import os
import stat
import shutil

def errorRemoveReadonly(func, path, exc):
    excvalue = exc[1]
    if func in (os.rmdir, os.remove) and excvalue.errno == errno.EACCES:
        # change the file to be readable,writable,executable: 0777
        os.chmod(path, stat.S_IRWXU | stat.S_IRWXG | stat.S_IRWXO)  
        # retry
        func(path)
    else:
        # raiseenter code here

shutil.rmtree(path, ignore_errors=False, onerror=errorRemoveReadonly) 

如果设置了ignore_errors，错误将被忽略;否则，如果设置了onerror，则调用它来处理带有参数(func, path, exc_info)的错误，其中func是os。listdir,操作系统。Remove, or os.rmdir;Path是导致该函数失败的参数;exc_info是由sys.exc_info()返回的元组。如果ignore_errors为false且onerror为None，则会引发异常。在这里输入代码

如果你不想使用shutil模块，你可以使用os模块。

from os import listdir, rmdir, remove
for i in listdir(directoryToRemove):
    os.remove(os.path.join(directoryToRemove, i))
rmdir(directoryToRemove) # Now the directory is empty of files

在我的情况下，删除的唯一方法是使用所有的可能性，因为我的代码应该运行cmd.exe或powershell.exe。如果是你的情况，只需要用下面的代码创建一个函数就可以了:

        #!/usr/bin/env python3

        import shutil
        from os import path, system
        import sys

        # Try to delete the folder ---------------------------------------------
        if (path.isdir(folder)):
            shutil.rmtree(folder, ignore_errors=True)

        if (path.isdir(folder)):
            try:
                system("rd -r {0}".format(folder))
            except Exception as e:
                print("WARN: Failed to delete => {0}".format(e),file=sys.stderr)

        if (path.isdir(self.backup_folder_wrk)):
            try:
                system("rd /s /q {0}".format(folder))
            except Exception as e:
                print("WARN: Failed to delete => {0}".format(e),file=sys.stderr)

        if (path.isdir(folder)):
            print("WARN: Failed to delete {0}".format(folder),file=sys.stderr)
        # -------------------------------------------------------------------------------------

我想添加一个“纯pathlib”方法:

from pathlib import Path
from typing import Union

def del_dir(target: Union[Path, str], only_if_empty: bool = False):
    """
    Delete a given directory and its subdirectories.

    :param target: The directory to delete
    :param only_if_empty: Raise RuntimeError if any file is found in the tree
    """
    target = Path(target).expanduser()
    assert target.is_dir()
    for p in sorted(target.glob('**/*'), reverse=True):
        if not p.exists():
            continue
        p.chmod(0o666)
        if p.is_dir():
            p.rmdir()
        else:
            if only_if_empty:
                raise RuntimeError(f'{p.parent} is not empty!')
            p.unlink()
    target.rmdir()

这依赖于Path是可排序的，长路径总是排在短路径之后，就像str一样。因此，目录将排在文件之前。如果我们反转排序，那么文件就会出现在它们各自的容器之前，所以我们可以简单地一次将它们逐个解除/rmdir链接。

好处:

它不依赖于外部二进制文件:所有东西都使用Python的电池包含的模块(Python >= 3.6) 这意味着它不需要重复启动一个新的子进程来解除链接 它非常快速和简单;你不必实现你自己的递归 它是跨平台的(至少，这是pathlib在Python 3.6中所承诺的;上述操作不能在Windows上运行) 如果需要，可以进行非常细粒度的日志记录，例如，记录每一次删除。

import shutil

shutil.rmtree('/folder_name')

标准库参考:shutil.rmtree。

根据设计，rmtree在包含只读文件的文件夹树上失败。如果您希望删除文件夹而不管它是否包含只读文件，请使用

shutil.rmtree('/folder_name', ignore_errors=True)

来自os.walk()的python文档:

# Delete everything reachable from the directory named in 'top',
# assuming there are no symbolic links.
# CAUTION:  This is dangerous!  For example, if top == '/', it
# could delete all your disk files.
import os
for root, dirs, files in os.walk(top, topdown=False):
    for name in files:
        os.remove(os.path.join(root, name))
    for name in dirs:
        os.rmdir(os.path.join(root, name))