你可以匹配多行，然后输出n行:

awk 'c&&!--c;/match1/{c=1};/match2/{c=2}' file

匹配多个项目，输出n行后:

#!/bin/sh
[ -z $3 ] && echo $0 file \[match n\]+... \# to output line n after match && exit
f=$1; shift; while [ \! -z $2 ]; do s="$s/$1/{c=$2};"; shift; shift; done
awk 'c&&!--c;'$s $f

所以你可以把上面的文件保存为match .sh和chmod +x match .sh，然后如果你有一个这样的文件:

line1
line2 
line3
line4
line5
line6
line7

并运行:

./matchn.sh file line1 1 line3 2 line6 1

你会得到:

line2
line5
line7

这将需要更多的调整来支持0偏移量。

滚边是你的朋友……

使用grep -A1显示匹配后的下一行，然后将结果管道到tail，只抓取一行，

cat logs/info.log | grep "term" -A1 | tail -n 1

reaim的回答很好，对我很有用。将其扩展到打印模式之后的第7行是很简单的

awk -v lines=7 '/blah/ {for(i=lines;i;--i)getline; print $0 }' logfile

如果你想坚持使用grep:

grep -A1 'blah' logfile | grep -v "blah"

或者使用sed:

sed -n '/blah/{n;p;}' logfile

我不知道有什么方法可以用grep来做到这一点，但是使用awk可以达到相同的结果:

awk '/blah/ {getline;print}' < logfile

you can use grep, then take lines in jumps: grep -A1 'blah' logfile | awk 'NR%3==2' you can also take n lines after match, for example: seq 100 | grep -A3 .2 | awk 'NR%5==4' 15 25 35 45 55 65 75 85 95 explanation - here we want to grep all lines that are *2 and take 3 lines after it, which is *5. seq 100 | grep -A3 .2 will give you: 12 13 14 15 -- 22 23 24 25 -- ... the number in the modulo (NR%5) is the added rows by grep (here it's 3 by the flag -A3), +2 extra lines because you have current matching line and also the -- line that the grep is adding.