我需要做一件非常简单的事情-找出软件键盘是否显示。这在Android中可行吗?
当前回答
在了解了不同分辨率的一些问题后,我决定使用相对大小。正如我所注意到的,可见状态和隐藏状态之间的差异约为30%。所以我决定用0.3代替128 PX。
我添加了这个类监听器来通知任何变化。
这是我的版本
import android.app.*;
import android.graphics.*;
import android.view.*;
public class SoftKeyboardState {
public static final int HIDDEN = 0, VISIBLE = 1;
private OnKeyboardStateChangedListener listener;
private View decorView;
public SoftKeyboardState(Activity activity) {
this.decorView = activity.findViewById(android.R.id.content);
initKeyboardListener();
}
private void initKeyboardListener() {
decorView.getViewTreeObserver().addOnGlobalLayoutListener(
new ViewTreeObserver.OnGlobalLayoutListener(){
private final Rect windowVisibleDisplayFrame = new Rect();
private int lastVisibleDecorViewHeight;
@Override
public void onGlobalLayout() {
decorView.getWindowVisibleDisplayFrame(windowVisibleDisplayFrame);
final int visibleDecorViewHeight = windowVisibleDisplayFrame.height();
if (lastVisibleDecorViewHeight != 0) {
if ((lastVisibleDecorViewHeight > visibleDecorViewHeight) && (lastVisibleDecorViewHeight / visibleDecorViewHeight >= 0.3f)) {
// visible
if (listener != null)listener.onKeyboardStateChanged(VISIBLE);
} else if ((lastVisibleDecorViewHeight < visibleDecorViewHeight) && (visibleDecorViewHeight / lastVisibleDecorViewHeight >= 0.3f)) {
// hidden
if (listener != null)listener.onKeyboardStateChanged(HIDDEN);
}
}
lastVisibleDecorViewHeight = visibleDecorViewHeight;
}
});
}
public void setOnKeyboardStateChangedListener(OnKeyboardStateChangedListener listener) {
this.listener = listener;
}
public interface OnKeyboardStateChangedListener {
public void onKeyboardStateChanged(int state);
}
}
其他回答
2012年1月25日新增答案
写了下面的答案后,有人告诉我ViewTreeObserver和其他api的存在,这些api从版本1开始就潜伏在SDK中。
而不是需要一个自定义的布局类型,一个更简单的解决方案是给你的活动的根视图一个已知的ID,比如@+ ID /activityRoot,钩子一个GlobalLayoutListener到ViewTreeObserver,并从那里计算你的活动的视图根和窗口大小之间的大小差:
final View activityRootView = findViewById(R.id.activityRoot);
activityRootView.getViewTreeObserver().addOnGlobalLayoutListener(new OnGlobalLayoutListener() {
@Override
public void onGlobalLayout() {
int heightDiff = activityRootView.getRootView().getHeight() - activityRootView.getHeight();
if (heightDiff > dpToPx(this, 200)) { // if more than 200 dp, it's probably a keyboard...
// ... do something here
}
}
});
使用一个实用程序,如:
public static float dpToPx(Context context, float valueInDp) {
DisplayMetrics metrics = context.getResources().getDisplayMetrics();
return TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP, valueInDp, metrics);
}
简单!
注意: 你的应用程序必须在Android Manifest中设置这个标志Android:windowSoftInputMode=" adjuststresize "否则上述解决方案将无法工作。
原来的答案
是的,这是可能的,但它比应该的要难得多。
如果我需要关心键盘何时出现和消失(这是相当经常的),那么我所做的是自定义我的顶级布局类为一个覆盖onMeasure()。基本逻辑是,如果布局发现自己填充的面积明显小于窗口的总面积,那么可能显示了软键盘。
import android.app.Activity;
import android.content.Context;
import android.graphics.Rect;
import android.util.AttributeSet;
import android.widget.LinearLayout;
/*
* LinearLayoutThatDetectsSoftKeyboard - a variant of LinearLayout that can detect when
* the soft keyboard is shown and hidden (something Android can't tell you, weirdly).
*/
public class LinearLayoutThatDetectsSoftKeyboard extends LinearLayout {
public LinearLayoutThatDetectsSoftKeyboard(Context context, AttributeSet attrs) {
super(context, attrs);
}
public interface Listener {
public void onSoftKeyboardShown(boolean isShowing);
}
private Listener listener;
public void setListener(Listener listener) {
this.listener = listener;
}
@Override
protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) {
int height = MeasureSpec.getSize(heightMeasureSpec);
Activity activity = (Activity)getContext();
Rect rect = new Rect();
activity.getWindow().getDecorView().getWindowVisibleDisplayFrame(rect);
int statusBarHeight = rect.top;
int screenHeight = activity.getWindowManager().getDefaultDisplay().getHeight();
int diff = (screenHeight - statusBarHeight) - height;
if (listener != null) {
listener.onSoftKeyboardShown(diff>128); // assume all soft keyboards are at least 128 pixels high
}
super.onMeasure(widthMeasureSpec, heightMeasureSpec);
}
}
然后在活动课上…
public class MyActivity extends Activity implements LinearLayoutThatDetectsSoftKeyboard.Listener {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
...
LinearLayoutThatDetectsSoftKeyboard mainLayout = (LinearLayoutThatDetectsSoftKeyboard)findViewById(R.id.main);
mainLayout.setListener(this);
...
}
@Override
public void onSoftKeyboardShown(boolean isShowing) {
// do whatever you need to do here
}
...
}
我发现@Reuben_Scratton的方法与@Yogesh的方法的组合似乎效果最好。将他们的方法结合起来会产生如下结果:
final View activityRootView = findViewById(R.id.activityRoot);
activityRootView.getViewTreeObserver().addOnGlobalLayoutListener(new OnGlobalLayoutListener() {
@Override
public void onGlobalLayout() {
if (getResources().getConfiguration().keyboardHidden == Configuration.KEYBOARDHIDDEN_NO) { // Check if keyboard is not hidden
// ... do something here
}
}
});
这些解决方案都不适用于棒棒糖。在Lollipop activityRootView.getRootView(). getheight()包含按钮栏的高度,而测量视图则不包含。我已经采用了上面最好/最简单的解决方案来处理棒棒糖。
final View activityRootView = findViewById(R.id.activityRoot);
activityRootView.getViewTreeObserver().addOnGlobalLayoutListener(new OnGlobalLayoutListener() {
@Override
public void onGlobalLayout() {
Rect r = new Rect();
//r will be populated with the coordinates of your view that area still visible.
activityRootView.getWindowVisibleDisplayFrame(r);
int heightDiff = activityRootView.getRootView().getHeight() - (r.bottom - r.top);
Resources res = getResources();
// The status bar is 25dp, use 50dp for assurance
float maxDiff =
TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP, 50, res.getDisplayMetrics());
//Lollipop includes button bar in the root. Add height of button bar (48dp) to maxDiff
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP) {
float buttonBarHeight =
TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP, 48, res.getDisplayMetrics());
maxDiff += buttonBarHeight;
}
if (heightDiff > maxDiff) { // if more than 100 pixels, its probably a keyboard...
...do something here
}
}
});
有一种直接的方法可以找出答案。而且,它不需要任何布局更改。 所以,它也可以在沉浸式全屏模式下工作。 诀窍在于,您尝试隐藏或显示软键盘,并捕获尝试的结果。 没有恐慌,这并不真正显示或隐藏键盘。我们只要求状态。 为了保持最新,您可以简单地重复操作,例如,每200毫秒,使用处理器。 您可以在这里找到一个实现:https://stackoverflow.com/a/27567074/2525452
我知道如何准确地确定键盘是否隐藏。
public int getStatusBarHeight() {
int result = 0;
int resourceId = getResources().getIdentifier("status_bar_height", "dimen", "android");
if (resourceId > 0) {
result = getResources().getDimensionPixelSize(resourceId);
}
return result;
}
public int getNavigationBarHeight() {
int result = 0;
int resourceId = getResources().getIdentifier("navigation_bar_height", "dimen", "android");
if (resourceId > 0) {
result = getResources().getDimensionPixelSize(resourceId);
}
return result;
}
public boolean isKeyboardHidden() {
int delta = mRootView.getRootView().getHeight() - mRootView.getHeight() - getNavigationBarHeight() - getStatusBarHeight()
- getSupportActionBar().getHeight();
return delta <= 0;
}
这适用于平板电脑。当导航栏水平显示时。
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