>>> d={'a':1,'b':2,'c':3}
>>> for kv in d.items():
...     print kv[0],'\t',kv[1]
... 
a   1
c   3
b   2

或者，对于Python 3:

for k,v in dict.items():
    print(k, v)

如果你正在寻找漂亮的印刷字典，看看Rich:

from rich import print

prices = {
    "banana": 4,
    "apple": 2,
    "orange": 1.5,
    "pear": 3,
    "strawberry": 1,
    "blueberry": 0.5,
    "mango": 4.5
}

print(prices)

for key, value in d.iteritems():
    print key, '\t', value

对于Python 3.x

for key, value in d.iteritems():
    print(f'{key}\t{value}') 

字典:

d={'key1':'value1','key2':'value2','key3':'value3'}

另一个单线解决方案:

print(*d.items(), sep='\n')

输出:

('key1', 'value1')
('key2', 'value2')
('key3', 'value3')

(但是，由于之前没有人建议这样做，我怀疑这不是一个好的实践)

除了已经提到的方法之外。可以使用" viewitems " " viewkeys " " viewvalues "

>>> d = {320: 1, 321: 0, 322: 3}
>>> list(d.viewitems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.viewkeys())
[320, 321, 322]
>>> list(d.viewvalues())
[1, 0, 3]

Or

>>> list(d.iteritems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.iterkeys())
[320, 321, 322]
>>> list(d.itervalues())
[1, 0, 3]

或者使用itemgetter

>>> from operator import itemgetter
>>> map(itemgetter(0), dd.items())     ####  for keys
['323', '332']
>>> map(itemgetter(1), dd.items())     ####  for values
['3323', 232]