grep -A1 'blah' logfile
多亏了这个命令,每一行都有'blah',我得到了包含'blah'的行输出和日志文件中的下一行。这可能是一个简单的,但我找不到一种方法来省略一行有'blah',只显示下一行在输出。
grep -A1 'blah' logfile
多亏了这个命令,每一行都有'blah',我得到了包含'blah'的行输出和日志文件中的下一行。这可能是一个简单的,但我找不到一种方法来省略一行有'blah',只显示下一行在输出。
当前回答
you can use grep, then take lines in jumps: grep -A1 'blah' logfile | awk 'NR%3==2' you can also take n lines after match, for example: seq 100 | grep -A3 .2 | awk 'NR%5==4' 15 25 35 45 55 65 75 85 95 explanation - here we want to grep all lines that are *2 and take 3 lines after it, which is *5. seq 100 | grep -A3 .2 will give you: 12 13 14 15 -- 22 23 24 25 -- ... the number in the modulo (NR%5) is the added rows by grep (here it's 3 by the flag -A3), +2 extra lines because you have current matching line and also the -- line that the grep is adding.
其他回答
you can use grep, then take lines in jumps: grep -A1 'blah' logfile | awk 'NR%3==2' you can also take n lines after match, for example: seq 100 | grep -A3 .2 | awk 'NR%5==4' 15 25 35 45 55 65 75 85 95 explanation - here we want to grep all lines that are *2 and take 3 lines after it, which is *5. seq 100 | grep -A3 .2 will give you: 12 13 14 15 -- 22 23 24 25 -- ... the number in the modulo (NR%5) is the added rows by grep (here it's 3 by the flag -A3), +2 extra lines because you have current matching line and also the -- line that the grep is adding.
grep /Pattern/ | tail -n 2 | head -n
尾先2个,头最后一个,比赛结束后正好排在第一行。
滚边是你的朋友……
使用grep -A1显示匹配后的下一行,然后将结果管道到tail,只抓取一行,
cat logs/info.log | grep "term" -A1 | tail -n 1
如果下一行从来没有包含'blah',你可以过滤他们:
grep -A1 blah logfile | grep -v blah
使用cat logfile |…不需要。
Perl一行程序警告
只是为了好玩……匹配后只打印一行
perl -lne '$. == $next && print; $next = ($.+1) if /match/' data.txt
更有趣的是……匹配后打印接下来的十行
perl -lne 'push @nexts, (($.+1)..($.+10)) if /match/; $. ~~ @nexts && print' data.txt
虽然有点作弊,因为实际上有两个命令