有没有办法在Swift中获得设备型号名称(iPhone 4S, iPhone 5, iPhone 5S等)?

我知道有一个名为UIDevice.currentDevice()的属性。模型,但它只返回设备类型(iPod touch, iPhone, iPad, iPhone模拟器等)。

我也知道在Objective-C中使用以下方法可以轻松完成:

#import <sys/utsname.h>

struct utsname systemInfo;
uname(&systemInfo);

NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
                          encoding:NSUTF8StringEncoding];

但是我正在Swift中开发我的iPhone应用程序,所以有人可以帮助我用等效的方法在Swift中解决这个问题吗?


当前回答

在Swift 3中是这样的

 UIDevice.current.model

其他回答

struct DeviceType {
        static let IS_IPHONE_4_OR_LESS = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH < 568
        static let IS_IPHONE_5 = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH == 568
        static let IS_IPHONE_6 = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH == 667
        static let IS_IPHONE_6P = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH == 736
        static let IS_IPAD = UIDevice.current.userInterfaceIdiom == .pad && Constants.SCREEN_MAX_LENGTH == 1024
    }

我最近在开发这个swift包:

https://github.com/EmilioOjeda/Device

我认为它的主要优点是代码生成的。所以每当一个新的Xcode版本发布时,我所要做的就是运行一个脚本并更新swift包。

代码生成是如何工作的?

它从Xcode的数据库(每个平台)读取并解析设备的数据,以识别正在运行的设备,并为其提供信息。

这是用法……

import Device
// or => 'import iPhoneOSDevice' <= iPhoneOS-only device data
// or => 'import tvOSDevice' <= tvOS-only device data

// A representation of the running device - it could be either actual or simulated.
let device = Device.current

// It is 'true' when running on a physical device.
_ = device.isDevice

// It is 'true' when running on a simulator instance.
_ = device.isSimulator

// It is 'true' when the device does not match either simulators or physical devices.
_ = device.isUnknown

// The identifier for the device.
// i.e.: 'iPhone15,3'
let id = device.id

// The known/commercial name of the device.
// i.e.: 'iPhone 14 Pro Max'
let model = device.model

这是一个用于检测apple设备的新库

import DeviceDetector

let detector = DeviceDetector.shared
let deviceName = detector.currentDeviceName
let deviceSet = detector.currentDevice
        
let information = """
Model: \(deviceName)
iPhone?: \(detector.isiPhone)
iPad?: \(detector.isiPad)
Notch?: \(detector.hasSafeArea)
        
4inch?: \(DeviceSet.iPhone4inchSet.contains(deviceSet))
4.7inch?: \(DeviceSet.iPhone4_7inchSet.contains(deviceSet))
iPhoneSE?: \(DeviceSet.iPhoneSESet.contains(deviceSet))
iPhonePlus?: \(DeviceSet.iPhonePlusSet.contains(deviceSet))
iPadPro?: \(DeviceSet.iPadProSet.contains(deviceSet))
"""

结果

下面是获取硬件字符串的代码,但是您需要比较这些硬件字符串才能知道它是哪个设备。我已经创建了一个类,包含几乎所有的设备字符串(我们保持字符串最新的新设备)。使用方便,请检查

吉hub /恶魔大师

Objective-C: GitHub/DeviceUtil

public func hardwareString() -> String {
  var name: [Int32] = [CTL_HW, HW_MACHINE]
  var size: Int = 2
  sysctl(&name, 2, nil, &size, &name, 0)
  var hw_machine = [CChar](count: Int(size), repeatedValue: 0)
  sysctl(&name, 2, &hw_machine, &size, &name, 0)

  let hardware: String = String.fromCString(hw_machine)!
  return hardware
}
struct utsname systemInfo;
uname(&systemInfo);

NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
                          encoding:NSUTF8StringEncoding];