给定一个绝对路径或相对路径(在类unix系统中),我希望在解析任何中间符号链接之后确定目标的完整路径。同时还可以解析~用户名符号。

如果目标是一个目录,则可以将chdir()放入该目录,然后调用getcwd(),但我确实希望从shell脚本而不是编写C helper来完成此操作。不幸的是,shell倾向于试图向用户隐藏符号链接的存在(这是OS X上的bash):

$ ls -ld foo bar
drwxr-xr-x   2 greg  greg  68 Aug 11 22:36 bar
lrwxr-xr-x   1 greg  greg   3 Aug 11 22:36 foo -> bar
$ cd foo
$ pwd
/Users/greg/tmp/foo
$

我想要的是一个函数resolve(),这样当从上面的例子中的tmp目录执行时,resolve("foo") == "/Users/greg/tmp/bar"。


当前回答

因为我在过去的几年里遇到过很多次这样的情况,这一次我需要一个纯粹的bash可移植版本,可以在OSX和linux上使用,我继续写了一个:

活生生的版本就在这里:

https://github.com/keen99/shell-functions/tree/master/resolve_path

但为了SO,这里是当前的版本(我觉得它经过了很好的测试..但我愿意接受反馈!)

可能不难使它为普通bourne shell (sh)工作,但我没有尝试…我太喜欢$FUNCNAME了。:)

#!/bin/bash

resolve_path() {
    #I'm bash only, please!
    # usage:  resolve_path <a file or directory> 
    # follows symlinks and relative paths, returns a full real path
    #
    local owd="$PWD"
    #echo "$FUNCNAME for $1" >&2
    local opath="$1"
    local npath=""
    local obase=$(basename "$opath")
    local odir=$(dirname "$opath")
    if [[ -L "$opath" ]]
    then
    #it's a link.
    #file or directory, we want to cd into it's dir
        cd $odir
    #then extract where the link points.
        npath=$(readlink "$obase")
        #have to -L BEFORE we -f, because -f includes -L :(
        if [[ -L $npath ]]
         then
        #the link points to another symlink, so go follow that.
            resolve_path "$npath"
            #and finish out early, we're done.
            return $?
            #done
        elif [[ -f $npath ]]
        #the link points to a file.
         then
            #get the dir for the new file
            nbase=$(basename $npath)
            npath=$(dirname $npath)
            cd "$npath"
            ndir=$(pwd -P)
            retval=0
            #done
        elif [[ -d $npath ]]
         then
        #the link points to a directory.
            cd "$npath"
            ndir=$(pwd -P)
            retval=0
            #done
        else
            echo "$FUNCNAME: ERROR: unknown condition inside link!!" >&2
            echo "opath [[ $opath ]]" >&2
            echo "npath [[ $npath ]]" >&2
            return 1
        fi
    else
        if ! [[ -e "$opath" ]]
         then
            echo "$FUNCNAME: $opath: No such file or directory" >&2
            return 1
            #and break early
        elif [[ -d "$opath" ]]
         then 
            cd "$opath"
            ndir=$(pwd -P)
            retval=0
            #done
        elif [[ -f "$opath" ]]
         then
            cd $odir
            ndir=$(pwd -P)
            nbase=$(basename "$opath")
            retval=0
            #done
        else
            echo "$FUNCNAME: ERROR: unknown condition outside link!!" >&2
            echo "opath [[ $opath ]]" >&2
            return 1
        fi
    fi
    #now assemble our output
    echo -n "$ndir"
    if [[ "x${nbase:=}" != "x" ]]
     then
        echo "/$nbase"
    else 
        echo
    fi
    #now return to where we were
    cd "$owd"
    return $retval
}

这里有一个经典的例子,感谢brew:

%% ls -l `which mvn`
lrwxr-xr-x  1 draistrick  502  29 Dec 17 10:50 /usr/local/bin/mvn@ -> ../Cellar/maven/3.2.3/bin/mvn

使用这个函数,它将返回-real- path:

%% cat test.sh
#!/bin/bash
. resolve_path.inc
echo
echo "relative symlinked path:"
which mvn
echo
echo "and the real path:"
resolve_path `which mvn`


%% test.sh

relative symlinked path:
/usr/local/bin/mvn

and the real path:
/usr/local/Cellar/maven/3.2.3/libexec/bin/mvn 

其他回答

根据标准,pwd -P应该返回已解析符号链接的路径。

C函数char *getcwd(char *buf, size_t size)从unistd.h应该有相同的行为。

getcwd 松材线虫病

为了解决Mac不兼容的问题,我想到了

echo `php -r "echo realpath('foo');"`

不是很好,但是跨越了操作系统

注意:我相信这是一个可靠的、可移植的、现成的解决方案,但由于这个原因,它总是很冗长。

下面是一个完全兼容POSIX的脚本/函数,因此是跨平台的(也适用于macOS,其readlink在10.12 (Sierra)仍然不支持-f) -它只使用POSIX shell语言特性和只使用POSIX兼容的实用程序调用。

它是GNU readlink -e (readlink -f的严格版本)的可移植实现。

您可以使用sh运行脚本,也可以在bash、ksh和zsh中获取该函数:

例如,在一个脚本中,你可以像下面这样使用它来获取运行脚本的真实源目录,并解析符号链接:

trueScriptDir=$(dirname -- "$(rreadlink "$0")")

Rreadlink脚本/函数定义:

出于感激,代码改编自这个回答。 我还在这里创建了一个基于bash的独立实用程序版本,您可以使用它进行安装 npm install rreadlink -g,如果你已经安装了Node.js。

#!/bin/sh

# SYNOPSIS
#   rreadlink <fileOrDirPath>
# DESCRIPTION
#   Resolves <fileOrDirPath> to its ultimate target, if it is a symlink, and
#   prints its canonical path. If it is not a symlink, its own canonical path
#   is printed.
#   A broken symlink causes an error that reports the non-existent target.
# LIMITATIONS
#   - Won't work with filenames with embedded newlines or filenames containing 
#     the string ' -> '.
# COMPATIBILITY
#   This is a fully POSIX-compliant implementation of what GNU readlink's
#    -e option does.
# EXAMPLE
#   In a shell script, use the following to get that script's true directory of origin:
#     trueScriptDir=$(dirname -- "$(rreadlink "$0")")
rreadlink() ( # Execute the function in a *subshell* to localize variables and the effect of `cd`.

  target=$1 fname= targetDir= CDPATH=

  # Try to make the execution environment as predictable as possible:
  # All commands below are invoked via `command`, so we must make sure that
  # `command` itself is not redefined as an alias or shell function.
  # (Note that command is too inconsistent across shells, so we don't use it.)
  # `command` is a *builtin* in bash, dash, ksh, zsh, and some platforms do not 
  # even have an external utility version of it (e.g, Ubuntu).
  # `command` bypasses aliases and shell functions and also finds builtins 
  # in bash, dash, and ksh. In zsh, option POSIX_BUILTINS must be turned on for
  # that to happen.
  { \unalias command; \unset -f command; } >/dev/null 2>&1
  [ -n "$ZSH_VERSION" ] && options[POSIX_BUILTINS]=on # make zsh find *builtins* with `command` too.

  while :; do # Resolve potential symlinks until the ultimate target is found.
      [ -L "$target" ] || [ -e "$target" ] || { command printf '%s\n' "ERROR: '$target' does not exist." >&2; return 1; }
      command cd "$(command dirname -- "$target")" # Change to target dir; necessary for correct resolution of target path.
      fname=$(command basename -- "$target") # Extract filename.
      [ "$fname" = '/' ] && fname='' # !! curiously, `basename /` returns '/'
      if [ -L "$fname" ]; then
        # Extract [next] target path, which may be defined
        # *relative* to the symlink's own directory.
        # Note: We parse `ls -l` output to find the symlink target
        #       which is the only POSIX-compliant, albeit somewhat fragile, way.
        target=$(command ls -l "$fname")
        target=${target#* -> }
        continue # Resolve [next] symlink target.
      fi
      break # Ultimate target reached.
  done
  targetDir=$(command pwd -P) # Get canonical dir. path
  # Output the ultimate target's canonical path.
  # Note that we manually resolve paths ending in /. and /.. to make sure we have a normalized path.
  if [ "$fname" = '.' ]; then
    command printf '%s\n' "${targetDir%/}"
  elif  [ "$fname" = '..' ]; then
    # Caveat: something like /var/.. will resolve to /private (assuming /var@ -> /private/var), i.e. the '..' is applied
    # AFTER canonicalization.
    command printf '%s\n' "$(command dirname -- "${targetDir}")"
  else
    command printf '%s\n' "${targetDir%/}/$fname"
  fi
)

rreadlink "$@"

关于安全问题:

Jarno在引用确保内置命令不会被同名的别名或shell函数所遮蔽的函数时,在注释中询问:

如果unalias或unset和[被设置为别名或shell函数会怎样?

rreadlink确保命令具有其原始含义的动机是使用它来绕过(良性的)方便别名和函数,这些别名和函数通常用于掩盖交互式shell中的标准命令,例如重新定义ls以包括最喜欢的选项。

我认为可以肯定地说,除非您正在处理一个不受信任的、恶意的环境,担心unalias或unset -或者,就此而言,do,…-被重新定义不是一个问题。

有一些函数必须依赖于它的原始意义和行为-没有办法绕过它。 类似posix的shell允许重新定义内置程序甚至语言关键字,这本质上是一种安全风险(而且编写偏执的代码通常是困难的)。

为了解决您的问题:

该函数依赖于unalias和unset具有其原始含义。以改变它们行为的方式将它们重新定义为shell函数将是一个问题;重新定义为别名 不必担心,因为引用(部分)命令名(例如\unalias)会绕过别名。

然而,shell关键字不能引用(while, for, if, do,…),虽然shell关键字优先于shell函数,但在bash和zsh中别名具有最高优先级,因此为了防止shell关键字重新定义,您必须使用它们的名称运行别名(尽管在非交互式bash shell(如脚本)中,默认情况下别名不会扩展-只有在首先显式调用shopt -s expand_aliases时)。

为了确保unalias(作为内置程序)具有其原始含义,您必须首先在其上使用\unset,这要求unset具有其原始含义:

Unset是一个内置的shell,所以为了确保它被这样调用,你必须确保它本身没有被重新定义为一个函数。虽然可以通过引用绕过别名形式,但不能绕过shell函数形式——catch 22。

因此,除非你可以依靠unset来获得它的原始含义,否则就我所知,没有保证的方法来防御所有恶意的重新定义。

下面是如何使用内联Perl脚本在MacOS/Unix中获得文件的实际路径:

FILE=$(perl -e "use Cwd qw(abs_path); print abs_path('$0')")

类似地,要获取符号链接文件的目录:

DIR=$(perl -e "use Cwd qw(abs_path); use File::Basename; print dirname(abs_path('$0'))")

我的2分钱。这个函数是POSIX兼容的,源和目标都可以包含->。但是,我还没有让它与容器换行符或制表符的文件名一起工作,因为ls通常有这些问题。

resolve_symlink() {
  test -L "$1" && ls -l "$1" | awk -v SYMLINK="$1" '{ SL=(SYMLINK)" -> "; i=index($0, SL); s=substr($0, i+length(SL)); print s }'
}

我认为这里的解决方案是file命令,使用一个自定义魔术文件,只输出所提供的符号链接的目标。