给定一个透明的PNG显示一个简单的形状在白色,它是有可能以某种方式改变这通过CSS的颜色?某种叠加还是什么?


当前回答

body{ background: #333 url(/images/classy_fabric.png); width: 430px; margin: 0 auto; padding: 30px; } .preview{ background: #ccc; width: 415px; height: 430px; border: solid 10px #fff; } input[type='radio'] { -webkit-appearance: none; -moz-appearance: none; width: 25px; height: 25px; margin: 5px 0 5px 5px; background-size: 225px 70px; position: relative; float: left; display: inline; top: 0; border-radius: 3px; z-index: 99999; cursor: pointer; box-shadow: 1px 1px 1px #000; } input[type='radio']:hover{ -webkit-filter: opacity(.4); filter: opacity(.4); } .red{ background: red; } .red:checked{ background: linear-gradient(brown, red) } .green{ background: green; } .green:checked{ background: linear-gradient(green, lime); } .yellow{ background: yellow; } .yellow:checked{ background: linear-gradient(orange, yellow); } .purple{ background: purple; } .pink{ background: pink; } .purple:checked{ background: linear-gradient(purple, violet); } .red:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 red); filter: opacity(.5) drop-shadow(0 0 0 red); } .green:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 green); filter: opacity(.5) drop-shadow(0 0 0 green); } .yellow:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 yellow); filter: opacity(.5) drop-shadow(0 0 0 yellow); } .purple:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 purple); filter: opacity(.5) drop-shadow(0 0 0 purple); } .pink:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 pink); filter: opacity(.5) drop-shadow(0 0 0 pink); } img{ width: 394px; height: 375px; position: relative; } .label{ width: 150px; height: 75px; position: absolute; top: 170px; margin-left: 130px; } ::selection{ background: #000; } <div class="preview"> <input class='red' name='color' type='radio' /> <input class='green' name='color' type='radio' /> <input class='pink' name='color' type='radio' /> <input checked class='yellow' name='color' type='radio' /> <input class='purple' name='color' type='radio' /> <img src="https://i.stack.imgur.com/bd7VJ.png"/> </div>

来源:https://codepen.io/taryaoui/pen/EKkcu

其他回答

对我来说有效的解决方案是使用滤镜:投影

滤镜:水滴阴影的工作方式不同于常规的盒子阴影。

滤镜将阴影应用于真实形状(因此它支持透明图像)。

现在的技巧是“隐藏”真实的图像,只显示阴影。

https://jsfiddle.net/d4m8x0qb/2

请注意,我的用例是将图标的颜色修改为一种纯色,所以这种方法适合我,但可能不适用于其他用例

body{ background: #333 url(/images/classy_fabric.png); width: 430px; margin: 0 auto; padding: 30px; } .preview{ background: #ccc; width: 415px; height: 430px; border: solid 10px #fff; } input[type='radio'] { -webkit-appearance: none; -moz-appearance: none; width: 25px; height: 25px; margin: 5px 0 5px 5px; background-size: 225px 70px; position: relative; float: left; display: inline; top: 0; border-radius: 3px; z-index: 99999; cursor: pointer; box-shadow: 1px 1px 1px #000; } input[type='radio']:hover{ -webkit-filter: opacity(.4); filter: opacity(.4); } .red{ background: red; } .red:checked{ background: linear-gradient(brown, red) } .green{ background: green; } .green:checked{ background: linear-gradient(green, lime); } .yellow{ background: yellow; } .yellow:checked{ background: linear-gradient(orange, yellow); } .purple{ background: purple; } .pink{ background: pink; } .purple:checked{ background: linear-gradient(purple, violet); } .red:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 red); filter: opacity(.5) drop-shadow(0 0 0 red); } .green:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 green); filter: opacity(.5) drop-shadow(0 0 0 green); } .yellow:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 yellow); filter: opacity(.5) drop-shadow(0 0 0 yellow); } .purple:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 purple); filter: opacity(.5) drop-shadow(0 0 0 purple); } .pink:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 pink); filter: opacity(.5) drop-shadow(0 0 0 pink); } img{ width: 394px; height: 375px; position: relative; } .label{ width: 150px; height: 75px; position: absolute; top: 170px; margin-left: 130px; } ::selection{ background: #000; } <div class="preview"> <input class='red' name='color' type='radio' /> <input class='green' name='color' type='radio' /> <input class='pink' name='color' type='radio' /> <input checked class='yellow' name='color' type='radio' /> <input class='purple' name='color' type='radio' /> <img src="https://i.stack.imgur.com/bd7VJ.png"/> </div>

来源:https://codepen.io/taryaoui/pen/EKkcu

I've been able to do this using SVG filter. You can write a filter that multiplies the color of source image with the color you want to change to. In the code snippet below, flood-color is the color we want to change image color to (which is Red in this case.) feComposite tells the filter how we're processing the color. The formula for feComposite with arithmetic is (k1*i1*i2 + k2*i1 + k3*i2 + k4) where i1 and i2 are input colors for in/in2 accordingly. So specifying only k1=1 means it will do just i1*i2, which means multiplying both input colors together.

注意:这只适用于HTML5,因为它使用内联SVG。但我认为,通过将SVG放在一个单独的文件中,您可能能够在较老的浏览器中实现这一点。我还没有尝试过这种方法。

Here's the snippet: <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask1"> <feFlood flood-color="#ff0000" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask1)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask2"> <feFlood flood-color="#00ff00" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask2)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask3"> <feFlood flood-color="#0000ff" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask3)" /> </svg>

是的:)

Surfin' Safari - Blog Archive » CSS Masks WebKit now supports alpha masks in CSS. Masks allow you to overlay the content of a box with a pattern that can be used to knock out portions of that box in the final display. In other words, you can clip to complex shapes based off the alpha of an image. [...] We have introduced new properties to provide Web designers with a lot of control over these masks and how they are applied. The new properties are analogous to the background and border-image properties that already exist. -webkit-mask (background) -webkit-mask-attachment (background-attachment) -webkit-mask-clip (background-clip) -webkit-mask-origin (background-origin) -webkit-mask-image (background-image) -webkit-mask-repeat (background-repeat) -webkit-mask-composite (background-composite) -webkit-mask-box-image (border-image)

我找到了这个很棒的codedeen示例,您插入十六进制颜色值,它返回所需的过滤器,将此颜色应用到png

CSS过滤器生成器转换从黑色到目标十六进制颜色

例如,我需要PNG的颜色为#1a9790

然后你必须对你的PNG应用下面的过滤器

filter: invert(48%) sepia(13%) saturate(3207%) hue-rotate(130deg) brightness(95%) contrast(80%);

PS:代码依赖是基于这里的MultiplyByZer0的精彩回答:如何仅使用CSS过滤器将黑色转换为任何给定的颜色

所有功劳都归他:鼓掌: