我可以通过在导航控制器的“viewDidDisappear”中写代码重定向到根页面，

override func viewDidDisappear(_ animated: Bool) { self.navigationController ?。popToRootViewController(动画:真) ｝

如果Segue是“Show”或“Push”类型，那么你可以在UINavigationController的实例上调用“popViewController(animated: Bool)”。或者如果segue是present，那么调用UIViewController的实例"dismiss(animated: Bool, completion: (() -> Void)?

斯威夫特3

我可能回答得晚了，但对于swift 3，你可以这样做:

override func viewDidLoad() {
    super.viewDidLoad()

    navigationItem.leftBarButtonItem = UIBarButtonItem(title: "< Back", style: .plain, target: self, action: #selector(backAction))

    // Do any additional setup if required.
}

func backAction(){
    //print("Back Button Clicked")
    dismiss(animated: true, completion: nil)
}

斯威夫特3，斯威夫特4

if movetoroot { 
    navigationController?.popToRootViewController(animated: true)
} else {
    navigationController?.popViewController(animated: true)
}

navigationController是可选的，因为可能没有。

试试这个: 对于前面的视图使用这个:

navigationController?.popViewController(animated: true)  

弹出到根目录使用以下代码:

navigationController?.popToRootViewController(animated: true) 

这个很适合我(Swift UI)

struct DetailView: View {
@Environment(\.presentationMode) var presentationMode: Binding<PresentationMode>

  var body: some View {
      VStack {
        Text("This is the detail view")
        Button(action: {
          self.presentationMode.wrappedValue.dismiss()
        }) {
          Text("Back")
        }
      }
    }
}