除了已经提到的方法之外。可以使用" viewitems " " viewkeys " " viewvalues "

>>> d = {320: 1, 321: 0, 322: 3}
>>> list(d.viewitems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.viewkeys())
[320, 321, 322]
>>> list(d.viewvalues())
[1, 0, 3]

Or

>>> list(d.iteritems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.iterkeys())
[320, 321, 322]
>>> list(d.itervalues())
[1, 0, 3]

或者使用itemgetter

>>> from operator import itemgetter
>>> map(itemgetter(0), dd.items())     ####  for keys
['323', '332']
>>> map(itemgetter(1), dd.items())     ####  for values
['3323', 232]

如果要按字典键对输出进行排序，可以使用集合包。

import collections
for k, v in collections.OrderedDict(sorted(d.items())).items():
    print(k, v)

它适用于python 3

Python 2和Python 3

I是键，所以你只需要使用它:

for i in d:
    print i, d[i]

Python 3

D.items()返回迭代器;要获得一个列表，需要自己将迭代器传递给list()。

for k, v in d.items():
    print(k, v)

Python 2

你可以得到一个同时包含键和值的迭代器。D.items()返回一个(key, value)元组列表，而d.iteritems()返回一个提供相同元组的迭代器:

for k, v in d.iteritems():
    print k, v

如果你正在寻找漂亮的印刷字典，看看Rich:

from rich import print

prices = {
    "banana": 4,
    "apple": 2,
    "orange": 1.5,
    "pear": 3,
    "strawberry": 1,
    "blueberry": 0.5,
    "mango": 4.5
}

print(prices)

字典:

d={'key1':'value1','key2':'value2','key3':'value3'}

另一个单线解决方案:

print(*d.items(), sep='\n')

输出:

('key1', 'value1')
('key2', 'value2')
('key3', 'value3')

(但是，由于之前没有人建议这样做，我怀疑这不是一个好的实践)

打印键值对，例如:

players = {
     'lebron': 'lakers',
     'giannis':   'milwakee bucks',
     'durant':  'brooklyn nets',
     'kawhi':   'clippers',    
}

对于player，在players.items()中的club:

print(f"\n{player.title()} is the leader of {club}")

上面的代码，键值对:

 'lebron': 'lakers', - Lebron is key and lakers is value

对于循环-在dictionary.item()中指定键和值:

现在打印(玩家名是俱乐部队长)。

输出为:

#Lebron is the leader of lakers
#Giannis is the leader of milwakee bucks
#Durant is the leader of brooklyn nets
#Kawhi is the leader of clippers