/* change image color to white */
filter: invert(100%) sepia(16%) saturate(7463%) hue-rotate(222deg) brightness(119%) contrast(115%);

/* change image color to red */`
filter: invert(16%) sepia(99%) saturate(7404%) hue-rotate(4deg) brightness(95%) contrast(118%);

/* change image color to green */
filter: invert(26%) sepia(89%) saturate(1583%) hue-rotate(95deg) brightness(96%) contrast(106%);

/* change image color to blue */
filter: invert(10%) sepia(90%) saturate(5268%) hue-rotate(245deg) brightness(109%) contrast(155%);

在大多数浏览器中，你可以使用过滤器:

在<img>元素和其他元素的背景图像上 并在CSS中静态设置它们，或者使用JavaScript动态设置它们

请看下面的演示。

< img >元素

你可以把这个技巧应用到<img>元素上:

#original， #changed { 宽度:45%; 填充:2.5%; 浮:左; ｝ #{改变 -webkit-filter:色调旋转(180度); 滤镜:色调旋转(180度); ｝ <img id="original" src="http://i.stack.imgur.com/rfar2.jpg" /> <img id="changed" src="http://i.stack.imgur.com/rfar2.jpg" />

背景图片

你可以把这个技巧应用到背景图像上:

#original， #changed { 背景:url (http://i.stack.imgur.com/kaKzj.jpg); background-size:封面; 宽度:30%; 利润率:0 10% 0 10%; padding-bottom: 28%; 浮:左; ｝ #{改变 -webkit-filter:色调旋转(180度); 滤镜:色调旋转(180度); ｝ < div id = "原始" > < / div > < div id = "改变" > < / div >

JavaScript

你可以使用JavaScript在运行时设置一个过滤器:

var element = document.getElementById("changed"); Var过滤器= '色调-旋转(120度)饱和(2.4)'; 元素。Style ['-webkit-filter'] = filter; 元素。Style ['filter'] = filter; #original， #changed { 利润率:0 10%; 宽度:30%; 浮:左; 背景:url (http://i.stack.imgur.com/856IQ.png); background-size:封面; padding-bottom: 25%; ｝ < div id = "原始" > < / div > < div id = "改变" > < / div >

body{ background: #333 url(/images/classy_fabric.png); width: 430px; margin: 0 auto; padding: 30px; } .preview{ background: #ccc; width: 415px; height: 430px; border: solid 10px #fff; } input[type='radio'] { -webkit-appearance: none; -moz-appearance: none; width: 25px; height: 25px; margin: 5px 0 5px 5px; background-size: 225px 70px; position: relative; float: left; display: inline; top: 0; border-radius: 3px; z-index: 99999; cursor: pointer; box-shadow: 1px 1px 1px #000; } input[type='radio']:hover{ -webkit-filter: opacity(.4); filter: opacity(.4); } .red{ background: red; } .red:checked{ background: linear-gradient(brown, red) } .green{ background: green; } .green:checked{ background: linear-gradient(green, lime); } .yellow{ background: yellow; } .yellow:checked{ background: linear-gradient(orange, yellow); } .purple{ background: purple; } .pink{ background: pink; } .purple:checked{ background: linear-gradient(purple, violet); } .red:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 red); filter: opacity(.5) drop-shadow(0 0 0 red); } .green:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 green); filter: opacity(.5) drop-shadow(0 0 0 green); } .yellow:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 yellow); filter: opacity(.5) drop-shadow(0 0 0 yellow); } .purple:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 purple); filter: opacity(.5) drop-shadow(0 0 0 purple); } .pink:checked ~ img{ -webkit-filter: opacity(.5) drop-shadow(0 0 0 pink); filter: opacity(.5) drop-shadow(0 0 0 pink); } img{ width: 394px; height: 375px; position: relative; } .label{ width: 150px; height: 75px; position: absolute; top: 170px; margin-left: 130px; } ::selection{ background: #000; } <div class="preview"> <input class='red' name='color' type='radio' /> <input class='green' name='color' type='radio' /> <input class='pink' name='color' type='radio' /> <input checked class='yellow' name='color' type='radio' /> <input class='purple' name='color' type='radio' /> <img src="https://i.stack.imgur.com/bd7VJ.png"/> </div>

来源:https://codepen.io/taryaoui/pen/EKkcu

I've been able to do this using SVG filter. You can write a filter that multiplies the color of source image with the color you want to change to. In the code snippet below, flood-color is the color we want to change image color to (which is Red in this case.) feComposite tells the filter how we're processing the color. The formula for feComposite with arithmetic is (k1*i1*i2 + k2*i1 + k3*i2 + k4) where i1 and i2 are input colors for in/in2 accordingly. So specifying only k1=1 means it will do just i1*i2, which means multiplying both input colors together.

注意:这只适用于HTML5，因为它使用内联SVG。但我认为，通过将SVG放在一个单独的文件中，您可能能够在较老的浏览器中实现这一点。我还没有尝试过这种方法。

Here's the snippet: <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask1"> <feFlood flood-color="#ff0000" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask1)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask2"> <feFlood flood-color="#00ff00" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask2)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask3"> <feFlood flood-color="#0000ff" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask3)" /> </svg>

我需要一个特定的颜色，所以滤镜不适合我。

相反，我创建了一个div，利用CSS多个背景图像和线性梯度函数(它自己创建图像)。如果你使用叠加混合模式，你的实际图像将与生成的“渐变”图像混合，包含你想要的颜色(这里，#BADA55)

.colored-image { background-image: linear-gradient(向右，#BADA55， #BADA55)， url("https://i.imgur.com/lYXT8R6.png"); background-blend-mode:覆盖; background-size:包含; 宽度:200 px; 身高:200 px; ｝ < div class = "的" > < / div >

使用这个很棒的codedeen示例，您插入十六进制颜色值，它返回所需的过滤器，将此颜色应用到png

CSS过滤器生成器转换从黑色到目标十六进制颜色

例如，我需要我的png颜色为#EF8C57

然后你必须对你的PNG应用下面的过滤器 结果:

filter: invert(76%) sepia(30%) saturate(3461%) hue-rotate(321deg) brightness(98%) contrast(91%);