I've been able to do this using SVG filter. You can write a filter that multiplies the color of source image with the color you want to change to. In the code snippet below, flood-color is the color we want to change image color to (which is Red in this case.) feComposite tells the filter how we're processing the color. The formula for feComposite with arithmetic is (k1*i1*i2 + k2*i1 + k3*i2 + k4) where i1 and i2 are input colors for in/in2 accordingly. So specifying only k1=1 means it will do just i1*i2, which means multiplying both input colors together.

注意:这只适用于HTML5，因为它使用内联SVG。但我认为，通过将SVG放在一个单独的文件中，您可能能够在较老的浏览器中实现这一点。我还没有尝试过这种方法。

Here's the snippet: <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask1"> <feFlood flood-color="#ff0000" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask1)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask2"> <feFlood flood-color="#00ff00" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask2)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask3"> <feFlood flood-color="#0000ff" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask3)" /> </svg>

最简单的一句话对我很管用:

filter: opacity(0.5) drop-shadow(0 0 0 blue);

您可以将不透明度从0调整到1，以使颜色更亮或更暗。

你可以使用滤镜:色调旋转(Ndeg)，但如果图像是黑白的，色调将永远不会改变。

但是，你可以把它和滤镜结合起来:sepia(100)。这将为图像添加色彩，色彩旋转滤镜可以改变。

Sepia增加了一个相当不饱和的颜色，所以增强一点滤镜:饱和(50);这使得它的颜色更深，色彩旋转可以更好地工作。

然后把它们组合在一起:

滤镜:棕褐色(100)饱和(50)色调旋转(280度)

然后尝试旋转的程度，直到你找到你喜欢的颜色。

是的:)

Surfin' Safari - Blog Archive » CSS Masks WebKit now supports alpha masks in CSS. Masks allow you to overlay the content of a box with a pattern that can be used to knock out portions of that box in the final display. In other words, you can clip to complex shapes based off the alpha of an image. [...] We have introduced new properties to provide Web designers with a lot of control over these masks and how they are applied. The new properties are analogous to the background and border-image properties that already exist. -webkit-mask (background) -webkit-mask-attachment (background-attachment) -webkit-mask-clip (background-clip) -webkit-mask-origin (background-origin) -webkit-mask-image (background-image) -webkit-mask-repeat (background-repeat) -webkit-mask-composite (background-composite) -webkit-mask-box-image (border-image)

I've been able to do this using SVG filter. You can write a filter that multiplies the color of source image with the color you want to change to. In the code snippet below, flood-color is the color we want to change image color to (which is Red in this case.) feComposite tells the filter how we're processing the color. The formula for feComposite with arithmetic is (k1*i1*i2 + k2*i1 + k3*i2 + k4) where i1 and i2 are input colors for in/in2 accordingly. So specifying only k1=1 means it will do just i1*i2, which means multiplying both input colors together.

注意:这只适用于HTML5，因为它使用内联SVG。但我认为，通过将SVG放在一个单独的文件中，您可能能够在较老的浏览器中实现这一点。我还没有尝试过这种方法。

Here's the snippet: <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask1"> <feFlood flood-color="#ff0000" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask1)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask2"> <feFlood flood-color="#00ff00" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask2)" /> </svg> <svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="60" height="90" style="float:left"> <defs> <filter id="colorMask3"> <feFlood flood-color="#0000ff" result="flood" /> <feComposite in="SourceGraphic" in2="flood" operator="arithmetic" k1="1" k2="0" k3="0" k4="0" /> </filter> </defs> <image width="100%" height="100%" xlink:href="http://i.stack.imgur.com/OyP0g.jpg" filter="url(#colorMask3)" /> </svg>

我需要一个特定的颜色，所以滤镜不适合我。

相反，我创建了一个div，利用CSS多个背景图像和线性梯度函数(它自己创建图像)。如果你使用叠加混合模式，你的实际图像将与生成的“渐变”图像混合，包含你想要的颜色(这里，#BADA55)

.colored-image { background-image: linear-gradient(向右，#BADA55， #BADA55)， url("https://i.imgur.com/lYXT8R6.png"); background-blend-mode:覆盖; background-size:包含; 宽度:200 px; 身高:200 px; ｝ < div class = "的" > < / div >