>>> if 'foo' in foo and 'bar' in foo:
...     print 'yes'
... 
yes

Jason，()在Python中不是必需的。

你可以这样做:

>>> if all(k in foo for k in ("foo","bar")):
...     print "They're there!"
...
They're there!

>>> if 'foo' in foo and 'bar' in foo:
...     print 'yes'
... 
yes

Jason，()在Python中不是必需的。

并不是说这不是你没有想过的事情，但我发现最简单的事情通常是最好的:

if ("foo" in foo) and ("bar" in foo):
    # do stuff

这里有一个替代的解决方案，以防你想要得到不匹配的项目……

not_existing_keys = [item for item in ["foo","bar"] if item not in foo]
if not_existing_keys:
  log.error('These items are missing', not_existing_keys)

检测是否所有键都在字典中的另一个选项:

dict_to_test = { ... }  # dict
keys_sought = { "key_sought_1", "key_sought_2", "key_sought_3" }  # set

if keys_sought & dict_to_test.keys() == keys_sought: 
    # True -- dict_to_test contains all keys in keys_sought
    # code_here
    pass