通过查看调用堆栈，我们可以获得正在执行的每个脚本的文件路径，其中最有用的两个可能是当前正在执行的脚本，或者是要获取的第一个脚本(条目)。

script.dir.executing = (function() return( if(length(sys.parents())==1) getwd() else dirname( Filter(is.character,lapply(rev(sys.frames()),function(x) x$ofile))[[1]] ) ))()

script.dir.entry = (function() return( if(length(sys.parents())==1) getwd() else dirname(sys.frame(1)$ofile) ))()

我自己刚算出来的。为了确保脚本的可移植性，总是以以下开头:

wd <- setwd(".")
setwd(wd)

It works because "." translates like the Unix command $PWD. Assigning this string to a character object allows you to then insert that character object into setwd() and Presto your code will always run with its current directory as the working directory, no matter whose machine it is on or where in the file structure it is located. (Extra bonus: The wd object can be used with file.path() (ie. file.path(wd, "output_directory") to allow for the creation of a standard output directory regardless of the file path leading to your named directory. This does require you to make the new directory before referencing it this way but that, too, can be aided with the wd object.

或者，下面的代码执行完全相同的事情:

wd <- getwd()
setwd(wd)

或者，如果你不需要对象中的文件路径，你可以简单地:

setwd(".")

我的一切都在一个!(—2019年9月1日更新以处理RStudio控制台)

#' current script file (in full path)
#' @description current script file (in full path)
#' @examples
#' works with Rscript, source() or in RStudio Run selection, RStudio Console
#' @export
ez.csf <- function() {
    # http://stackoverflow.com/a/32016824/2292993
    cmdArgs = commandArgs(trailingOnly = FALSE)
    needle = "--file="
    match = grep(needle, cmdArgs)
    if (length(match) > 0) {
        # Rscript via command line
        return(normalizePath(sub(needle, "", cmdArgs[match])))
    } else {
        ls_vars = ls(sys.frames()[[1]])
        if ("fileName" %in% ls_vars) {
            # Source'd via RStudio
            return(normalizePath(sys.frames()[[1]]$fileName))
        } else {
            if (!is.null(sys.frames()[[1]]$ofile)) {
            # Source'd via R console
            return(normalizePath(sys.frames()[[1]]$ofile))
            } else {
                # RStudio Run Selection
                # http://stackoverflow.com/a/35842176/2292993
                pth = rstudioapi::getActiveDocumentContext()$path
                if (pth!='') {
                    return(normalizePath(pth))
                } else {
                    # RStudio Console
                    tryCatch({
                            pth = rstudioapi::getSourceEditorContext()$path
                            pth = normalizePath(pth)
                        }, error = function(e) {
                            # normalizePath('') issues warning/error
                            pth = ''
                        }
                    )
                    return(pth)
                }
            }
        }
    }
}

你可以在一个bash脚本中包装r脚本，并检索脚本的路径作为bash变量，如下所示:

#!/bin/bash
     # [environment variables can be set here]
     path_to_script=$(dirname $0)

     R --slave<<EOF
        source("$path_to_script/other.R")

     EOF

你可以使用commandArgs函数获取Rscript传递给实际R解释器的所有选项，并搜索——file=。如果你的脚本是从路径启动的，或者它是以一个完整的路径启动的，下面的script.name将以'/'开头。否则，它必须是相对于cwd，你可以连接两个路径，以获得完整的路径。

编辑:听起来你只需要上面的script.name，并剥离路径的最后一个组件。我已经删除了不需要的cwd()样本，并清理了主脚本，并张贴了我的其他. r。只需要保存这个脚本和其他脚本。R脚本放到同一个目录下，chmod +x它们，然后运行主脚本。

主要。接待员:

#!/usr/bin/env Rscript
initial.options <- commandArgs(trailingOnly = FALSE)
file.arg.name <- "--file="
script.name <- sub(file.arg.name, "", initial.options[grep(file.arg.name, initial.options)])
script.basename <- dirname(script.name)
other.name <- file.path(script.basename, "other.R")
print(paste("Sourcing",other.name,"from",script.name))
source(other.name)

其他。接待员:

print("hello")

输出:

burner@firefighter:~$ main.R
[1] "Sourcing /home/burner/bin/other.R from /home/burner/bin/main.R"
[1] "hello"
burner@firefighter:~$ bin/main.R
[1] "Sourcing bin/other.R from bin/main.R"
[1] "hello"
burner@firefighter:~$ cd bin
burner@firefighter:~/bin$ main.R
[1] "Sourcing ./other.R from ./main.R"
[1] "hello"

我相信这就是德曼在找的东西。

Steamer25的方法是有效的，但前提是路径中没有空白。在macOS上，至少cmdArgs[match]返回类似/base/some~+~dir~+~带~+~空格/ for /base/some\ dir\带\空格/。

我通过在返回之前用一个简单的空格替换“~+~”来解决这个问题。

thisFile <- function() {
  cmdArgs <- commandArgs(trailingOnly = FALSE)
  needle <- "--file="
  match <- grep(needle, cmdArgs)
  if (length(match) > 0) {
    # Rscript
    path <- cmdArgs[match]
    path <- gsub("\\~\\+\\~", " ", path)
    return(normalizePath(sub(needle, "", path)))
  } else {
    # 'source'd via R console
    return(normalizePath(sys.frames()[[1]]$ofile))
  }
}

显然，你仍然可以像aprstar那样扩展else块。