有没有办法在Swift中获得设备型号名称(iPhone 4S, iPhone 5, iPhone 5S等)?
我知道有一个名为UIDevice.currentDevice()的属性。模型，但它只返回设备类型(iPod touch, iPhone, iPad, iPhone模拟器等)。
我也知道在Objective-C中使用以下方法可以轻松完成:
#import <sys/utsname.h>
struct utsname systemInfo;
uname(&systemInfo);
NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
encoding:NSUTF8StringEncoding];
但是我正在Swift中开发我的iPhone应用程序，所以有人可以帮助我用等效的方法在Swift中解决这个问题吗?
当前回答
对于swift4.0及以上使用以下代码:
let udid = UIDevice.current.identifierForVendor?.uuidString
let name = UIDevice.current.name
let version = UIDevice.current.systemVersion
let modelName = UIDevice.current.model
let osName = UIDevice.current.systemName
let localized = UIDevice.current.localizedModel
print(udid ?? "")
print(name)
print(version)
print(modelName)
print(osName)
print(localized)
其他回答
当你使用Swift 3时，接受的答案有一些问题! 这个答案(灵感来自NAZIK)适用于Swift 3和新款iPhone:
import UIKit
public extension UIDevice {
var modelName: String {
#if (arch(i386) || arch(x86_64)) && os(iOS)
let DEVICE_IS_SIMULATOR = true
#else
let DEVICE_IS_SIMULATOR = false
#endif
var machineString = String()
if DEVICE_IS_SIMULATOR == true
{
if let dir = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
machineString = dir
}
}
else {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
machineString = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8 , value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
}
switch machineString {
case "iPod4,1": return "iPod Touch 4G"
case "iPod5,1": return "iPod Touch 5G"
case "iPod7,1": return "iPod Touch 6G"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone8,4": return "iPhone SE"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone 9,4": return "iPhone 7 Plus"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro (9.7 inch)"
case "iPad6,7", "iPad6,8": return "iPad Pro (12.9 inch)"
case "AppleTV5,3": return "Apple TV"
default: return machineString
}
}
}
这个Swift 3.0示例将当前设备模型作为枚举常量返回(以避免与字符串字面值直接比较)。enum的原始值是一个包含人类可读的iOS设备名称的字符串。因为它是Swift，所以认可的设备列表只包括最新的机型，足以支持包含Swift的iOS版本。下面的使用示例利用了这个答案末尾的实现:
switch UIDevice().type {
case .iPhone5:
print("No TouchID sensor")
case .iPhone5S:
fallthrough
case .iPhone6:
fallthrough
case .iPhone6plus:
fallthrough
case .iPad_Pro9_7:
fallthrough
case .iPad_Pro12_9:
fallthrough
case .iPhone7:
fallthrough
case .iPhone7plus:
print("Put your thumb on the " +
UIDevice().type.rawValue + " TouchID sensor")
case .unrecognized:
print("Device model unrecognized");
default:
print(UIDevice().type.rawValue + " not supported by this app");
}
你的应用应该保持最新的新设备发布，以及当苹果为同一设备家族添加新型号时。例如，iPhone3、1 iPhone3、2 iPhone3、4都是“iPhone 4”。避免编写不考虑新型号的代码，这样你的算法就不会意外地配置失败或对新设备做出响应。你可以参考这个维护列表的iOS设备型号#更新你的应用程序在战略时刻。
iOS includes device-independent interfaces to detect hardware capabilities and parameters such as screen size. The generalized interfaces Apple provides are usually the safest, best supported mechanisms to dynamically adapt an app's behavior to different hardware. Nevertheless, the following code can be useful for prototyping, debugging, testing, or any time code needs to target a specific device family. This technique can also be useful to describe the current device by its common/publicly recognized name.
斯威夫特3
// 1. Declare outside class definition (or in its own file).
// 2. UIKit must be included in file where this code is added.
// 3. Extends UIDevice class, thus is available anywhere in app.
//
// Usage example:
//
// if UIDevice().type == .simulator {
// print("You're running on the simulator... boring!")
// } else {
// print("Wow! Running on a \(UIDevice().type.rawValue)")
// }
import UIKit
public enum Model : String {
case simulator = "simulator/sandbox",
iPod1 = "iPod 1",
iPod2 = "iPod 2",
iPod3 = "iPod 3",
iPod4 = "iPod 4",
iPod5 = "iPod 5",
iPad2 = "iPad 2",
iPad3 = "iPad 3",
iPad4 = "iPad 4",
iPhone4 = "iPhone 4",
iPhone4S = "iPhone 4S",
iPhone5 = "iPhone 5",
iPhone5S = "iPhone 5S",
iPhone5C = "iPhone 5C",
iPadMini1 = "iPad Mini 1",
iPadMini2 = "iPad Mini 2",
iPadMini3 = "iPad Mini 3",
iPadAir1 = "iPad Air 1",
iPadAir2 = "iPad Air 2",
iPadPro9_7 = "iPad Pro 9.7\"",
iPadPro9_7_cell = "iPad Pro 9.7\" cellular",
iPadPro10_5 = "iPad Pro 10.5\"",
iPadPro10_5_cell = "iPad Pro 10.5\" cellular",
iPadPro12_9 = "iPad Pro 12.9\"",
iPadPro12_9_cell = "iPad Pro 12.9\" cellular",
iPhone6 = "iPhone 6",
iPhone6plus = "iPhone 6 Plus",
iPhone6S = "iPhone 6S",
iPhone6Splus = "iPhone 6S Plus",
iPhoneSE = "iPhone SE",
iPhone7 = "iPhone 7",
iPhone7plus = "iPhone 7 Plus",
iPhone8 = "iPhone 8",
iPhone8plus = "iPhone 8 Plus",
iPhoneX = "iPhone X",
iPhoneXS = "iPhone XS",
iPhoneXSmax = "iPhone XS Max",
iPhoneXR = "iPhone XR",
iPhone11 = "iPhone 11",
iPhone11Pro = "iPhone 11 Pro",
iPhone11ProMax = "iPhone 11 Pro Max",
unrecognized = "?unrecognized?"
}
public extension UIDevice {
public var type: Model {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafePointer(to: &systemInfo.machine) {
$0.withMemoryRebound(to: CChar.self, capacity: 1) {
ptr in String.init(validatingUTF8: ptr)
}
}
var modelMap : [ String : Model ] = [
"i386" : .simulator,
"x86_64" : .simulator,
"iPod1,1" : .iPod1,
"iPod2,1" : .iPod2,
"iPod3,1" : .iPod3,
"iPod4,1" : .iPod4,
"iPod5,1" : .iPod5,
"iPad2,1" : .iPad2,
"iPad2,2" : .iPad2,
"iPad2,3" : .iPad2,
"iPad2,4" : .iPad2,
"iPad2,5" : .iPadMini1,
"iPad2,6" : .iPadMini1,
"iPad2,7" : .iPadMini1,
"iPhone3,1" : .iPhone4,
"iPhone3,2" : .iPhone4,
"iPhone3,3" : .iPhone4,
"iPhone4,1" : .iPhone4S,
"iPhone5,1" : .iPhone5,
"iPhone5,2" : .iPhone5,
"iPhone5,3" : .iPhone5C,
"iPhone5,4" : .iPhone5C,
"iPad3,1" : .iPad3,
"iPad3,2" : .iPad3,
"iPad3,3" : .iPad3,
"iPad3,4" : .iPad4,
"iPad3,5" : .iPad4,
"iPad3,6" : .iPad4,
"iPhone6,1" : .iPhone5S,
"iPhone6,2" : .iPhone5S,
"iPad4,1" : .iPadAir1,
"iPad4,2" : .iPadAir2,
"iPad4,4" : .iPadMini2,
"iPad4,5" : .iPadMini2,
"iPad4,6" : .iPadMini2,
"iPad4,7" : .iPadMini3,
"iPad4,8" : .iPadMini3,
"iPad4,9" : .iPadMini3,
"iPad6,3" : .iPadPro9_7,
"iPad6,11" : .iPadPro9_7,
"iPad6,4" : .iPadPro9_7_cell,
"iPad6,12" : .iPadPro9_7_cell,
"iPad6,7" : .iPadPro12_9,
"iPad6,8" : .iPadPro12_9_cell,
"iPad7,3" : .iPadPro10_5,
"iPad7,4" : .iPadPro10_5_cell,
"iPhone7,1" : .iPhone6plus,
"iPhone7,2" : .iPhone6,
"iPhone8,1" : .iPhone6S,
"iPhone8,2" : .iPhone6Splus,
"iPhone8,4" : .iPhoneSE,
"iPhone9,1" : .iPhone7,
"iPhone9,2" : .iPhone7plus,
"iPhone9,3" : .iPhone7,
"iPhone9,4" : .iPhone7plus,
"iPhone10,1" : .iPhone8,
"iPhone10,2" : .iPhone8plus,
"iPhone10,3" : .iPhoneX,
"iPhone10,6" : .iPhoneX,
"iPhone11,2" : .iPhoneXS,
"iPhone11,4" : .iPhoneXSmax,
"iPhone11,6" : .iPhoneXSmax,
"iPhone11,8" : .iPhoneXR,
"iPhone12,1" : .iPhone11,
"iPhone12,3" : .iPhone11Pro,
"iPhone12,5" : .iPhone11ProMax
]
if let model = modelMap[String.init(validatingUTF8: modelCode!)!] {
return model
}
return Model.unrecognized
}
}
如果你不想每次苹果向设备家族添加新型号时都更新你的代码，可以使用下面的方法只返回型号代码。
func platform() -> String {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafeMutablePointer(&systemInfo.machine) {
ptr in String.fromCString(UnsafePointer<CChar>(ptr))
}
return String.fromCString(modelCode!)!
}
Swift 3.0或更高版本
import UIKit
class ViewController: UIViewController {
let device = UIDevice.current
override func viewDidLoad() {
super.viewDidLoad()
let model = device.model
print(model) // e.g. "iPhone"
let modelName = device.modelName
print(modelName) // e.g. "iPhone 6" /* see the extension */
let deviceName = device.name
print(deviceName) // e.g. "My iPhone"
let systemName = device.systemName
print(systemName) // e.g. "iOS"
let systemVersion = device.systemVersion
print(systemVersion) // e.g. "10.3.2"
if let identifierForVendor = device.identifierForVendor {
print(identifierForVendor) // e.g. "E1X2XX34-5X6X-7890-123X-XXX456C78901"
}
}
}
并添加以下扩展
extension UIDevice {
var modelName: String {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad6,11", "iPad6,12": return "iPad 5"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro 9.7 Inch"
case "iPad6,7", "iPad6,8": return "iPad Pro 12.9 Inch"
case "iPad7,1", "iPad7,2": return "iPad Pro 12.9 Inch 2. Generation"
case "iPad7,3", "iPad7,4": return "iPad Pro 10.5 Inch"
case "AppleTV5,3": return "Apple TV"
case "i386", "x86_64": return "Simulator"
default: return identifier
}
}
}
我在UIDevice上做了这个“纯Swift”扩展。
如果你正在寻找一个更优雅的解决方案，你可以使用我在GitHub上发布的µ-框架DeviceKit(也可以通过CocoaPods, Carthage和Swift Package Manager获得)。
代码如下:
import UIKit
public extension UIDevice {
static let modelName: String = {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
func mapToDevice(identifier: String) -> String { // swiftlint:disable:this cyclomatic_complexity
#if os(iOS)
switch identifier {
case "iPod5,1": return "iPod touch (5th generation)"
case "iPod7,1": return "iPod touch (6th generation)"
case "iPod9,1": return "iPod touch (7th generation)"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone10,1", "iPhone10,4": return "iPhone 8"
case "iPhone10,2", "iPhone10,5": return "iPhone 8 Plus"
case "iPhone10,3", "iPhone10,6": return "iPhone X"
case "iPhone11,2": return "iPhone XS"
case "iPhone11,4", "iPhone11,6": return "iPhone XS Max"
case "iPhone11,8": return "iPhone XR"
case "iPhone12,1": return "iPhone 11"
case "iPhone12,3": return "iPhone 11 Pro"
case "iPhone12,5": return "iPhone 11 Pro Max"
case "iPhone13,1": return "iPhone 12 mini"
case "iPhone13,2": return "iPhone 12"
case "iPhone13,3": return "iPhone 12 Pro"
case "iPhone13,4": return "iPhone 12 Pro Max"
case "iPhone14,4": return "iPhone 13 mini"
case "iPhone14,5": return "iPhone 13"
case "iPhone14,2": return "iPhone 13 Pro"
case "iPhone14,3": return "iPhone 13 Pro Max"
case "iPhone14,7": return "iPhone 14"
case "iPhone14,8": return "iPhone 14 Plus"
case "iPhone15,2": return "iPhone 14 Pro"
case "iPhone15,3": return "iPhone 14 Pro Max"
case "iPhone8,4": return "iPhone SE"
case "iPhone12,8": return "iPhone SE (2nd generation)"
case "iPhone14,6": return "iPhone SE (3rd generation)"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4": return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad (3rd generation)"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad (4th generation)"
case "iPad6,11", "iPad6,12": return "iPad (5th generation)"
case "iPad7,5", "iPad7,6": return "iPad (6th generation)"
case "iPad7,11", "iPad7,12": return "iPad (7th generation)"
case "iPad11,6", "iPad11,7": return "iPad (8th generation)"
case "iPad12,1", "iPad12,2": return "iPad (9th generation)"
case "iPad13,18", "iPad13,19": return "iPad (10th generation)"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad11,3", "iPad11,4": return "iPad Air (3rd generation)"
case "iPad13,1", "iPad13,2": return "iPad Air (4th generation)"
case "iPad13,16", "iPad13,17": return "iPad Air (5th generation)"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad mini 3"
case "iPad5,1", "iPad5,2": return "iPad mini 4"
case "iPad11,1", "iPad11,2": return "iPad mini (5th generation)"
case "iPad14,1", "iPad14,2": return "iPad mini (6th generation)"
case "iPad6,3", "iPad6,4": return "iPad Pro (9.7-inch)"
case "iPad7,3", "iPad7,4": return "iPad Pro (10.5-inch)"
case "iPad8,1", "iPad8,2", "iPad8,3", "iPad8,4": return "iPad Pro (11-inch) (1st generation)"
case "iPad8,9", "iPad8,10": return "iPad Pro (11-inch) (2nd generation)"
case "iPad13,4", "iPad13,5", "iPad13,6", "iPad13,7": return "iPad Pro (11-inch) (3rd generation)"
case "iPad14,3", "iPad14,4": return "iPad Pro (11-inch) (4th generation)"
case "iPad6,7", "iPad6,8": return "iPad Pro (12.9-inch) (1st generation)"
case "iPad7,1", "iPad7,2": return "iPad Pro (12.9-inch) (2nd generation)"
case "iPad8,5", "iPad8,6", "iPad8,7", "iPad8,8": return "iPad Pro (12.9-inch) (3rd generation)"
case "iPad8,11", "iPad8,12": return "iPad Pro (12.9-inch) (4th generation)"
case "iPad13,8", "iPad13,9", "iPad13,10", "iPad13,11":return "iPad Pro (12.9-inch) (5th generation)"
case "iPad14,5", "iPad14,6": return "iPad Pro (12.9-inch) (6th generation)"
case "AppleTV5,3": return "Apple TV"
case "AppleTV6,2": return "Apple TV 4K"
case "AudioAccessory1,1": return "HomePod"
case "AudioAccessory5,1": return "HomePod mini"
case "i386", "x86_64", "arm64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "iOS"))"
default: return identifier
}
#elseif os(tvOS)
switch identifier {
case "AppleTV5,3": return "Apple TV 4"
case "AppleTV6,2": return "Apple TV 4K"
case "i386", "x86_64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "tvOS"))"
default: return identifier
}
#endif
}
return mapToDevice(identifier: identifier)
}()
}
你这样称呼它:
let modelName = UIDevice.modelName
对于真实的设备，它返回例如:“iPad Pro(12.9英寸)(第五代)”，对于模拟器，它返回例如。模拟式iPad Pro(12.9英寸)(第五代)
下面是模型参考:
https://theiphonewiki.com/wiki/Models https://theiphonewiki.com/wiki/BORD
