Java中有哪些好的电子邮件地址验证库?有任何替代公共验证器的方法吗?
当前回答
回答迟了,但我觉得简单而有价值:
public boolean isValidEmailAddress(String email) {
String ePattern = "^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@((\\[[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\])|(([a-zA-Z\\-0-9]+\\.)+[a-zA-Z]{2,}))$";
java.util.regex.Pattern p = java.util.regex.Pattern.compile(ePattern);
java.util.regex.Matcher m = p.matcher(email);
return m.matches();
}
测试用例:
出于生产目的,域名验证应该在网络上执行。
其他回答
我在这个地址上维护了一个类:http://lacinato.com/cm/software/emailrelated/emailaddress
它基于Les Hazlewood的类,但有许多改进并修复了一些错误。Apache许可证。
I believe it is the most capable email parser in Java, and I have yet to see one more capable in any language, though there may be one out there. It's not a lexer-style parser, but uses some complicated java regex, and thus is not as efficient as it could be, but my company has parsed well over 10 billion real-world addresses with it: it's certainly usable in a high-performance situation. Maybe once a year it'll hit an address that causes a regex stack overflow (appropriately), but these are spam addresses which are hundreds or thousands of characters long with many many quotes and parenthesis and the like.
RFC 2822和相关规范在电子邮件地址方面是非常宽松的,所以这样的类对于大多数用途来说是多余的。例如,以下是一个合法的地址,根据规范,空格和所有:
"<bob \" (here) " < (hi there) "bob(the man)smith" (hi) @ (there) example.com (hello) > (again)
没有邮件服务器允许这样做,但是这个类可以解析它(并将其重写为可用的形式)。
我们发现现有的Java电子邮件解析器选项不够持久(也就是说,它们都不能解析一些有效地址),因此创建了这个类。
该代码有良好的文档记录,并且有许多易于更改的选项来允许或禁止某些电子邮件表单。它还提供了许多方法来访问地址的某些部分(左侧、右侧、个人姓名、注释等),解析/验证邮箱列表头,解析/验证返回路径(在头中是唯一的),等等。
编写的代码有一个javamail依赖项,但是如果您不想要它提供的次要功能,那么很容易删除它。
当前的Apache Commons Validator版本为1.3.1。
进行验证的类是org.apache.commons.validator.EmailValidator。它导入了org.apache.oro.text.perl。Perl5Util来自一个退役的雅加达ORO项目。
BTW, I found that there is a 1.4 version, here are the API docs. On the site it says: "Last Published: 05 March 2008 | Version: 1.4-SNAPSHOT", but that's not final. Only way to build yourself (but this is a snapshot, not RELEASE) and use, or download from here. This means 1.4 has not been made final for three years (2008-2011). This is not in Apache's style. I'm looking for a better option, but didn't find one that is very adopted. I want to use something that is well tested, don't want to hit any bugs.
public class Validations {
private Pattern regexPattern;
private Matcher regMatcher;
public String validateEmailAddress(String emailAddress) {
regexPattern = Pattern.compile("^[(a-zA-Z-0-9-\\_\\+\\.)]+@[(a-z-A-z)]+\\.[(a-zA-z)]{2,3}$");
regMatcher = regexPattern.matcher(emailAddress);
if(regMatcher.matches()) {
return "Valid Email Address";
} else {
return "Invalid Email Address";
}
}
public String validateMobileNumber(String mobileNumber) {
regexPattern = Pattern.compile("^\\+[0-9]{2,3}+-[0-9]{10}$");
regMatcher = regexPattern.matcher(mobileNumber);
if(regMatcher.matches()) {
return "Valid Mobile Number";
} else {
return "Invalid Mobile Number";
}
}
public static void main(String[] args) {
String emailAddress = "suryaprakash.pisay@gmail.com";
String mobileNumber = "+91-9986571622";
Validations validations = new Validations();
System.out.println(validations.validateEmailAddress(emailAddress));
System.out.println(validations.validateMobileNumber(mobileNumber));
}
}
回答迟了,但我觉得简单而有价值:
public boolean isValidEmailAddress(String email) {
String ePattern = "^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@((\\[[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\])|(([a-zA-Z\\-0-9]+\\.)+[a-zA-Z]{2,}))$";
java.util.regex.Pattern p = java.util.regex.Pattern.compile(ePattern);
java.util.regex.Matcher m = p.matcher(email);
return m.matches();
}
测试用例:
出于生产目的,域名验证应该在网络上执行。
这是最好的方法:
public static boolean isValidEmail(String enteredEmail){
String EMAIL_REGIX = "^[\\\\w!#$%&’*+/=?`{|}~^-]+(?:\\\\.[\\\\w!#$%&’*+/=?`{|}~^-]+)*@(?:[a-zA-Z0-9-]+\\\\.)+[a-zA-Z]{2,6}$";
Pattern pattern = Pattern.compile(EMAIL_REGIX);
Matcher matcher = pattern.matcher(enteredEmail);
return ((!enteredEmail.isEmpty()) && (enteredEmail!=null) && (matcher.matches()));
}
来源: http://howtodoinjava.com/2014/11/11/java-regex-validate-email-address/
http://www.rfc-editor.org/rfc/rfc5322.txt
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