如何使用JUnit来测试某些代码是否抛出异常？
我当然可以这样做：
@Test
public void testFooThrowsIndexOutOfBoundsException() {
boolean thrown = false;
try {
foo.doStuff();
} catch (IndexOutOfBoundsException e) {
thrown = true;
}
assertTrue(thrown);
}
我记得，对于这类情况，有一个注释或Assert.xyz之类的东西远没有JUnit那么笨拙，更符合JUnit的精神。
当前回答
我使用Java 8 lambdas的解决方案：
public static <T extends Throwable> T assertThrows(Class<T> expected, ThrowingRunnable action) throws Throwable {
try {
action.run();
Assert.fail("Did not throw expected " + expected.getSimpleName());
return null; // never actually
} catch (Throwable actual) {
if (!expected.isAssignableFrom(actual.getClass())) { // runtime '!(actual instanceof expected)'
System.err.println("Threw " + actual.getClass().getSimpleName()
+ ", which is not a subtype of expected "
+ expected.getSimpleName());
throw actual; // throw the unexpected Throwable for maximum transparency
} else {
return (T) actual; // return the expected Throwable for further examination
}
}
}
您必须定义FunctionalInterface，因为Runnable没有声明所需的抛出。
@FunctionalInterface
public interface ThrowingRunnable {
void run() throws Throwable;
}
方法如下：
class CustomException extends Exception {
public final String message;
public CustomException(final String message) { this.message = message;}
}
CustomException e = assertThrows(CustomException.class, () -> {
throw new CustomException("Lorem Ipsum");
});
assertEquals("Lorem Ipsum", e.message);
其他回答
我使用Java 8 lambdas的解决方案：
public static <T extends Throwable> T assertThrows(Class<T> expected, ThrowingRunnable action) throws Throwable {
try {
action.run();
Assert.fail("Did not throw expected " + expected.getSimpleName());
return null; // never actually
} catch (Throwable actual) {
if (!expected.isAssignableFrom(actual.getClass())) { // runtime '!(actual instanceof expected)'
System.err.println("Threw " + actual.getClass().getSimpleName()
+ ", which is not a subtype of expected "
+ expected.getSimpleName());
throw actual; // throw the unexpected Throwable for maximum transparency
} else {
return (T) actual; // return the expected Throwable for further examination
}
}
}
您必须定义FunctionalInterface，因为Runnable没有声明所需的抛出。
@FunctionalInterface
public interface ThrowingRunnable {
void run() throws Throwable;
}
方法如下：
class CustomException extends Exception {
public final String message;
public CustomException(final String message) { this.message = message;}
}
CustomException e = assertThrows(CustomException.class, () -> {
throw new CustomException("Lorem Ipsum");
});
assertEquals("Lorem Ipsum", e.message);
我会使用assertThatTownBy
@Test
public void testFooThrowsIndexOutOfBoundsException() {
assertThatThrownBy(() -> doStuff()).isInstanceOf(IndexOutOfBoundsException.class)
}
有两种编写测试用例的方法
使用方法引发的异常来注释测试。类似于@Test（预期=IndexOutOfBoundsException.class）您可以使用try-catch块在测试类中捕获异常，并对从测试类中的方法抛出的消息进行断言。尝试{}catch（从方法e抛出的异常）{assertEquals（“message”，即getmessage（））；}
我希望这能回答你的问题快乐学习。。。
我建议库assertj核心处理junit测试中的异常
在java 8中，如下所示：
//given
//when
Throwable throwable = catchThrowable(() -> anyService.anyMethod(object));
//then
AnyException anyException = (AnyException) throwable;
assertThat(anyException.getMessage()).isEqualTo("........");
assertThat(exception.getCode()).isEqualTo(".......);
这样如何：捕获一个非常普通的异常，确保它从catch块中取出，然后断言该异常的类是您期望的。如果a）异常类型错误（例如，如果您使用了空指针），并且b）该异常从未被抛出，则该断言将失败。
public void testFooThrowsIndexOutOfBoundsException() {
Throwable e = null;
try {
foo.doStuff();
} catch (Throwable ex) {
e = ex;
}
assertTrue(e instanceof IndexOutOfBoundsException);
}
