我有一些复选框:

<input type='checkbox' value="apple" checked>
<input type='checkbox' value="orange">
<input type='checkbox' value="pear" checked>
<input type='checkbox' value="naartjie">

我想绑定到我的控制器中的一个列表,这样每当一个复选框被更改时,控制器就会维护一个包含所有选中值的列表,例如,['apple', 'pear']。

Ng-model似乎只能将一个复选框的值绑定到控制器中的一个变量。

是否有其他方法可以将这四个复选框绑定到控制器中的列表?


当前回答

我在控制器中放了一个数组。

$scope.statuses = [{ name: 'Shutdown - Reassessment Required' },
    { name: 'Under Construction' },
    { name: 'Administrative Cancellation' },
    { name: 'Initial' },
    { name: 'Shutdown - Temporary' },
    { name: 'Decommissioned' },
    { name: 'Active' },
    { name: 'SO Shutdown' }]

在标记上,我添加了如下内容

<div ng-repeat="status in $scope.statuses">
   <input type="checkbox" name="unit_status" ng-model="$scope.checkboxes[status.name]"> {{status.name}}
   <br>                        
</div>
{{$scope.checkboxes}}

输出如下,在控制器中,我只需要检查它是真还是假;选中为True,未选中为null /false。

{
"Administrative Cancellation":true,
"Under Construction":true,
"Shutdown - Reassessment Required":true,
"Decommissioned":true,
"Active":true
}

希望这能有所帮助。

其他回答

试试我的宝贝:

**

myApp.filter('inputSelected', function(){
  return function(formData){
    var keyArr = [];
    var word = [];
    Object.keys(formData).forEach(function(key){
    if (formData[key]){
        var keyCap = key.charAt(0).toUpperCase() + key.slice(1);
      for (var char = 0; char<keyCap.length; char++ ) {
        if (keyCap[char] == keyCap[char].toUpperCase()){
          var spacedLetter = ' '+ keyCap[char];
          word.push(spacedLetter);
        }
        else {
          word.push(keyCap[char]);
        }
      }
    }
    keyArr.push(word.join(''))
    word = [];
    })
    return keyArr.toString();
  }
})

**

然后对于任何带有复选框的ng-model,它将返回你选择的所有输入的字符串:

<label for="Heard about ITN">How did you hear about ITN?: *</label><br>
<label class="checkbox-inline"><input ng-model="formData.heardAboutItn.brotherOrSister" type="checkbox" >Brother or Sister</label>
<label class="checkbox-inline"><input ng-model="formData.heardAboutItn.friendOrAcquaintance" type="checkbox" >Friend or Acquaintance</label>


{{formData.heardAboutItn | inputSelected }}

//returns Brother or Sister, Friend or Acquaintance

你可以结合AngularJS和jQuery。例如,您需要定义一个数组$scope。控制器中的Selected = [];

<label ng-repeat="item in items">
    <input type="checkbox" ng-model="selected[$index]" ng-true-value="'{{item}}'">{{item}}
</label>

您可以获得拥有所选项目的数组。使用方法alert(JSON.stringify($scope.selected)),可以检查选中的项。

看看这个有效管理复选框列表的指令。我希望这对你有用。 检查表模型

一种简单的HTML方法:

<input type="checkbox" ng-checked="fruits.indexOf('apple') > -1" ng-click="fruits.indexOf('apple') > -1 ? fruits.splice(fruits.indexOf('apple'), 1) : fruits.push('apple')"> <input type="checkbox" ng-checked="fruits.indexOf('orange') > -1" ng-click="fruits.indexOf('orange') > -1 ? fruits.splice(fruits.indexOf('orange'), 1) : fruits.push('orange')"> <input type="checkbox" ng-checked="fruits.indexOf('pear') > -1" ng-click="fruits.indexOf('pear') > -1 ? fruits.splice(fruits.indexOf('pear'), 1) : fruits.push('pear')"> <input type="checkbox" ng-checked="fruits.indexOf('naartjie') > -1" ng-click="fruits.indexOf('apple') > -1 ? fruits.splice(fruits.indexOf('apple'), 1) : fruits.push('naartjie')">

我喜欢Yoshi的回答。我增强了它,所以你可以对多个列表使用相同的函数。

<label ng-repeat="fruitName in fruits">
<input
type="checkbox"
name="selectedFruits[]"
value="{{fruitName}}"
ng-checked="selection.indexOf(fruitName) > -1"
ng-click="toggleSelection(fruitName, selection)"> {{fruitName}}
</label>


<label ng-repeat="veggieName in veggies">
<input
type="checkbox"
name="selectedVeggies[]"
value="{{veggieName}}"
ng-checked="veggieSelection.indexOf(veggieName) > -1"
ng-click="toggleSelection(veggieName, veggieSelection)"> {{veggieName}}
</label>



app.controller('SimpleArrayCtrl', ['$scope', function SimpleArrayCtrl($scope) {
  // fruits
  $scope.fruits = ['apple', 'orange', 'pear', 'naartjie'];
  $scope.veggies = ['lettuce', 'cabbage', 'tomato']
  // selected fruits
  $scope.selection = ['apple', 'pear'];
  $scope.veggieSelection = ['lettuce']
  // toggle selection for a given fruit by name
  $scope.toggleSelection = function toggleSelection(selectionName, listSelection) {
    var idx = listSelection.indexOf(selectionName);

    // is currently selected
    if (idx > -1) {
      listSelection.splice(idx, 1);
    }

    // is newly selected
    else {
      listSelection.push(selectionName);
    }
  };
}]);

http://plnkr.co/edit/KcbtzEyNMA8s1X7Hja8p?p=preview