCap[char]);
        }
      }
    }
    keyArr.push(word.join(''))
    word = [];
    })
    return keyArr.toString();
  }
})

**

然后对于任何带有复选框的ng-model,它将返回你选择的所有输入的字符串:

<label for="Heard about ITN">How did you hear about ITN?: *</label><br>
<label class="checkbox-inline"><input ng-model="formData.heardAboutItn.brotherOrSister" type="checkbox" >Brother or Sister</label>
<label class="checkbox-inline"><input ng-model="formData.heardAboutItn.friendOrAcquaintance" type="checkbox" >Friend or Acquaintance</label>


{{formData.heardAboutItn | inputSelected }}

//returns Brother or Sister, Friend or Acquaintance

我认为最简单的解决方法是使用'select'并指定'multiple':

<select ng-model="selectedfruit" multiple ng-options="v for v in fruit"></select>

否则,我认为您将不得不处理该列表来构造该列表 (通过$watch()用复选框绑定模型数组)。

  <div ng-app='app' >
    <div ng-controller='MainCtrl' >
       <ul> 
       <li ng-repeat="tab in data">
         <input type='checkbox' ng-click='change($index,confirm)' ng-model='confirm' />
         {{tab.name}} 
         </li>
     </ul>
    {{val}}
   </div>
 </div>


var app = angular.module('app', []);
 app.controller('MainCtrl',function($scope){
 $scope.val=[];
  $scope.confirm=false;
  $scope.data=[
   {
     name:'vijay'
     },
    {
      name:'krishna'
    },{
      name:'Nikhil'
     }
    ];
    $scope.temp;
   $scope.change=function(index,confirm){
     console.log(confirm);
    if(!confirm){
     ($scope.val).push($scope.data[index]);   
    }
    else{
    $scope.temp=$scope.data[index];
        var d=($scope.val).indexOf($scope.temp);
        if(d!=undefined){
         ($scope.val).splice(d,1);
        }    
       }
     }   
   })
<input type='checkbox' ng-repeat="fruit in fruits"
  ng-checked="checkedFruits.indexOf(fruit) != -1" ng-click="toggleCheck(fruit)">

.

function SomeCtrl ($scope) {
    $scope.fruits = ["apple, orange, pear, naartjie"];
    $scope.checkedFruits = [];
    $scope.toggleCheck = function (fruit) {
        if ($scope.checkedFruits.indexOf(fruit) === -1) {
            $scope.checkedFruits.push(fruit);
        } else {
            $scope.checkedFruits.splice($scope.checkedFruits.indexOf(fruit), 1);
        }
    };
}