我想从python字典中输出我的键值对,如下所示:
key1 \t value1
key2 \t value2
我想我可以这样做:
for i in d:
print d.keys(i), d.values(i)
但显然不是这样的,因为keys()和values()不带参数。
我想从python字典中输出我的键值对,如下所示:
key1 \t value1
key2 \t value2
我想我可以这样做:
for i in d:
print d.keys(i), d.values(i)
但显然不是这样的,因为keys()和values()不带参数。
当前回答
>>> d={'a':1,'b':2,'c':3}
>>> for kv in d.items():
... print kv[0],'\t',kv[1]
...
a 1
c 3
b 2
其他回答
或者,对于Python 3:
for k,v in dict.items():
print(k, v)
如果你正在寻找漂亮的印刷字典,看看Rich:
from rich import print
prices = {
"banana": 4,
"apple": 2,
"orange": 1.5,
"pear": 3,
"strawberry": 1,
"blueberry": 0.5,
"mango": 4.5
}
print(prices)
for key, value in d.iteritems():
print key, '\t', value
对于Python 3.x
for key, value in d.iteritems():
print(f'{key}\t{value}')
字典:
d={'key1':'value1','key2':'value2','key3':'value3'}
另一个单线解决方案:
print(*d.items(), sep='\n')
输出:
('key1', 'value1')
('key2', 'value2')
('key3', 'value3')
(但是,由于之前没有人建议这样做,我怀疑这不是一个好的实践)
除了已经提到的方法之外。可以使用" viewitems " " viewkeys " " viewvalues "
>>> d = {320: 1, 321: 0, 322: 3}
>>> list(d.viewitems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.viewkeys())
[320, 321, 322]
>>> list(d.viewvalues())
[1, 0, 3]
Or
>>> list(d.iteritems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.iterkeys())
[320, 321, 322]
>>> list(d.itervalues())
[1, 0, 3]
或者使用itemgetter
>>> from operator import itemgetter
>>> map(itemgetter(0), dd.items()) #### for keys
['323', '332']
>>> map(itemgetter(1), dd.items()) #### for values
['3323', 232]