当我试图删除一个非空文件夹时,我得到一个“访问被拒绝”错误。我在尝试中使用了以下命令:os.remove("/folder_name")。
删除一个非空文件夹/目录最有效的方法是什么?
当我试图删除一个非空文件夹时,我得到一个“访问被拒绝”错误。我在尝试中使用了以下命令:os.remove("/folder_name")。
删除一个非空文件夹/目录最有效的方法是什么?
当前回答
在我的情况下,删除的唯一方法是使用所有的可能性,因为我的代码应该运行cmd.exe或powershell.exe。如果是你的情况,只需要用下面的代码创建一个函数就可以了:
#!/usr/bin/env python3
import shutil
from os import path, system
import sys
# Try to delete the folder ---------------------------------------------
if (path.isdir(folder)):
shutil.rmtree(folder, ignore_errors=True)
if (path.isdir(folder)):
try:
system("rd -r {0}".format(folder))
except Exception as e:
print("WARN: Failed to delete => {0}".format(e),file=sys.stderr)
if (path.isdir(self.backup_folder_wrk)):
try:
system("rd /s /q {0}".format(folder))
except Exception as e:
print("WARN: Failed to delete => {0}".format(e),file=sys.stderr)
if (path.isdir(folder)):
print("WARN: Failed to delete {0}".format(folder),file=sys.stderr)
# -------------------------------------------------------------------------------------
其他回答
如果你确定你想要删除整个目录树,并且不再对目录的内容感兴趣,那么爬行整个目录树是愚蠢的…只需从python中调用本机操作系统命令即可。它将更快,更有效,更少的内存消耗。
RMDIR c:\blah /s /q
例如*那晚尼克斯。
rm -rf /home/whatever
在python中,代码看起来像..
import sys
import os
mswindows = (sys.platform == "win32")
def getstatusoutput(cmd):
"""Return (status, output) of executing cmd in a shell."""
if not mswindows:
return commands.getstatusoutput(cmd)
pipe = os.popen(cmd + ' 2>&1', 'r')
text = pipe.read()
sts = pipe.close()
if sts is None: sts = 0
if text[-1:] == '\n': text = text[:-1]
return sts, text
def deleteDir(path):
"""deletes the path entirely"""
if mswindows:
cmd = "RMDIR "+ path +" /s /q"
else:
cmd = "rm -rf "+path
result = getstatusoutput(cmd)
if(result[0]!=0):
raise RuntimeError(result[1])
import os
import stat
import shutil
def errorRemoveReadonly(func, path, exc):
excvalue = exc[1]
if func in (os.rmdir, os.remove) and excvalue.errno == errno.EACCES:
# change the file to be readable,writable,executable: 0777
os.chmod(path, stat.S_IRWXU | stat.S_IRWXG | stat.S_IRWXO)
# retry
func(path)
else:
# raiseenter code here
shutil.rmtree(path, ignore_errors=False, onerror=errorRemoveReadonly)
如果设置了ignore_errors,错误将被忽略;否则,如果设置了onerror,则调用它来处理带有参数(func, path, exc_info)的错误,其中func是os。listdir,操作系统。Remove, or os.rmdir;Path是导致该函数失败的参数;exc_info是由sys.exc_info()返回的元组。如果ignore_errors为false且onerror为None,则会引发异常。在这里输入代码
在python 3.4中,你可以使用:
import pathlib
def delete_folder(pth) :
for sub in pth.iterdir() :
if sub.is_dir() :
delete_folder(sub)
else :
sub.unlink()
pth.rmdir() # if you just want to delete the dir content but not the dir itself, remove this line
其中PTH是一个pathlib。路径实例。不错,但可能不是最快的。
在我的情况下,删除的唯一方法是使用所有的可能性,因为我的代码应该运行cmd.exe或powershell.exe。如果是你的情况,只需要用下面的代码创建一个函数就可以了:
#!/usr/bin/env python3
import shutil
from os import path, system
import sys
# Try to delete the folder ---------------------------------------------
if (path.isdir(folder)):
shutil.rmtree(folder, ignore_errors=True)
if (path.isdir(folder)):
try:
system("rd -r {0}".format(folder))
except Exception as e:
print("WARN: Failed to delete => {0}".format(e),file=sys.stderr)
if (path.isdir(self.backup_folder_wrk)):
try:
system("rd /s /q {0}".format(folder))
except Exception as e:
print("WARN: Failed to delete => {0}".format(e),file=sys.stderr)
if (path.isdir(folder)):
print("WARN: Failed to delete {0}".format(folder),file=sys.stderr)
# -------------------------------------------------------------------------------------
只需一些python 3.5选项就可以完成上面的回答。(我很想在这里找到它们)。
import os
import shutil
from send2trash import send2trash # (shutil delete permanently)
删除空文件夹
root = r"C:\Users\Me\Desktop\test"
for dir, subdirs, files in os.walk(root):
if subdirs == [] and files == []:
send2trash(dir)
print(dir, ": folder removed")
删除包含此文件的also文件夹
elif subdirs == [] and len(files) == 1: # if contains no sub folder and only 1 file
if files[0]== "desktop.ini" or:
send2trash(dir)
print(dir, ": folder removed")
else:
print(dir)
删除只包含.srt或.txt文件的文件夹
elif subdirs == []: #if dir doesn’t contains subdirectory
ext = (".srt", ".txt")
contains_other_ext=0
for file in files:
if not file.endswith(ext):
contains_other_ext=True
if contains_other_ext== 0:
send2trash(dir)
print(dir, ": dir deleted")
删除小于400kb的文件夹:
def get_tree_size(path):
"""Return total size of files in given path and subdirs."""
total = 0
for entry in os.scandir(path):
if entry.is_dir(follow_symlinks=False):
total += get_tree_size(entry.path)
else:
total += entry.stat(follow_symlinks=False).st_size
return total
for dir, subdirs, files in os.walk(root):
If get_tree_size(dir) < 400000: # ≈ 400kb
send2trash(dir)
print(dir, "dir deleted")