有没有办法在Swift中获得设备型号名称(iPhone 4S, iPhone 5, iPhone 5S等)?
我知道有一个名为UIDevice.currentDevice()的属性。模型，但它只返回设备类型(iPod touch, iPhone, iPad, iPhone模拟器等)。
我也知道在Objective-C中使用以下方法可以轻松完成:
#import <sys/utsname.h>
struct utsname systemInfo;
uname(&systemInfo);
NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
encoding:NSUTF8StringEncoding];
但是我正在Swift中开发我的iPhone应用程序，所以有人可以帮助我用等效的方法在Swift中解决这个问题吗?
当前回答
在Swift 3中是这样的
UIDevice.current.model
其他回答
下面是获取硬件字符串的代码，但是您需要比较这些硬件字符串才能知道它是哪个设备。我已经创建了一个类，包含几乎所有的设备字符串(我们保持字符串最新的新设备)。使用方便，请检查
吉hub /恶魔大师
Objective-C: GitHub/DeviceUtil
public func hardwareString() -> String {
var name: [Int32] = [CTL_HW, HW_MACHINE]
var size: Int = 2
sysctl(&name, 2, nil, &size, &name, 0)
var hw_machine = [CChar](count: Int(size), repeatedValue: 0)
sysctl(&name, 2, &hw_machine, &size, &name, 0)
let hardware: String = String.fromCString(hw_machine)!
return hardware
}
Swift 3.0或更高版本
import UIKit
class ViewController: UIViewController {
let device = UIDevice.current
override func viewDidLoad() {
super.viewDidLoad()
let model = device.model
print(model) // e.g. "iPhone"
let modelName = device.modelName
print(modelName) // e.g. "iPhone 6" /* see the extension */
let deviceName = device.name
print(deviceName) // e.g. "My iPhone"
let systemName = device.systemName
print(systemName) // e.g. "iOS"
let systemVersion = device.systemVersion
print(systemVersion) // e.g. "10.3.2"
if let identifierForVendor = device.identifierForVendor {
print(identifierForVendor) // e.g. "E1X2XX34-5X6X-7890-123X-XXX456C78901"
}
}
}
并添加以下扩展
extension UIDevice {
var modelName: String {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad6,11", "iPad6,12": return "iPad 5"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro 9.7 Inch"
case "iPad6,7", "iPad6,8": return "iPad Pro 12.9 Inch"
case "iPad7,1", "iPad7,2": return "iPad Pro 12.9 Inch 2. Generation"
case "iPad7,3", "iPad7,4": return "iPad Pro 10.5 Inch"
case "AppleTV5,3": return "Apple TV"
case "i386", "x86_64": return "Simulator"
default: return identifier
}
}
}
如果你不想每次苹果向设备家族添加新型号时都更新你的代码，可以使用下面的方法只返回型号代码。
func platform() -> String {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafeMutablePointer(&systemInfo.machine) {
ptr in String.fromCString(UnsafePointer<CChar>(ptr))
}
return String.fromCString(modelCode!)!
}
struct DeviceType {
static let IS_IPHONE_4_OR_LESS = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH < 568
static let IS_IPHONE_5 = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH == 568
static let IS_IPHONE_6 = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH == 667
static let IS_IPHONE_6P = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH == 736
static let IS_IPAD = UIDevice.current.userInterfaceIdiom == .pad && Constants.SCREEN_MAX_LENGTH == 1024
}
我的简单解决方案是按设备分组，支持新设备iPhone 8和iPhone X在Swift 3:
public extension UIDevice {
var modelName: String {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
switch identifier {
case "iPhone3,1", "iPhone3,2", "iPhone3,3", "iPhone4,1":
return "iPhone 4"
case "iPhone5,1", "iPhone5,2", "iPhone5,3", "iPhone5,4", "iPhone6,1", "iPhone6,2", "iPhone8,4":
return "iPhone 5"
case "iPhone7,2", "iPhone8,1", "iPhone9,1", "iPhone9,3", "iPhone10,1", "iPhone10,4":
return "iPhone 6,7,8"
case "iPhone7,1", "iPhone8,2", "iPhone9,2", "iPhone9,4", "iPhone10,2", "iPhone10,5":
return "iPhone Plus"
case "iPhone10,3", "iPhone10,6":
return "iPhone X"
case "i386", "x86_64":
return "Simulator"
default:
return identifier
}
}
}
和使用:
switch UIDevice.current.modelName {
case "iPhone 4":
case "iPhone 5":
case "iPhone 6,7,8":
case "iPhone Plus":
case "iPhone X":
case "Simulator":
default:
}
