给定一个透明的PNG显示一个简单的形状在白色,它是有可能以某种方式改变这通过CSS的颜色?某种叠加还是什么?


当前回答

img标签有一个和其他标签一样的background属性。如果你有一个透明形状的白色PNG,就像一个模板,那么你可以这样做:

<img src= 'stencil.png' style= 'background-color: red'>

其他回答

如果你只需要一个图标,就不需要整个字体集,而且我觉得它作为一个单独的元素更“干净”。因此,出于这个目的,在HTML5中可以直接在文档流中放置SVG。然后你可以在你的.CSS样式表中定义一个类,并使用fill属性访问它的背景色:

工作小提琴: http://jsfiddle.net/qmsj0ez1/

请注意,在示例中,我使用:hover来说明行为;如果您只是想更改“正常”状态的颜色,则应该删除伪类。

你可以使用-webkit-filter和filter来使用过滤器: 过滤器对于浏览器来说相对较新,但根据以下CanIUse表:https://caniuse.com/#feat=css-filters,超过90%的浏览器支持过滤器

你可以将图像更改为灰度,深褐色和更多(请看示例)。

所以你现在可以用滤镜改变PNG文件的颜色。

body { background-color:#03030a; min-width: 800px; min-height: 400px } img { width:20%; float:left; margin:0; } /*Filter styles*/ .saturate { filter: saturate(3); } .grayscale { filter: grayscale(100%); } .contrast { filter: contrast(160%); } .brightness { filter: brightness(0.25); } .blur { filter: blur(3px); } .invert { filter: invert(100%); } .sepia { filter: sepia(100%); } .huerotate { filter: hue-rotate(180deg); } .rss.opacity { filter: opacity(50%); } <!--- img src http://upload.wikimedia.org/wikipedia/commons/thumb/e/ec/Mona_Lisa%2C_by_Leonardo_da_Vinci%2C_from_C2RMF_retouched.jpg/500px-Mona_Lisa%2C_by_Leonardo_da_Vinci%2C_from_C2RMF_retouched.jpg --> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="original"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="saturate" class="saturate"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="grayscale" class="grayscale"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="contrast" class="contrast"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="brightness" class="brightness"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="blur" class="blur"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="invert" class="invert"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="sepia" class="sepia"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="huerotate" class="huerotate"> <img alt="Mona Lisa" src="https://images.pexels.com/photos/40997/mona-lisa-leonardo-da-vinci-la-gioconda-oil-painting-40997.jpeg?auto=compress&cs=tinysrgb&dpr=3&h=750&w=1260" title="opacity" class="rss opacity">

我需要一个特定的颜色,所以滤镜不适合我。

相反,我创建了一个div,利用CSS多个背景图像和线性梯度函数(它自己创建图像)。如果你使用叠加混合模式,你的实际图像将与生成的“渐变”图像混合,包含你想要的颜色(这里,#BADA55)

.colored-image { background-image: linear-gradient(向右,#BADA55, #BADA55), url("https://i.imgur.com/lYXT8R6.png"); background-blend-mode:覆盖; background-size:包含; 宽度:200 px; 身高:200 px; } < div class = "的" > < / div >

I've been able to do this using SVG filter. You can write a filter that multiplies the color of source image with the color you want to change to. In the code snippet below, flood-color is the color we want to change image color to (which is Red in this case.) feComposite tells the filter how we're processing the color. The formula for feComposite with arithmetic is (k1*i1*i2 + k2*i1 + k3*i2 + k4) where i1 and i2 are input colors for in/in2 accordingly. So specifying only k1=1 means it will do just i1*i2, which means multiplying both input colors together.

注意:这只适用于HTML5,因为它使用内联SVG。但我认为,通过将SVG放在一个单独的文件中,您可能能够在较老的浏览器中实现这一点。我还没有尝试过这种方法。

Here's the snippet: <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask1"> <feFlood flood-color="#ff0000" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask1)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask2"> <feFlood flood-color="#00ff00" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask2)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask3"> <feFlood flood-color="#0000ff" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask3)" /> </svg>

在大多数浏览器中,你可以使用过滤器:

在<img>元素和其他元素的背景图像上 并在CSS中静态设置它们,或者使用JavaScript动态设置它们

请看下面的演示。


< img >元素

你可以把这个技巧应用到<img>元素上:

#original, #changed { 宽度:45%; 填充:2.5%; 浮:左; } #{改变 -webkit-filter:色调旋转(180度); 滤镜:色调旋转(180度); } <img id="original" src="http://i.stack.imgur.com/rfar2.jpg" /> <img id="changed" src="http://i.stack.imgur.com/rfar2.jpg" />

背景图片

你可以把这个技巧应用到背景图像上:

#original, #changed { 背景:url (http://i.stack.imgur.com/kaKzj.jpg); background-size:封面; 宽度:30%; 利润率:0 10% 0 10%; padding-bottom: 28%; 浮:左; } #{改变 -webkit-filter:色调旋转(180度); 滤镜:色调旋转(180度); } < div id = "原始" > < / div > < div id = "改变" > < / div >

JavaScript

你可以使用JavaScript在运行时设置一个过滤器:

var element = document.getElementById("changed"); Var过滤器= '色调-旋转(120度)饱和(2.4)'; 元素。Style ['-webkit-filter'] = filter; 元素。Style ['filter'] = filter; #original, #changed { 利润率:0 10%; 宽度:30%; 浮:左; 背景:url (http://i.stack.imgur.com/856IQ.png); background-size:封面; padding-bottom: 25%; } < div id = "原始" > < / div > < div id = "改变" > < / div >