我有一个名为foo的脚本。R包含另一个脚本other。R，在同一个目录下:
#!/usr/bin/env Rscript
message("Hello")
source("other.R")
但我想让R找到另一个。R，不管当前工作目录是什么。
换句话说，就是foo。R需要知道自己的路径。我该怎么做呢?
当前回答
我的一切都在一个!(—2019年9月1日更新以处理RStudio控制台)
#' current script file (in full path)
#' @description current script file (in full path)
#' @examples
#' works with Rscript, source() or in RStudio Run selection, RStudio Console
#' @export
ez.csf <- function() {
# http://stackoverflow.com/a/32016824/2292993
cmdArgs = commandArgs(trailingOnly = FALSE)
needle = "--file="
match = grep(needle, cmdArgs)
if (length(match) > 0) {
# Rscript via command line
return(normalizePath(sub(needle, "", cmdArgs[match])))
} else {
ls_vars = ls(sys.frames()[[1]])
if ("fileName" %in% ls_vars) {
# Source'd via RStudio
return(normalizePath(sys.frames()[[1]]$fileName))
} else {
if (!is.null(sys.frames()[[1]]$ofile)) {
# Source'd via R console
return(normalizePath(sys.frames()[[1]]$ofile))
} else {
# RStudio Run Selection
# http://stackoverflow.com/a/35842176/2292993
pth = rstudioapi::getActiveDocumentContext()$path
if (pth!='') {
return(normalizePath(pth))
} else {
# RStudio Console
tryCatch({
pth = rstudioapi::getSourceEditorContext()$path
pth = normalizePath(pth)
}, error = function(e) {
# normalizePath('') issues warning/error
pth = ''
}
)
return(pth)
}
}
}
}
}
其他回答
I would use a variant of @steamer25 's approach. The point is that I prefer to obtain the last sourced script even when my session was started through Rscript. The following snippet, when included on a file, will provided a variable thisScript containing the normalized path of the script. I confess the (ab)use of source'ing, so sometimes I invoke Rscript and the script provided in the --file argument sources another script that sources another one... Someday I will invest in making my messy code turns into a package.
thisScript <- (function() {
lastScriptSourced <- tail(unlist(lapply(sys.frames(), function(env) env$ofile)), 1)
if (is.null(lastScriptSourced)) {
# No script sourced, checking invocation through Rscript
cmdArgs <- commandArgs(trailingOnly = FALSE)
needle <- "--file="
match <- grep(needle, cmdArgs)
if (length(match) > 0) {
return(normalizePath(sub(needle, "", cmdArgs[match]), winslash=.Platform$file.sep, mustWork=TRUE))
}
} else {
# 'source'd via R console
return(normalizePath(lastScriptSourced, winslash=.Platform$file.sep, mustWork=TRUE))
}
})()
我的一切都在一个!(—2019年9月1日更新以处理RStudio控制台)
#' current script file (in full path)
#' @description current script file (in full path)
#' @examples
#' works with Rscript, source() or in RStudio Run selection, RStudio Console
#' @export
ez.csf <- function() {
# http://stackoverflow.com/a/32016824/2292993
cmdArgs = commandArgs(trailingOnly = FALSE)
needle = "--file="
match = grep(needle, cmdArgs)
if (length(match) > 0) {
# Rscript via command line
return(normalizePath(sub(needle, "", cmdArgs[match])))
} else {
ls_vars = ls(sys.frames()[[1]])
if ("fileName" %in% ls_vars) {
# Source'd via RStudio
return(normalizePath(sys.frames()[[1]]$fileName))
} else {
if (!is.null(sys.frames()[[1]]$ofile)) {
# Source'd via R console
return(normalizePath(sys.frames()[[1]]$ofile))
} else {
# RStudio Run Selection
# http://stackoverflow.com/a/35842176/2292993
pth = rstudioapi::getActiveDocumentContext()$path
if (pth!='') {
return(normalizePath(pth))
} else {
# RStudio Console
tryCatch({
pth = rstudioapi::getSourceEditorContext()$path
pth = normalizePath(pth)
}, error = function(e) {
# normalizePath('') issues warning/error
pth = ''
}
)
return(pth)
}
}
}
}
}
Steamer25的方法是有效的，但前提是路径中没有空白。在macOS上，至少cmdArgs[match]返回类似/base/some~+~dir~+~带~+~空格/ for /base/some\ dir\带\空格/。
我通过在返回之前用一个简单的空格替换“~+~”来解决这个问题。
thisFile <- function() {
cmdArgs <- commandArgs(trailingOnly = FALSE)
needle <- "--file="
match <- grep(needle, cmdArgs)
if (length(match) > 0) {
# Rscript
path <- cmdArgs[match]
path <- gsub("\\~\\+\\~", " ", path)
return(normalizePath(sub(needle, "", path)))
} else {
# 'source'd via R console
return(normalizePath(sys.frames()[[1]]$ofile))
}
}
显然，你仍然可以像aprstar那样扩展else块。
这个问题有一个简单的解决办法。这个命令:
script.dir <- dirname(sys.frame(1)$ofile)
返回当前脚本文件的路径。它在保存脚本后工作。
通过查看调用堆栈，我们可以获得正在执行的每个脚本的文件路径，其中最有用的两个可能是当前正在执行的脚本，或者是要获取的第一个脚本(条目)。
script.dir.executing = (function() return( if(length(sys.parents())==1) getwd() else dirname( Filter(is.character,lapply(rev(sys.frames()),function(x) x$ofile))[[1]] ) ))()
script.dir.entry = (function() return( if(length(sys.parents())==1) getwd() else dirname(sys.frame(1)$ofile) ))()
