我使用Java 8 lambdas的解决方案：

public static <T extends Throwable> T assertThrows(Class<T> expected, ThrowingRunnable action) throws Throwable {
    try {
        action.run();
        Assert.fail("Did not throw expected " + expected.getSimpleName());
        return null; // never actually
    } catch (Throwable actual) {
        if (!expected.isAssignableFrom(actual.getClass())) { // runtime '!(actual instanceof expected)'
            System.err.println("Threw " + actual.getClass().getSimpleName() 
                               + ", which is not a subtype of expected " 
                               + expected.getSimpleName());
            throw actual; // throw the unexpected Throwable for maximum transparency
        } else {
            return (T) actual; // return the expected Throwable for further examination
        }
    }
}

您必须定义FunctionalInterface，因为Runnable没有声明所需的抛出。

@FunctionalInterface
public interface ThrowingRunnable {
    void run() throws Throwable;
}

方法如下：

class CustomException extends Exception {
    public final String message;
    public CustomException(final String message) { this.message = message;}
}
CustomException e = assertThrows(CustomException.class, () -> {
    throw new CustomException("Lorem Ipsum");
});
assertEquals("Lorem Ipsum", e.message);

try {
    my method();
    fail( "This method must thrwo" );
} catch (Exception ex) {
    assertThat(ex.getMessage()).isEqual(myErrormsg);
}

我们可以在必须返回异常的方法之后使用断言失败：

try{
   methodThatThrowMyException();
   Assert.fail("MyException is not thrown !");
} catch (final Exception exception) {
   // Verify if the thrown exception is instance of MyException, otherwise throws an assert failure
   assertTrue(exception instanceof MyException, "An exception other than MyException is thrown !");
   // In case of verifying the error message
   MyException myException = (MyException) exception;
   assertEquals("EXPECTED ERROR MESSAGE", myException.getMessage());
}

使用Java 8，您可以创建一个方法，将要检查的代码和预期异常作为参数：

private void expectException(Runnable r, Class<?> clazz) { 
    try {
      r.run();
      fail("Expected: " + clazz.getSimpleName() + " but not thrown");
    } catch (Exception e) {
      if (!clazz.isInstance(e)) fail("Expected: " + clazz.getSimpleName() + " but " + e.getClass().getSimpleName() + " found", e);
    }
  }

然后在测试中：

expectException(() -> list.sublist(0, 2).get(2), IndexOutOfBoundsException.class);

优点：

不依赖任何库本地化检查-更精确，如果需要，允许在一个测试中有多个这样的断言易于使用

为了解决同样的问题，我设立了一个小项目：http://code.google.com/p/catch-exception/

使用这个小助手，您可以编写

verifyException(foo, IndexOutOfBoundsException.class).doStuff();

这比JUnit 4.7的ExpectedException规则更详细。与skaffman提供的解决方案相比，您可以指定期望在哪行代码中出现异常。我希望这有帮助。

只需制作一个可以关闭和打开的Matcher，如下所示：

public class ExceptionMatcher extends BaseMatcher<Throwable> {
    private boolean active = true;
    private Class<? extends Throwable> throwable;

    public ExceptionMatcher(Class<? extends Throwable> throwable) {
        this.throwable = throwable;
    }

    public void on() {
        this.active = true;
    }

    public void off() {
        this.active = false;
    }

    @Override
    public boolean matches(Object object) {
        return active && throwable.isAssignableFrom(object.getClass());
    }

    @Override
    public void describeTo(Description description) {
        description.appendText("not the covered exception type");
    }
}

要使用它：

add public ExpectedException exception=ExpectedException.none（）；，那么：

ExceptionMatcher exMatch = new ExceptionMatcher(MyException.class);
exception.expect(exMatch);
someObject.somethingThatThrowsMyException();
exMatch.off();