字典:

d={'key1':'value1','key2':'value2','key3':'value3'}

另一个单线解决方案:

print(*d.items(), sep='\n')

输出:

('key1', 'value1')
('key2', 'value2')
('key3', 'value3')

(但是，由于之前没有人建议这样做，我怀疑这不是一个好的实践)

>>> d={'a':1,'b':2,'c':3}
>>> for kv in d.items():
...     print kv[0],'\t',kv[1]
... 
a   1
c   3
b   2

或者，对于Python 3:

for k,v in dict.items():
    print(k, v)

打印键值对，例如:

players = {
     'lebron': 'lakers',
     'giannis':   'milwakee bucks',
     'durant':  'brooklyn nets',
     'kawhi':   'clippers',    
}

对于player，在players.items()中的club:

print(f"\n{player.title()} is the leader of {club}")

上面的代码，键值对:

 'lebron': 'lakers', - Lebron is key and lakers is value

对于循环-在dictionary.item()中指定键和值:

现在打印(玩家名是俱乐部队长)。

输出为:

#Lebron is the leader of lakers
#Giannis is the leader of milwakee bucks
#Durant is the leader of brooklyn nets
#Kawhi is the leader of clippers

简单介绍一下字典

d={'a':'apple','b':'ball'}
d.keys()  # displays all keys in list
['a','b']
d.values() # displays your values in list
['apple','ball']
d.items() # displays your pair tuple of key and value
[('a','apple'),('b','ball')

打印键值，方法一

for x in d.keys():
    print(x +" => " + d[x])

另一种方法

for key,value in d.items():
    print(key + " => " + value)

你可以使用iter获取密钥

>>> list(iter(d))
['a', 'b']

你可以使用get(key， [value])获取字典key的值:

d.get('a')
'apple'

如果key不存在于字典中，当给出默认值时，将返回value。

d.get('c', 'Cat')
'Cat'

除了已经提到的方法之外。可以使用" viewitems " " viewkeys " " viewvalues "

>>> d = {320: 1, 321: 0, 322: 3}
>>> list(d.viewitems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.viewkeys())
[320, 321, 322]
>>> list(d.viewvalues())
[1, 0, 3]

Or

>>> list(d.iteritems())
[(320, 1), (321, 0), (322, 3)]
>>> list(d.iterkeys())
[320, 321, 322]
>>> list(d.itervalues())
[1, 0, 3]

或者使用itemgetter

>>> from operator import itemgetter
>>> map(itemgetter(0), dd.items())     ####  for keys
['323', '332']
>>> map(itemgetter(1), dd.items())     ####  for values
['3323', 232]